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a) = (-15)+(-10)
= -25
b) = (-222)-100-80
= (-322)-80
= -402
c) = 229+219-401+12
= 448-401+12
=47+12
= 59
d) = 500-(-120)+18
= 620+18
= 638
\(\left(-8\right)+\left(-7\right)+\left(-10\right)\)
\(=-8-7-10\)
\(=-15-10=-25\)
\(\left(-229\right)+219-401+12\)
\(=\left(219-229\right)-401+12\)
\(=-10-401+12\)
\(=-399\)
\(555-\left(-333\right)-100-80\)
\(=555+333-100-80\)
\(=888-100-80\)
\(=780-80=700\)
\(300-\left(-200\right)-\left(-120\right)+18\)
\(=300+200+120+18\)
\(=500+120+18\)
\(=620+18\)
\(=638\)
A. -25
B. 708
C. -379
D. 638
Mình chỉ ghi kết quả thôi ! Bạn biết cách tính chứ!
\(a.\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=-25\)
\(b.555-\left(-333\right)-100-80=\left(555+333\right)-\left(100+80\right)=888-180=708\)
\(c.-\left(-229\right)+\left(-219\right)-401+12=\left(229-219\right)-\left(401-12\right)=10-389=-379\)
\(d.300-\left(-200\right)-\left(-120\right)+1=\left(300+200\right)+\left(120+1\right)=500+121=621\)
Giải:
\(A=\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=\left(-25\right)\)
\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)+12=299-219-401+12=-309\)
\(C=555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\)
\(D=\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=2456\)
\(E=98.42-\left\{50.\left[\left(18-2^3\right):2+3^2\right]\right\}\)
\(E=4116-\left\{50.\left[\left(18-8\right):2+9\right]\right\}\)
\(E=4116-\left\{50.\left[10:2+9\right]\right\}\)
\(E=4116-\left\{50.\left[5+9\right]\right\}\)
\(E=4116-\left\{50.14\right\}\)
\(E=4116-700\)
\(E=3416\)
\(F=-80-\left[-130-\left(12-4^2\right)\right]+2008^0\)
\(F=-80-\left[-130-\left(12-16\right)\right]+1\)
\(F=-80-\left[-130-\left(-4\right)\right]+1\)
\(F=-80-\left(-126\right)+1\)
\(F=47\)
\(G=1000+\left(-670\right)+297+\left(-330\right)=1000-670+297-330=297\)
\(H=1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\)
\(H=2^{10}:2^4+140:\left(38+32\right)-7^2\)
\(H=2^6+140:70-49\)
\(H=64+2-49\)
\(H=17\)
\(I=\left|-129\right|-119+\left|2-31\right|=129-119+\left|-29\right|=10+29=39\)
\(K=219+573+381-173\)
\(K=\left(219+381\right)+\left(573-173\right)\)
\(K=600+400\)
\(K=1000\)
\(L=36.33-105.11+22.15\)
\(L=36.33-35.3.11+11.2.3.5\)
\(L=36.33-35.33+33.10\)
\(L=33.\left(36-35+10\right)\)
\(L=33.11\)
\(L=363\)
\(N=160-\left(2^3.5^2-6.25\right)\)
\(N=160-\left[25.\left(8-6\right)\right]\)
\(N=160-\left[25.2\right]\)
\(N=160-50\)
\(N=110\)
\(O=\left(44.52.60\right):\left(11.13.15\right)=137280:2145=64\)
\(P=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).\left(2^4-4^2\right)=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).0=0\)
\(Q=100+98+96+...+4+2-97-95-...-3-1\)
\(Q=100+\left(98-97\right)+\left(96-95\right)+...+\left(4-3\right)+\left(2-1\right)\)
\(Q=100+1+1+...+1+1\)
Vì có 98:2=49 số 1
\(\Rightarrow Q=100+49\)
\(Q=149\)
a, \(\left[\left(-8\right)+\left(-7\right)+\left(-10\right)\right]\) = -25
b, 555-(-333)-100-80 = 555 + 333 - 100 - 80
= 888-100-80
= 788 - 80
= 708
c, -(-229) +(-219) - 401 +12 = 229 - 219 - 401 + 12
= 10 + 12 - 401
= 22 - 401
= -379
d, 300 - (-200) - (-120) + 18 = 300 + 200 + 120 +18
= 620 + 18
= 638
câu a :
\(\dfrac{-8}{24}+\dfrac{-4}{12}=\dfrac{-1}{3}+\dfrac{-1}{3}=\dfrac{-2}{3}\)
câu b :
\(\dfrac{-20}{35}+\dfrac{16}{24}=\dfrac{-4}{7}+\dfrac{2}{3}=\dfrac{2}{21}\)
câu c :
\(\dfrac{-3}{9}+\dfrac{-6}{15}=\dfrac{-1}{3}+\dfrac{-2}{5}=\dfrac{-11}{15}\)
câu d :
\(\dfrac{3}{13}-\dfrac{4}{10}=\dfrac{3}{13}-\dfrac{2}{5}=\dfrac{-11}{65}\)
câu e :
\(\dfrac{5}{17}-\dfrac{9}{15}=\dfrac{5}{17}-\dfrac{3}{5}=\dfrac{-26}{85}\)
câu g :
\(\dfrac{9}{18}-\dfrac{6}{15}+\dfrac{3}{-9}=\dfrac{9}{18}-\dfrac{6}{15}+\dfrac{-3}{9}\\ =\dfrac{1}{2}-\dfrac{2}{5}+\dfrac{-1}{3}=\dfrac{-7}{30}\)
câu h :
\(\dfrac{5}{4}-\dfrac{1}{2}+\dfrac{-7}{8}=\dfrac{10}{8}-\dfrac{4}{8}+\dfrac{-7}{8}=\dfrac{-1}{8}\)
a) -35+40-15
=5-15
=-10
b) 8-(3-7)
=8-(-4)
=8+4
=12
c) (-5)-(9-12)
=-5-(-3)
=-2
d)7-(-9)-3
=7+9-3
=16-3
=13
e) (-3)+(8-11)
=-3+(-3)
=-6
g) -110-(-10)-35+85
=-100-35+85
=-135+85
=-50
h) [(-8)+(-7)]+(-10)
=-15+(-10)
=-25
i) -555-(-333)-100-80
=-555+333-100-80
=-222-100-80
=-322-80
=-402
k)-(-229)+(-219)-401+12
=229+(-219)-401+12
=10-401+12
=-391+12
=-379
l) -300-(+200)-(-120)-18
=-500+120-18
=-380-18
=-398