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A = \(\frac{3^4\left(5.79-1\right)}{2^2.3^2\left(5.79-1\right)}=\frac{9}{4}\); B = \(\frac{3.7.13.37\left(5.11-1\right)}{4.3.7.13.37\left(3.5-1\right)}=\frac{54}{4.14}=\frac{2.9}{4.2.7}=\frac{9}{28}\)
\(\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{3.5.7.11.13.37-3.7.13.37}{40404.30+40404.1}\)
\(=\frac{3.7.13.37.\left(5.11-1\right)}{40404.\left(30+1\right)}\)
\(=\frac{3.7.13.37.54}{40404.31}\)
\(=\frac{3.7.13.37.54}{3.7.13.37.31.4}\)
\(=\frac{54}{31.4}=\frac{27}{62}\)
31995 - 81 / 42660 - 108
= 31914 / 42552
= 3.10638 / 4.10638
= 3/4
\(=\frac{3\text{x}5x7x11\text{x}13\text{x}37-3\text{x}7\text{x}13\text{x}37}{2^3x3^2x5\text{x}7\text{x}13\text{x}37+2^2x3\text{x}7\text{x}13\text{x}37}=\frac{3\text{x}7\text{x}13\text{x}37\left(5\text{x}11-1\right)}{2^2x3\text{x}7\text{x}13\text{x}37\left(2\text{x}3\text{x}5+1\right)}\)
\(=\frac{54}{2^2x31}=\frac{54}{124}=\frac{27}{62}\) thử lại kết quả rồi nhé
Câu a) \(\dfrac{31995-81}{42660-108}=\dfrac{31914}{42552}=\dfrac{31914:10638}{42552:10638}\)
=\(\dfrac{3}{4}\)
Câu b) \(\dfrac{\left(3.5.7.11.13.15.37-10101\right)}{121212+40404}\)
=\(\dfrac{\left(3.5.7.11.13.15.37-3.7.13.37\right)}{3.7.13.37.12+3.7.13.37.4}\)
=\(\dfrac{3.7.13.37\left(5.11.15-1\right)}{3.7.13.37\left(12+4\right)}\)
= \(\dfrac{824}{16}\)=\(\dfrac{103}{2}\)
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