Question

[Hạ Thanh]

a) |2x-1|=x+3

b) |4x+7|=2x+5

c) x²-3|x|+2=0

d) \(\sqrt{x^2+6x+9}=\left|2x-1\right|\)

f) \(\left|4x-17\right|=x^2-4x-5\)

Answer 1

[Nguyễn Mai Phương]

|2x-1|=x+3

=> 2x-1=x+3 hoặc 2x-1=-(x+3)

2x-x=1+4 2x-1=-x-3

x=5 2x+x= 1-3

3x=-2

x=\(\frac{-2}{3}\)

Answer 2

[Nguyễn Mai Phương]

|4x+7|=2x+5

=> 4x+7=2x+5

4x-2x=5-7

-2x=-2

x=1

=>4x+7=-(2x+5)

4x+7=-2x-5

4x+2x=-5-7

6x=-12

x=-2