Question

[Nguyễn Bảo Khánh]

a) 2+3𝑥=−15−19

b) 2𝑥−5=−17+12

c) 10−𝑥−5=−5−7−11

d) |𝑥|−3=0

e) (7−|𝑥|).(2𝑥−4)=0

f) −10−(𝑥−5)+(3−𝑥)=−8

g) 10+3(𝑥−1)=10+6𝑥

h) (𝑥+1)(𝑥−2)=0

Bài 3. Tìm các số nguyên x và y sao cho:

a) (𝑥+2)(𝑦−1)=3

b) (3−𝑥)(𝑥𝑦+5)=−1

Answer 1

[✎✰ ๖ۣۜLαɗσηηα ༣✰✍]

a) 2+3𝑥=−15−19

3x= -15 - 19 -2

3x = -36

x= -12

b) 2𝑥−5=−17+12

2x = -17 + 12 + 5

2x = 0

x = 0

c) 10−𝑥−5=−5−7−11

-x = -5 - 7 - 11 - 10 + 5

-x = -28

x = 28

d) |𝑥|−3=0

|x|= 3

x = \(\pm\)3

e) (7−|𝑥|).(2𝑥−4)=0

th1 : ( 7 - | x| ) = 0

|x|= 7

x=\(\pm\)7

th2: ( 2x-4) = 0

2x = 4

x= 2

f) −10−(𝑥−5)+(3−𝑥)=−8

-10 - x + 5 + 3 - x = -8

-10 + 5 + 3 + 8 = 2x

2x= 6

x = 3

g) 10+3(𝑥−1)=10+6𝑥

10 + 3x - 3 = 10 + 6x

3x - 6x = 10 - 10 + 3

-3x = 3

x= -1

h) (𝑥+1)(𝑥−2)=0

th1: x+1= 0

x = -1

x-2=0

x=2

hok tốt!!!