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a) (-2 019) + (-550) + (-451) = [(-2 019) + (-451)] + (-550) = (-2 470) + (-550) = -(2 470 + 550) = -3 020
b) (-2) + 5 + (-6) + 9 = [(-2) + 5 ]+[ (-6) + 9] = 3 + 3 = 6
\(\frac{2019}{210}+\frac{2019}{280}+\frac{2019}{360}+\frac{2019}{450}+\frac{2019}{550}\)
\(=\frac{673}{70}+\frac{2019}{280}+\frac{673}{120}+\frac{673}{150}+\frac{2019}{550}\)
\(=\left[\frac{673}{70}+\frac{2019}{280}\right]+\frac{673}{120}+\frac{673}{150}+\frac{2019}{550}\)
\(=\left[\frac{2692}{280}+\frac{2019}{280}\right]+\frac{673}{120}+\frac{673}{150}+\frac{2019}{550}\)
\(=\frac{673}{40}+\frac{673}{120}+\frac{673}{150}+\frac{2019}{550}\)
\(=\left[\frac{673}{40}+\frac{673}{120}\right]+\frac{673}{150}+\frac{2019}{550}\)
\(=\left[\frac{2019}{120}+\frac{673}{120}\right]+\frac{673}{150}+\frac{2019}{550}\)
\(=\frac{673}{30}+\frac{673}{150}+\frac{2019}{550}\)
\(=\left[\frac{673}{30}+\frac{673}{150}\right]+\frac{2019}{550}\)
\(=\frac{673}{25}+\frac{2019}{550}=\frac{14806}{550}+\frac{2019}{550}=\frac{16825}{550}=\frac{673}{22}\)
P/S : Các a chị check dùm em ạ
A = 5 + 5² + 5³ + ... + 5⁴⁹ + 5⁵⁰
⇒ 5A = 5² + 5³ + 5⁴ + ... + 5⁵⁰ + 5⁵¹
⇒ 4A = 5A - A
= (5² + 5³ + 5⁴ + ... + 5⁵⁰ + 5⁵¹) - (5 + 5² + 5³ + ... + 5⁴⁹ + 5⁵⁰)
= 5⁵¹ - 5
⇒ A = (5⁵¹ - 5) : 4
a) -2021.371+2021-(-629)
=2021.(-371)+2021+629
=2021.[-371+1]+629
=2021.(-370)+629
=-747770+629
=-747141
b) 957.(-37)-137.(-957)
=957.(-37)+137.957
=957.[-37+137]
=957.100
=95700
d) (451-527)+(527-741-451)
=451-527+527-741-451
=(451-451)+(-527+527)-741
=0+0-741
=-741
e) (-632+129)-(-17-632+129)
=-632+129+17+632-129
=(-632+632)+(129-12)+17
=0+0+17
=17
\(\left(x-1\right)^4=81\)
\(\Rightarrow\left(x-1\right)^4=\left(\pm3\right)^4\)
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}\)
vậy___
a - (- 351) - (621 + 451 - 821)
= a + 351 - 621 - 451 + 821
= a - (451 - 351) + (821 - 621)
= a - 100 + 100
= a - 0
= a
1,\(\left(x-1\right)^4=81\)
\(\Rightarrow\left(x-1\right)^4=\orbr{\begin{cases}3^4\\\left(-3\right)^4\end{cases}}\)
\(\Rightarrow x-1=\orbr{\begin{cases}3\\-3\end{cases}}\)
\(\Rightarrow x=\orbr{\begin{cases}4\\-2\end{cases}}\)
2,\(a-\left(-351\right)-\left(621+451-821\right)\)
\(=a+351-251\)
\(=a+100\)
\(x+2x+3x+...+10x=550\)
\(\Leftrightarrow (1+2+3+...+10)x=550\)
\(\Leftrightarrow 55x=550\)
\(\Leftrightarrow x=10\)
Đáp án \(A\)
Ta có: \(A=\left(2020^{2019}+2019^{2019}\right)^{2020}\)
\(=\left(2019^{2019}+2020^{2019}\right)^{2019}\cdot\left(2019^{2019}+2020^{2019}\right)\)
\(\Leftrightarrow\dfrac{A}{B}=\dfrac{\left(2019^{2019}+2020^{2019}\right)^{2019}\cdot\left(2019^{2019}+2020^{2019}\right)}{\left(2020^{2020}+2019^{2020}\right)^{2019}}\)
\(\Leftrightarrow\dfrac{A}{B}=\dfrac{2019^{2019}+2020^{2019}}{2019+2020}>1\)
\(\Leftrightarrow A>B\)
Lời giải:
Ta có:
\(A+1=\frac{2019^{2019}+2019^{2020}}{2019^{2019}-1}=\frac{2019^{2019}.2020}{2019^{2019}-1}\)
\(B+1=\frac{2019^{2019}+2019^{2018}}{2019^{2018}-1}=\frac{2019^{2018}.2020}{2019^{2018}-1}\) \(=\frac{2019^{2019}.2020}{2019^{2019}-2019}>\frac{2019^{2019}.2020}{2019^{2019}-1}\)
$\Rightarrow B+1>A+1$
$\Rightarrow B>A$