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\(A=\dfrac{14^{14}+1}{14^{15}+1}\)
\(\Rightarrow14.A=\dfrac{14^{15}+14}{14^{15}+1}\)
\(\Rightarrow14.A=\dfrac{14^{15}+1}{14^{15}+1}+\dfrac{13}{14^{15}+1}\)
\(\Rightarrow14.A=1+\dfrac{13}{14^{15}+1}\)
\(B=\dfrac{14^{15}+1}{14^{16}+1}\)
\(\Rightarrow14.B=\dfrac{14^{16}+14}{14^{16}+1}\)
\(\Rightarrow14.B=\dfrac{14^{16}+1}{14^{16}+1}+\dfrac{13}{14^{16}+1}\)
\(\Rightarrow14.B=1+\dfrac{13}{14^{16}+1}\)
Nhận xét: \(\dfrac{13}{14^{15}+1}>\dfrac{13}{14^{16}+1}\) (cùng tử, xét mẫu)
\(\Rightarrow A>B\)
Vậy \(A>B\)
\(x:\dfrac{13}{16}=\dfrac{5}{-8}\\ x=\dfrac{5}{-8}.\dfrac{13}{16}=\dfrac{65}{-128}\)
\(x.\dfrac{-1}{2}=\dfrac{-4}{5}\\ x=\dfrac{-4}{5}:\dfrac{-1}{2}=\dfrac{8}{5}\)
\(=\dfrac{11}{6}-\dfrac{14}{3}+\sqrt{2}=\dfrac{11-28+6\sqrt{2}}{6}=\dfrac{-17+6\sqrt{2}}{6}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a-100}{16}=\dfrac{b}{15}=\dfrac{c+100}{14}=\dfrac{a-100+b+c+100}{16+15+14}\)=\(\dfrac{2250}{45}=50\)
bạn tự làm nốt nhé
A=\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}\)= \(\frac{\left(2.7\right)^{16}.\left(3.7\right)^{32}.\left(5.7\right)^{48}}{\left(2.5\right)^{16}.\left(3.5\right)^{32}.7^{96}}\)= \(\frac{2^{16}.7^{16}.3^{32}.7^{32}.5^{48}.7^{48}}{2^{16}.5^{16}.3^{32}.5^{32}.7^{96}}\)= \(\frac{2^{16}.7^{96}.3^{32}.5^{48}}{2^{16}.5^{48}.3^{32}.7^{96}}\)=1
\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}=\frac{2^{16}.7^{16}.3^{32}.7^{32}.5^{48}.7^{48}}{2^{16}.5^{16}.3^{32}.5^{32}.7^{96}}\)
\(=\frac{2^{16}.\left(7^{16}.7^{32}.7^{48}\right).5^{48}.3^{32}}{2^{16}\left(5^{16}.5^{32}\right).3^{32}.7^{96}}=\frac{2^{16}.7^{96}.5^{48}.3^{32}}{2^{16}.5^{48}.3^{32}.7^{96}}\)=1
A = 2 + (-4) + (-6) + 8 + 10 + (-12) + (-14) + 16 + ... + 2010
A = ( 2 - 4 ) + ( -6 + 8 ) + ( 10 - 12 ) + (-14 + 16 ) + ... + ( -2007 + 2008 ) + 2010
A = -2 + 2 - 2 + 2 + ... + 2 + 2010
A = 0 + 0 + 0 + ... + 2010
A = 2010