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Câu 1:
a: \(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{2}{5}=\dfrac{20-15+24}{60}=\dfrac{29}{60}\)
b: \(\dfrac{1}{3}-\dfrac{4}{5}+\dfrac{4}{3}=\dfrac{5}{3}-\dfrac{4}{5}=\dfrac{25-12}{15}=\dfrac{13}{15}\)
c: \(=\dfrac{1}{2}+\dfrac{1}{6}-\dfrac{1}{4}+\dfrac{1}{5}\)
\(=\dfrac{30}{60}+\dfrac{10}{60}-\dfrac{15}{60}+\dfrac{12}{60}\)
=37/60
Ta có : \(\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)\)
= \(\left(\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}\right):\left(\dfrac{55}{132}+\dfrac{132}{132}-\dfrac{84}{132}\right)\)
=\(\dfrac{115}{132}:\dfrac{103}{132}\)
=\(\dfrac{115}{132}.\dfrac{132}{103}\)
=\(\dfrac{115}{103}\)
Tìm x
a, \(\dfrac{1}{4}+\dfrac{1}{3}:3x=5\)
\(\Rightarrow\) \(\dfrac{1}{4}+\dfrac{1}{9}x=5\)
\(\Rightarrow\) \(\dfrac{1}{9}x\) \(=5-\dfrac{1}{4}\)
\(\Rightarrow\) \(\dfrac{1}{9}x=\dfrac{20}{4}-\dfrac{1}{4}\)
\(\Rightarrow\) \(\dfrac{1}{9}x=\dfrac{19}{4}\)
\(\Rightarrow\) \(x=\dfrac{19}{4}:\dfrac{1}{9}\)
\(\Rightarrow\) \(x=\dfrac{19}{4}.9\)
\(\Rightarrow\) \(x=\dfrac{171}{4}\)
Vậy \(x=\dfrac{171}{4}\)