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Bài 1:
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + (\(\frac45\) - \(\frac{3}{17}\) + \(\frac13\)) - \(\frac17\) + (- \(\frac{14}{30}\))
A = \(\frac15\) + \(\frac{3}{17}\) - \(\frac43\) + \(\frac45\) - \(\frac{3}{17}\) + \(\frac13\) - \(\frac17\) - \(\frac{14}{30}\)
A = (\(\frac15\) + \(\frac45\)) + (\(\frac{3}{17}\) - \(\frac{3}{17}\)) - (\(\frac43-\frac13\)) - \(\frac{30}{210}\) - \(\frac{98}{210}\)
A = 1 + 0 - 1 - (\(\frac{30}{210}+\frac{98}{210}\))
A = 1 - 1 - \(\frac{228}{210}\)
A = 0 - \(\frac{128}{210}\)
A = - \(\frac{64}{105}\)
Bài 2:
B= (\(\frac58\) - \(\frac{4}{12}\) + \(\frac32\)) - (\(\frac58\) + \(\frac{9}{13}\)) - (\(\frac{-3}{2}\)) + \(\frac{7}{-15}\)
B = \(\frac58\) - \(\frac{4}{12}\) + \(\frac32\) - \(\frac58\) - \(\frac{9}{13}\) + \(\frac32\) - \(\frac{7}{15}\)
B = (\(\frac58\) - \(\frac58\)) + (\(\frac32\) + \(\frac32\)) - (\(\frac13\) + \(\frac{9}{13}\) + \(\frac{7}{15}\))
B = 0 + 3 - (\(\frac{65}{195}\) + \(\frac{135}{195}\) + \(\frac{91}{195}\))
B = 3 - (\(\frac{200}{195}\) + \(\frac{91}{195}\))
B = 3 - \(\frac{97}{65}\)
B = \(\frac{195}{65}\) - \(\frac{97}{65}\)
B = \(\frac{98}{65}\)
1)
a) \(-\frac{9}{34}:\frac{17}{4}\)
\(=-\frac{18}{289}.\)
b) \(1\frac{1}{2}.\frac{1}{24}\)
\(=\frac{3}{2}.\frac{1}{24}\)
\(=\frac{1}{16}.\)
c) \(-\frac{5}{2}:\frac{3}{4}\)
\(=-\frac{10}{3}.\)
d) \(4\frac{1}{5}:\left(-2\frac{4}{5}\right)\)
\(=\frac{21}{5}:\left(-\frac{14}{5}\right)\)
\(=-\frac{3}{2}.\)
Mấy câu sau bạn đăng ríu rít quá khó nhìn lắm.
Chúc bạn học tốt!
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
\(A,\left(\dfrac{11}{12}-1\dfrac{5}{3}+\dfrac{1}{12}-\dfrac{1}{3}\right):\dfrac{2}{3}\)
\(\Rightarrow=\left(\dfrac{11}{12}-1+\dfrac{5}{3}+\dfrac{1}{12}-\dfrac{1}{3}\right):\dfrac{2}{3}\)
\(\Rightarrow=\left[\left(\dfrac{11}{12}+\dfrac{1}{12}\right)-\left(1+\dfrac{5}{3}+\dfrac{1}{3}\right)\right]:\dfrac{2}{3}\)
\(\Rightarrow=\left[1-3\right]:\dfrac{2}{3}\)
\(\Rightarrow=-2\cdot\dfrac{3}{2}\)
\(\Rightarrow=-3\)
\(B,-\dfrac{5}{19}+\dfrac{14}{18}-\dfrac{4}{9}+\dfrac{2}{9}+\dfrac{1}{2007}\)
\(=-\dfrac{5}{19}+\left(\dfrac{14}{18}-\dfrac{4}{9}+\dfrac{2}{9}\right)+\dfrac{1}{2007}\)
\(=-\dfrac{5}{19}+\dfrac{5}{9}+\dfrac{1}{2007}\)
\(=\dfrac{1241}{2007}\)
Ai thấy em làm sai thì bảo em ạ!
A, (\(\dfrac{11}{12}\) - 1\(\dfrac{5}{3}\) + \(\dfrac{1}{12}\) - \(\dfrac{1}{3}\)) : \(\dfrac{2}{3}\)
=[(\(\dfrac{11}{12}\) + \(\dfrac{1}{12}\)) - (\(\dfrac{8}{3}\) + \(\dfrac{1}{3}\))] : \(\dfrac{2}{3}\)
= [1 - 3]: \(\dfrac{2}{3}\)
= - 2 x \(\dfrac{3}{2}\)
= - 3