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a: \(=\dfrac{5^5\cdot5^{10}\cdot4^5}{5^{10}\cdot2^{10}}=5^5\)
b: \(=\left(\dfrac{0.9}{0.3}\right)^5\cdot\dfrac{1}{0.3}=\dfrac{3^5}{0.3}=810\)
c: \(=\dfrac{2^{12}\cdot3^6+2^3\cdot3^3\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\dfrac{2^{12}\cdot3^6+2^6\cdot3^4\cdot5}{2^{11}\cdot3^{11}\cdot5}\)
\(=\dfrac{2^6\cdot3^4\left(2^6\cdot3^2+5\right)}{2^{11}\cdot3^{11}\cdot5}=\dfrac{1}{2^5}\cdot\dfrac{1}{3^7}\cdot\dfrac{581}{5}=\dfrac{581}{2^5\cdot3^7\cdot5}\)
Mình nghĩ đề đúng là :
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.3.5.2^3}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}\)
\(=\frac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}\)
\(=\frac{2^{13}.3^{11}}{2^{11}.3^{11}.5}\)
\(=\frac{2^2}{5}\)
\(=\frac{4}{5}\)
\(A=\frac{4^6x9^5+6^9x120}{8^4x3^{12}-6^{11}}\)
\(A=\frac{2^{12}x3^{10}+2^9x3^9x2^3x3x5}{2^{12}x3^{12}-2^{11}x3^{11}}\)
\(A=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{10}-2^{11}.3^{11}}\)
\(A=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{10}.\left(2-3\right)}=\frac{2.6}{-1}=-12\)
a. \(\frac{20^5.5^{10}}{100^5}\)= \(\frac{20^5.5^{10}}{20^5.5^5}\)= \(5^5\)=\(3125\)
b. \(\frac{0,9^5}{0,3^6}\)= \(\frac{0,9^5}{0,3^5.0,3}\)= \(\left(\frac{0,9}{0,3}\right).\frac{1}{0,3}\)= \(243.\frac{1}{0,3}\)= \(810\)
c.\(\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(3.2\right)^3+3.\left(3.2\right)^{^2}+3^3}{-13}=\frac{3^3.2^3+3.3^2.2^2+3^3}{-13}\)\(=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=3^3.\left(-1\right)=-27\)
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