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VM
15 tháng 12 2019
\(=\left(\frac{135}{11}-\frac{58}{11}\right)+\left(\frac{13}{4}+\frac{5}{4}\right)-\frac{6}{13}\)
\(=7+\frac{9}{2}-\frac{6}{13}\)
\(=\frac{23}{2}-\frac{6}{13}\)
\(=\frac{287}{26}.\)
Chúc bạn học tốt!
VC
Vũ Cao Minh
CTV
VIP
15 tháng 12 2019
\(12\frac{3}{11}-\frac{6}{13}+3,25-5\frac{3}{11}-4\frac{7}{13}+\sqrt{1\frac{9}{16}}\)
\(=12+\frac{3}{11}-\frac{6}{13}+3,25-5-\frac{3}{11}-4-\frac{7}{13}+\sqrt{\frac{25}{16}}\)
\(=\left(12-5-4\right)+\left(\frac{3}{11}-\frac{3}{11}\right)+\left(\frac{-6}{13}-\frac{7}{13}\right)+\frac{5}{4}+3,25\)
\(=3+0+\left(-1\right)+1,25+3,25=2+4,5=6,5\)
C
16 tháng 10 2023
`1/3-5/6+3/2`
`=2/6-5/6+9/6`
`=-3/6+9/6`
`=6/6`
`=1`
__
`2/13-(15/13+4-0,5)`
`=2/13-1513-4+0,5`
`=(2/13-15/13)-4,5`
`=-13/13-4,5`
`=-1-4,5`
`=-5,5`
__
`-(1/9+7/5-3/11)+(-2/5+17/9-8/11)`
`=-1/9-7/5+3/11+(-2)/5+17/9-8/11`
`=(-1/9+17/9)+(-7/5+(-2)/5)+(3/11-8/11)`
`=16/9-9/5-5/11`
`=-236/495`
__
`5,75-3,25+5 5/6`
`=5/2+35/6`
`=15/6+35/6`
`=50/6`
`=25/3`
K
8 tháng 11 2018
ko dùng mt thì lâu ls đó, phải giải từ từ ra.
Theo đề của bạn ta được: biến thành phép chia phân số:
\(\left(\dfrac{4}{13}-0,8+\dfrac{4}{7}+1\right):\left(\dfrac{13}{7}-2,6+1+3,25\right)\)
\(=\left(\dfrac{4}{13}-0,8+\dfrac{4}{7}+1\right).\left(\dfrac{7}{13}-\dfrac{10}{26}+1+\dfrac{100}{325}\right)\)
Quy đồng rồi nhân ta được:
\(\dfrac{4}{13}\)
LT
2
TT
7 tháng 2 2022
\(\left(3,25-\frac{2}{5}x\right)\div\frac{-7}{4}=-3\)
\(\Rightarrow\)\(\left(3,25-\frac{2}{5}x\right)\div\frac{-7}{4}=-3\)
\(\Rightarrow\)\(\frac{13}{4}-\frac{2}{5}x=\frac{21}{4}\)
\(\Rightarrow\)\(\frac{2}{5}x=-2\)
\(\Rightarrow\)\(x=-5\)
QT
1
HQ
Hà Quang Minh
Giáo viên
16 tháng 9 2023
a)\(\frac{5}{7} - \left( { - 3,9} \right) = \frac{5}{7} + 3,9 = \frac{5}{7} + \frac{{39}}{{10}} = \frac{{50}}{{70}} + \frac{{273}}{{70}} = \frac{{323}}{{70}}\);
b)\(\left( { - 3,25} \right) + 4\frac{3}{4} = - \frac{{13}}{4} + \frac{{19}}{4} = \frac{6}{4} = \frac{3}{2}.\)
1 tháng 12 2019
\(12\frac{3}{11}-\frac{6}{13}+3,25-5\frac{3}{11}+\sqrt{1\frac{9}{16}}\)
\(=\frac{135}{11}-\frac{6}{13}+\frac{13}{4}-\frac{58}{11}+\sqrt{\frac{25}{16}}\)
\(=\frac{135}{11}-\frac{6}{13}+\frac{13}{4}-\frac{58}{11}+\frac{5}{4}\)
\(=\frac{135}{11}-\frac{58}{11}+\frac{13}{4}+\frac{5}{4}-\frac{6}{13}\)
\(=\frac{77}{11}+\frac{18}{4}-\frac{6}{13}\)
\(=7+\frac{9}{2}-\frac{6}{13}\)
\(=\frac{182}{26}+\frac{117}{26}-\frac{12}{26}\)
\(=\frac{287}{26}\)
T
28 tháng 10 2023
\(\left(3\dfrac{1}{2}+0,25\right)-\left(\dfrac{1}{4}-3,25+\dfrac{1}{2}\right)\)
\(=\left(\dfrac{7}{2}+\dfrac{1}{4}\right)-\left(\dfrac{1}{4}-\dfrac{13}{4}+\dfrac{1}{2}\right)\)
\(=\dfrac{7}{2}+\dfrac{1}{4}-\dfrac{1}{4}+\dfrac{13}{4}-\dfrac{1}{2}\)
\(=\left(\dfrac{7}{2}-\dfrac{1}{2}\right)+\dfrac{13}{4}\)
\(=3+\dfrac{13}{4}\)
\(=\dfrac{12}{4}+\dfrac{13}{4}\)
\(=\dfrac{25}{4}\)
28 tháng 10 2023
\(\left(3\dfrac{1}{2}+0,25\right)-\left(\dfrac{1}{4}-3,25+\dfrac{1}{2}\right)\)
\(=3,5+0,25-0,25+3,25-0,5\)
\(=6,75-0,5=6,25\)=25/4
NK
6 tháng 7 2023
\(1,0,75-\dfrac{2}{3}-0,5=\dfrac{3}{4}-\dfrac{2}{3}-\dfrac{1}{2}=\dfrac{9}{12}-\dfrac{8}{12}-\dfrac{1}{2}=\dfrac{1}{12}-\dfrac{1}{2}\)
\(=\dfrac{2}{24}-\dfrac{12}{24}=\dfrac{-10}{24}=\dfrac{-5}{12}\)
\(2,\dfrac{1}{5}-0,125-\dfrac{5}{4}=\dfrac{1}{5}-\dfrac{1}{8}-\dfrac{5}{4}=\dfrac{8}{40}-\dfrac{5}{40}-\dfrac{5}{4}=\dfrac{3}{40}-\dfrac{5}{4}\)
\(=\dfrac{3}{40}-\dfrac{50}{40}=\dfrac{-47}{40}\)
\(3,1,25-\dfrac{3}{4}+\dfrac{4}{3}=\dfrac{5}{4}-\dfrac{3}{4}+\dfrac{4}{3}=\dfrac{2}{4}+\dfrac{4}{3}=\dfrac{6}{12}+\dfrac{16}{12}=\dfrac{22}{12}=\dfrac{11}{6}\)
\(4,0,15-\dfrac{1}{4}+\dfrac{2}{5}=\dfrac{3}{20}-\dfrac{1}{4}+\dfrac{2}{5}=\dfrac{3}{20}-\dfrac{5}{20}+\dfrac{2}{5}=\dfrac{-2}{20}+\dfrac{2}{5}\)
\(=\dfrac{-2}{20}+\dfrac{8}{20}=\dfrac{6}{20}=\dfrac{3}{10}\)
\(5,5-3,4+\dfrac{1}{5}=\dfrac{5}{1}-\dfrac{17}{5}+\dfrac{1}{5}=\dfrac{25}{5}-\dfrac{17}{5}+\dfrac{1}{5}=\dfrac{25-17+1}{5}=\dfrac{9}{5}\)
\(6,\dfrac{1}{4}-0,3+\dfrac{4}{3}=\dfrac{1}{4}-\dfrac{3}{10}+\dfrac{4}{3}=\dfrac{10}{40}-\dfrac{12}{40}+\dfrac{4}{3}=\dfrac{-2}{40}+\dfrac{4}{3}\)
\(=\dfrac{-1}{20}+\dfrac{4}{3}=\dfrac{-3}{60}+\dfrac{80}{60}=\dfrac{77}{60}\)
\(7,0,2-3,25+4,7=\dfrac{1}{5}-\dfrac{13}{4}+\dfrac{47}{10}=\dfrac{4}{20}-\dfrac{65}{20}+\dfrac{47}{10}=\dfrac{-61}{20}+\dfrac{47}{10}\)
\(=\dfrac{-61}{20}+\dfrac{94}{20}=\dfrac{33}{20}=1,65\)
\(8,5,4+\dfrac{-7}{3}-\dfrac{-5}{7}=\dfrac{27}{5}+\dfrac{-7}{3}-\dfrac{-5}{7}=\dfrac{81}{15}+\dfrac{-35}{15}-\dfrac{-5}{7}\)
\(=\dfrac{46}{15}-\dfrac{-5}{7}=\dfrac{322}{105}-\dfrac{-75}{105}=\dfrac{397}{105}\)
\(9,\dfrac{-4}{2}+\dfrac{1}{3}-\dfrac{1}{4}=\dfrac{-12}{6}+\dfrac{2}{6}-\dfrac{1}{4}=\dfrac{-10}{6}-\dfrac{1}{4}=\dfrac{-5}{3}-\dfrac{1}{4}\)
\(=\dfrac{-20}{12}-\dfrac{3}{12}=\text{ }\dfrac{-23}{12}\)
\(10,5,4-1,5-\left(7,2-1\right)=3,9-6,2=-2,3\)
\(11,4,9-\left(1,5-7,7+3\right)=4,9-\left(-3,2\right)=8,1\)
\(12,7,8-4,7+\left(5,3-1,4\right)=3,1+3,9=7\)
\(14,\dfrac{1}{2}-0,4+\dfrac{1}{5}\text{=}0,5-0,4+0,2=0,3\)
\(15,4,2-\dfrac{4}{5}+\dfrac{1}{2}=4,2-0,8+0,5=3,9\)
16 tháng 7 2017
5.[3/4-2/3x]-13/4=-2{(5/4)2-5/2.1/4+(1/16)2
5.[3/4-2/3x]-13/4=2{25/16-5/8+1/256}
........................=2{400/256-160/250+1/256}
........................=2.241/256
........................=241/128
5.[3/4-2/3x]=241/128+13/4
5.[3/4-2/3x]=241/128+416/128
[3/4-2/3x]=657/128:5
[3/4-2/3x]=657/640
vậy 3/4-2/3x=657/640 và 3/4-2/3x=-657/640
th1:3/4-2/3x va th2:3/4-2/3x=-657/640
còn lại bạn chỉ cần tính kết quả mà dấu[..] là giá tri tuyệt đối đó
\(\frac{9}{4}.3,25+\frac{7}{4}3,25\)
\(=\left(\frac{9}{4}+\frac{7}{4}\right).3,25\)
\(=4.3,25\)
\(=13\)
\(\text{HT}\)