Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,91-5.\left(5+x\right)=61\\ \Rightarrow=5.\left(5+x\right)=30\\ \Rightarrow5+x=6\\ \Rightarrow x=1.\\ b,\left[195-\left(3x-27\right)\right].39=4212\\ \Rightarrow195-\left(3x-27\right)=108\\ \Rightarrow3x-27=87\\ \Rightarrow3x=114\\ \Rightarrow x=38.\)
\(91-5.\left(5+x\right)=61\)
\(\Rightarrow5.\left(5+x\right)=91-61\)
\(\Rightarrow5.\left(5+x\right)=30\)
\(\Rightarrow5+x=\dfrac{30}{5}=6\)
\(\Rightarrow x=6-5=1\)
\(\left[195-\left(3x-27\right)\right].39=4212\)
\(\Rightarrow195-3x+27=\dfrac{4212}{39}=108\)
\(\Rightarrow222-3x=108\)
\(\Rightarrow3x=222-108=114\)
\(\Rightarrow x=\dfrac{114}{3}=38\)
a, 91 - 5 . ( 5 + x ) = 61
5 . (5+x)=91-61
5 . (5+x)=30
5+x=30:5
5+x=6
x=6-5
x=1
Bài 1. Tìm số tự nhiên x biết:
a, 91 - 5 . ( 5 + x ) = 61
5(5 + x) = 91 - 61
5(5 + x) = 30
5 + x = 30 : 5
5 + x = 6
x = 6-5
x= 1
b, ( x+ 34 ) - 50 = 56 : 2
( x + 34 ) - 50 = 28
x + 34 = 28 + 50
x + 34 = 68
x= 78 - 34
x = 44
Tk mk nha
a,91-5(5+x)=61
=>25+5x=91-61=30
=>5x=30-25=5
=>x=1
b,\([\left(x+34\right)-50]\)x2=56
=>(x+34)-50=56:2=28
=>x+34=28+50=78
=>x=78-34=44.
c,1045-\([2015-\left(3x-24\right)]\)=5
=>2015-(3x-24)=1045-5=1040
=>3x-24=2015-1040=975
=>3x=975+24=999
=>x=999:3=333
d,\([195-\left(3x-27\right)]\)x39=4212
=>195-(3x-27)=4212:39=108
=>3x-27=195-108=87
=>3x=87+27=117
=>x=39
e,30-3(x-2)=18
=>30-3x+6=18
=>30-3x=18-6=12
=>3x=30-12=18
=>x=18:3=6
a) \(...\Rightarrow5\left(5+x\right)=91-61=30\)
\(\Rightarrow\left(5+x\right)=30:5=6\Rightarrow x=6-5=1\)
b) \(...\Rightarrow\left(x+34\right)-50=56:2=28\)
\(\Rightarrow\left(x+34\right)=28+50=78\Rightarrow x=78-34=44\)
c) \(...\Rightarrow2015-\left(3x-24\right)=1045-5=1040\)
\(\Rightarrow\left(3x-24\right)=2015-1040=975\)
\(\Rightarrow3x=975+24=999\Rightarrow x=999:3=333\)
d) \(...\Rightarrow195-\left(3x-27\right)=4212:39=108\)
\(\Rightarrow\left(3x-27\right)=195-108=87\)
\(\Rightarrow3x=87+27=114\Rightarrow x=114:3=38\)
e) \(...\Rightarrow3\left(x-2\right)=30-18=12\Rightarrow x-2=12:3=4\)
\(\Rightarrow x=4+2=6\)
a) 91 - 5(5+x) = 61
5(5+x) = 30
5+x=6
x=1
b) [(x+34) - 50]2 = 56
(x+34) - 50 = 28
x+34 = 78
x= 44
Tập hợp con của A có 2 phần tử:
{1;2} {1;3} {1;4}
(2;3} {2;4}
{3;4}
a) 91 - 5 . ( 5 + x ) = 61
5 . ( 5 + x ) = 61
5 . ( 5 + x ) = 30
5 + x = 30 : 5
5 + x = 6
x = 6 - 5
x = 1.
b) [ ( x + 34 ) - 50 ] . 2 = 56
[ ( x + 34 ) - 50 ] = 56 : 2
[ ( x + 34 ) - 50 ] = 28
x + 34 = 28 + 50
x + 34 = 78
x = 78 - 34
x = 44.
2.Cho tập hợp A = { 1 ; 2 ; 3 ; 4 }
B = { 1 ; 2 }
C = { 1 ; 3 )
D = { 1 ; 4 }
E = { 2 ; 3 }
F = { 2 ; 4 }
1/97 chứ sao lại 1/91!
giải:
đặt :1/5+1/14+1/28+1/44+1/61+1/85+1/97 =A
ta có :A=1/5(1/14+1/28+1/44)+(1/61+1/85+1/97)
A<1/5(1/14.3)+(1/61.3)
A<1/5+3/14+3/61
A<1/5+3/12+1/20
A<1/5+1/4+1/20
=>A<1/2
VẬY dpcm
\(91-5\left(5+x\right)=61\)
\(\Rightarrow5\left(5+x\right)=91-61\)
\(\Rightarrow5\left(5+x\right)=30\)
\(\Rightarrow5+x=\dfrac{30}{5}\)
\(\Rightarrow5+x=6\)
\(\Rightarrow x=6-5\)
\(\Rightarrow x=1\)