
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) \(88-3\cdot\left(7+x\right)=64\)
\(3\cdot\left(7+x\right)=88-64=24\)
\(7+x=\frac{24}{3}=8\)
\(x=8-7=1\)
b) \(\left[\left(x+32\right)-17\right]\cdot2=42\)
\(\left(x+32\right)-17=\frac{42}{2}=21\)
\(x+32=21+17=38\)
\(x=38-32=6\)
c) \(\left[\left(x^2+54\right)-32\right]:2=61\)
\(\left(x^2+54\right)-32=61\cdot2=122\)
\(x^2+54=122+32=154\)
\(x^2=154-54=100\)
\(\Rightarrow x=\sqrt{100}=10\)
a) \(88-3.\left(7+x\right)=64\)
\(3.\left(7+x\right)=88-64\)
\(21+3x=24\)
\(3x=3\)
\(x=1\)
b) \(\left[\left(x+32\right)-17\right].2=42\)
\(\left(x+32\right)-17=42:2\)
\(\left(x+32\right)-17=21\)
\(x+32=21+17\)
\(x+32=38\)
\(x=38-32=6\)
c) \(\left[\left(x^2+54\right)-32\right]:2=61\)
\(\left(x^2+54\right)-32=61.2\)
\(\left(x^2+54\right)-32=122\)
\(x^2+54=122+32\)
\(x^2+54=154\)
\(x^2=154-54\)
\(x^2=100\)
\(x^2=10^2\)
\(x=10\)

( 7.x - 15 ) : 3 = 2
7.x - 15 = 6
7.x = 6 + 15
7.x = 21
x = 3
không biết vì chưa học
88 - 3 ( 7 + x ) = 64
3 ( 7 + x ) = 88 - 64
3 ( 7 + x ) = 24
7 + x = 8
x = 1
(7.x -15):3=2
7.x-15=2.3
7.x-15=6
7.x=6+15
7.x=21
x=21:7
x=3
12.(x+37)=504
x+37=504:12
x+37=42
x=42-37
x=5
88-3(7+x)=64
3(7+x)=88-64
3(7+x)=24
7+x=24:3
7+x=8
x=8-7
x=1
dấu . là nhân nhé

\(88-\left(7+y\right)\cdot3=64\)
\(\Rightarrow\left(7+y\right)\cdot3=88-64\)
\(\Rightarrow\left(7+y\right)\cdot3=24\)
\(\Rightarrow7+y=24:3\)
\(\Rightarrow7+y=8\)
\(\Rightarrow y=8-7\)
\(\Rightarrow y=1\)

a)88-3(7+x)=64
=>3(7+x)=88-64
=>3(7+x)=24
=>7+x=24:3
=>7+x=8
=>x=8-7=1
tick nha

88-3.(7+x)=64
3(7+x) = 88-64
3(7+x) = 24
7+x = 24:3
7+x = 8
x= 8-7
x=1
88-3(7+x)=64
3(7+x)=88-64
3(7+x)=24
7+x=24:3
7+x=8
x=8-7
x=1
Vậy x=1

a)131.x-941=32
131x=32+941=973
x=973:131
=973/131
b.88-(7+x).3=64
(7+x).3=88-64=24
7+x=24:3=8
x=8-7
x=1
c)51+(26-3x):5=55
(26-3x):5=55-51=4
26-3x=4.5=20
2x=26-20=6
x=6:3=2
a) 131 . x - 941 = 32
131 . x = 32 + 941
131 . x = 973
x = 973 : 131
x = 973/131
\(88-3.(7+x)=64\)
\(3.(7+x)=88-64\)
\(3.(7+x)=24\)
\(7+x=24:3\)
\(7+x=8\)
\(x=8-7\)
\(x=1\)
vậy \(x=1\)
x=1