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\(\frac{5-\frac{5}{3}+\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}+\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)
\(=\frac{5\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)
\(=\frac{5}{8}:\frac{15}{16}\)
\(=\frac{2}{3}\)
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\(\frac{5\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}\div\frac{15\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}=\frac{5}{8}\div\frac{15}{16}=\frac{2}{3}\)
F=5-5x(1/3+1/9-1/27) /8-8x(1/3+1/9-1/27)
: 15-15x(1/11+1/121) /16-16x(1/11+1/121)
=5-5x1/8-8x1
: 15-15x1/16-16x1
=0:0=0
chắc vậy!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)
\(=\frac{5\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)
\(=\frac{5}{8}:\frac{15}{16}=\frac{5}{8}.\frac{16}{15}=\frac{2}{3}\)
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a) \(2.4.16.8=2.2^2.2^4.2^3=2^{1+2+4+3}=2^{10}\)
b) \(3^3.22^5.45=3^3.22^5.5.3^2=3^{3+2}.22^5=3^5.22^5=\left(3.22\right)^5=66^5\)
c) \(9.27.81=3^2.3^3.3^4=3^{2+3+4}=3^9\)
d) \(36.30.125=6^2.5.6.5^3=6^{2+1}.5^{3+1}=6^3.5^4\)
e) \(2.4.8.16.256=2.2^2.2^3.2^4.2^8=2^{1+2+3+4+8}=2^{18}\)
g) \(3.9.27.81.729=3.3^2.3^3.3^4.3^6=3^{1+2+3+4+6}=3^{16}\)
h) \(5.25.125.625.75=5.5^2.5^3.5^4.5^2.3=5^{1+2+3+4+2}.3=5^{12}.3\)
k) \(7.49.343.77=7.7^2.7^3.7.11=7^{1+2+3+1}.11=7^7.11\)
\(8^3:16+16^2.4^3-27^0.1^5\)
\(=512:16+256.64-1.1\)
\(=32+16384-1\)
\(=16416-1\)
\(=16415\)
8^3: 16 + 16^2.4^3 - 27^0.1^5
= 32 + 16 384 - 1
= 16 416 - 1
= 16 415