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a) \(2^x\cdot4=128\)
\(\Rightarrow2^x\cdot2^2=2^7\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x+2=7\)
\(\Rightarrow x=5\)
b) \(\left(2x+1\right)^3=125\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2\)
\(\Rightarrow x=2\)
c) \(2x-2^6=6\)
\(\Rightarrow2x-64=6\)
\(\Rightarrow2x=70\)
\(\Rightarrow x=70:2\)
\(\Rightarrow x=35\)
d) \(64\cdot4^x=45\)
\(\Rightarrow4^3\cdot4^x=45\)
\(\Rightarrow4^{x+3}=45\)
Xem lại đề
e) \(27\cdot3^x=243\)
\(\Rightarrow3^3\cdot3^x=3^5\)
\(\Rightarrow3^{x+3}=3^5\)
\(\Rightarrow x+3=5\)
\(\Rightarrow x=2\)
g) \(49\cdot7^x=2401\)
\(\Rightarrow7^2\cdot7^x=7^4\)
\(\Rightarrow7^{x+2}=7^4\)
\(\Rightarrow x+2=4\)
\(\Rightarrow x=2\)
h) \(3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
k) \(3^4\cdot3^x=3^7\)
\(\Rightarrow3^{x+4}=3^7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
n) \(3^x+25=26\cdot2^2+2\cdot3^0\)
\(\Rightarrow3^x+25=104+2\)
\(\Rightarrow3^x+25=106\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(x=4\)
`@` `\text {Ans}`
`\downarrow`
`a)`
`2^x*4 = 128`
`=> 2^x = 128 \div 4`
`=> 2^x = 2^7 \div 2^2`
`=> 2^x = 2^5`
`=> x = 5`
Vậy, `x = 5.`
`b)`
\(\left(2x+1\right)^3=125\)
`=> (2x + 1)^3 = 5^3`
`=> 2x + 1 = 5`
`=> 2x = 5-1`
`=> 2x = 4`
`=> x = 4 \div 2`
`=> x = 2`
Vậy, `x = 2`
`c)`
\(2x-2^6=6\)
`=> 2x = 6+2^6`
`=> 2x = 70`
`=> x = 70 \div 2`
`=> x = 35`
Vậy, `x = 35`
`d)`
\(64\cdot4^x=45\) Bạn xem lại đề
`e)`
`27*3^x = 243`
`=> 3^3 * 3^x = 3^5`
`=> 3^(3 + x) = 3^5`
`=> 3 + x = 5`
`=> x = 5 - 3`
`=> x = 2`
Vậy, `x = 2`
`g)`
`49* 7^x = 2401`
`=> 7^2 * 7^x = 7^4`
`=> 7^(2 + x) = 7^4`
`=> 2 + x = 4`
`=> x = 4 - 2`
`=> x = 2`
Vậy, `x = 2`
`h)`
`3^x = 81`
`=> 3^x = 3^4`
`=> x = 4`
Vậy, `x = 4`
`k)`
`3^4 * 3^x = 3^7`
`=> 3^(4 + x) = 3^7`
`=> 4 + x = 7`
`=> x = 7 - 4`
`=> x = 3`
Vậy, `x = 3`
`n)`
`3^x + 25 = 26*2^2 + 2*3^0`
`=> 3^x + 25 = 104 + 2`
`=> 3^x + 25 = 106`
`=> 3^x = 106 - 25`
`=> 3^x = 81`
`=> 3^x = 3^4`
`=> x = 4`
Vậy, `x = 4.`
\(#48Cd\)
\(\left(7x-11\right)^3=2^5.5^2+2.10^2\)
\(\Rightarrow\left(7x-11\right)^3=32.25+2.100\)
\(\Rightarrow\left(7x-11\right)^3=800+200\)
\(\Rightarrow\left(7x-11\right)^3=1000\)
\(\Rightarrow\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(\Rightarrow7x=21\)
\(\Rightarrow x=3\)
(7\(x\) - 11)3 = 25.52 + 2.102
(7\(x\) - 11)3 = 1000
(7\(x\) - 11)3 = 103
7\(x\) - 11 = 10
7\(x\) = 10 + 11
7\(x\) = 21
\(x\) = 21:7
\(x\) = 3
\(\left(7x-11\right)^3=2^5\cdot5^2+200\cdot2023^0\\ \left(7x-11\right)^3=32\cdot25+200\cdot1\\ \left(7x-11\right)^3=1000\\ \left(7x-11\right)^3=10^3\\ 7x-11=10\\ 7x=21\\ x=\dfrac{21}{7}=3\)
Lời giải:
$(7x-11)^3=2^5.5^2+200.2023^0=32.25+200=1000=10^3$
$\Rightarrow 7x-11=10$
$\Rightarrow 7x=21$
$\Rightarrow x=3$
X=0
Vì 2 mũ 5 = 32
2 mũ 2 = 4
Suy ra 2 mũ 5 + 2 mũ 2 +200 = 32+4+200=236
* ước của 236 = (1;2;4;59;118;236)
* Mà chỉ có 59+11=70 có chữ số đầu tiên là 7
ĐÚNG THÌ TICK CHO MÌNH NHA
1: \(6x^2-8=40\)
\(\Leftrightarrow x^2=8\)
hay \(x\in\left\{2\sqrt{2};-2\sqrt{2}\right\}\)
`a) 27.3^x =243`
`3^x=243/27=9`
`3^x=3^2`
`=>x=2`
`b) 49.7^x =2401`
`7^x = 2401/49=49`
`7^x=7^2`
`=>x=2`
`c) 3^x +25 =26*2^2+2.3^0`
`3^x = 26.4+2.1-25 = 81`
`3^x =3^4`
`=>x=4`
\(e,27.3^x=243\\ \Leftrightarrow3^3.3^x=3^5\\ \Leftrightarrow3^{3+x}=3^5\\ \Rightarrow3+x=5\\ \Leftrightarrow x=2\\ g,49.7^x=2401\\ \Leftrightarrow7^2.7^x=7^4\\ \Leftrightarrow7^{2+x}=7^4\\ \Rightarrow2+x=4\\ \Leftrightarrow x=2\\ h,3^x+25=26.2^2+2.3^0\\ \Leftrightarrow3^x+25=26.4+2.1\\ \Leftrightarrow3^x=104+2-25\\ \Leftrightarrow3^x=81=3^4\\ Vậy:x=4\)
1)
a) 2x + 5 = 3⁴ : 3²
2x + 5 = 3²
2x + 5 = 9
2x = 9 - 5
2x = 4
x = 4 : 2
x = 2
b) (3x - 24).73 = 2.74
(3x - 24).73 = 148
3x - 24 = 148/73
3x = 148/73 + 24
3x = 1900/73
x = 1900/73 : 3
x = 1900/219
c) [3.(42 - x)] + 15 = 23.3
126 - 3x + 15 = 69
141 - 3x = 69
3x = 141 - 69
3x = 72
x = 72 : 3
x = 24
d) 126 + (132 - x) = 300
132 - x = 300 - 126
132 - x = 174
x = 132 - 174
x = -42
2)
a) 120 - (x + 55) = 60
x + 55 = 120 - 60
x + 155 = 60
x = 60 - 55
x = 5
b) (7x - 11).3 = 25.52 + 200
(7x - 11).3 = 1500
7x - 11 = 1500 : 3
7x - 11 = 500
7x = 500 + 11
7x = 511
x = 511 : 7
x = 73
c) 2x + 2x + 4 = 544
4x = 544 - 4
4x = 540
x = 540 : 4
x = 135
(7x - 11)3 = 25.52 + 200
=> (7x - 11)3 = 800 + 200
=> (7x - 11)3 = 1000
=> (7x - 11)3 = 103
=> 7x - 11 = 10
=> 7x = 10 + 11
=> 7x = 21
=> x = 21 : 7 = 3
3x + 25 = 26.22 + 2.30
=> 3x + 25 = 104 + 2
=> 3x + 25 = 106
=> 3x = 106 - 25
=> 3x = 81
=> 3x = 34
=> x = 4
a)\(\left(7x-11\right)^3=2^5.5^2+200\) b) \(3^x+25=26.2^2+2.3^0\)
\(\left(7x-11\right)^3=32.25+200\) \(3^x+25=26.4+2.1\)
\(\left(7x-11\right)^3=800+200\) \(3^x+25=104+2\)
\(\left(7x-11\right)^3=1000\) \(3^x+25=106\)
\(\Rightarrow\left(7x-11\right)^3=10^3\) \(3^x=106-25\)
\(\Rightarrow7x-11=10\) \(3^x=81\)
\(7x=10+11\) \(3^x=3^4\)
\(x=\frac{21}{7}\) \(\Rightarrow x=4\)
\(x=3\) Vậy x = 4
Vậy x = 3