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8 tháng 6 2019
Tìm x:
1. 3x (2x + 3) - (2x + 5).(3x - 2) = 8
\(\Leftrightarrow6x^2+9x-6x^2+4x-15x+10=0 \)
\(\Leftrightarrow-2x+10=0\Leftrightarrow x=5\)
Vậy x = 5
2. 4x (x -1) - 3(x2 - 5) -x2 = (x - 3) - (x + 4)
\(\Leftrightarrow4x^2-4x-3x^2+15-x^2=x-3-x-4\)
\(\Leftrightarrow-4x+15=-7\)
\(\Leftrightarrow-4x=-22\Leftrightarrow x=\frac{11}{2}\)
Vậy x = \(\frac{11}{2}\)
3. 2 (3x -1) (2x +5) - 6 (2x - 1) (x + 2) = -6
\(\Leftrightarrow2\left(6x^2+15x-2x-5\right)-6\left(2x^2+4x-x-2\right)=-6\)
\(\Leftrightarrow12x^2+30x-4x-10-12x^2-24x+6x+12=-6\)
\(\Leftrightarrow8x=-8\Leftrightarrow x=-1\)
Vậy x = -1
4. 3 ( 2x - 1) (3x - 1) - (2x - 3) (9x - 1) - 3 = -3
\(\Leftrightarrow3\left(6x^2-2x-3x+1\right)-18x^2+2x+27x-3-3=-3\)
\(\Leftrightarrow18x^2-6x-9x+3-18x^2+2x+27x-6=-3\)
\(\Leftrightarrow14x=0\Leftrightarrow x=0\)
Vậy x = 0
5. (3x - 1) (2x + 7) - ( x + 1) (6x - 5) = (x + 2) - (x - 5)
\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5=7\)
\(\Leftrightarrow18x=9\Leftrightarrow x=\frac{1}{2}\)
Vậy x = \(\frac{1}{2}\)
6. 3xy (x + y) - (x + y) (x2 + y2 + 2xy) + y3 = 27
\(\Leftrightarrow3x^2y+3xy^2-\left(x+y\right)^3+y^3=27\)
\(\Leftrightarrow3x^2y+3xy^2-x^3-y^3-3x^2y-3xy^2+y^3=27\)
\(\Leftrightarrow-x^3=27\)
\(\Leftrightarrow x=-3\)
Vậy x = -3
7. 3x (8x - 4) - 6x (4x - 3) = 30
\(\Leftrightarrow24x^2-12x-24x^2+12x=30\)
\(\Leftrightarrow0=30\) ( vô lý)
Vậy pt vô nghiệm
8. 3x (5 - 2x) + 2x (3x - 5) = 20
\(\Leftrightarrow15x-6x^2+6x^2-10x=20\)
\(\Leftrightarrow5x=20\Leftrightarrow x=4\)
Vậy x = 4
MB
2
HH
22 tháng 6 2018
Giải:
a) \(\left(x-4\right)\left(x+4\right)-\left(1+2x\right)^2\)
\(=\left(x^2-16\right)-\left(1+4x+2x\right)\)
\(=x^2-16-1-4x-4x^2\)
\(=-17-4x-3x^2\)
Vậy ...
b) \(\left(3-2y\right)^2-\left(y-6\right)\left(y+6\right)\)
\(=9-12y+4y^2-\left(y^2-36\right)\)
\(=9-12y+4y^2-y^2+36\)
\(=45-12y+3y^2\)
Vậy ...
c) \(3x\left(x-5\right)-\left(x+7\right)\left(x-7\right)\)
\(=3x^2-15x-\left(x^2-49\right)\)
\(=3x^2-15x-x^2+49\)
\(=2x^2-15x+49\)
Vậy ...
KP
0
NT
5
MN
1 tháng 2 2018
b) \(x^9-x^7-x^6-x^5+x^4+x^3+x^2-1\)
\(=x^9-x^6-x^7+x^4-x^5+x^2+x^3-1\)
\(=x^6\left(x^3-1\right)-x^4\left(x^3-1\right)-x^2\left(x^3-1\right)+\left(x^3-1\right)\)
\(=\left(x^3-1\right)\left(x^6-x^4-x^2+1\right)\)
\(=\left(x-1\right)\left(x^2+x+1\right)\left[x^4\left(x^2-1\right)-\left(x^2-1\right)\right]\)
\(=\left(x-1\right)\left(x^2+x+1\right)\left(x-1\right)\left(x+1\right)\left(x^2-1\right)\left(x^2+1\right)\)
\(=\left(x-1\right)^3\left(x+1\right)^2\left(x^2+1\right)\left(x^2+x+1\right)\)
9 tháng 1 2021
Câu 1 :
a, \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}=\frac{2x-1}{3}-\frac{3-x}{4}\)
\(\Leftrightarrow\frac{6x+3}{4}+\frac{3-x}{4}=\frac{2x-1}{3}+\frac{5x+3}{6}\)
\(\Leftrightarrow\frac{5x+6}{4}=\frac{9x+1}{6}\Leftrightarrow\frac{30x+36}{24}=\frac{36x+4}{24}\)
Khử mẫu : \(30x+36=36x+4\Leftrightarrow-6x=-32\Leftrightarrow x=\frac{32}{6}=\frac{16}{3}\)
tương tự
PN
16 tháng 5 2021
\(\frac{19}{4}-\frac{2\left(3x-5\right)}{5}=\frac{3-2x}{10}-\frac{3x-1}{4}\)
\(< =>\frac{19.5}{20}-\frac{8\left(3x-5\right)}{20}=\frac{2\left(3-2x\right)}{20}-\frac{5\left(3x-1\right)}{20}\)
\(< =>95-24x+40=6-4x-15x+5\)
\(< =>-24x+135=-19x+11\)
\(< =>5x=135-11=124\)
\(< =>x=\frac{124}{5}\)
\(\frac{7}{4}-y.\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\Leftrightarrow\frac{5}{6}.y=\frac{7}{4}-\frac{1}{2}-\frac{1}{3}\)
\(\Leftrightarrow\frac{5}{6}.y=\frac{11}{12}\)
\(\Leftrightarrow y=\frac{11}{12}:\frac{5}{6}\)
\(\Leftrightarrow y=\frac{11}{12}.\frac{6}{5}\)
\(\Leftrightarrow y=\frac{11}{10}\)
Vậy\(y=\frac{11}{10}\)
Dumflinz