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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
18 tháng 9 2023
a, \(\dfrac{3}{7}\)\(x\)- \(\dfrac{2}{3}\)\(x\) = \(\dfrac{10}{21}\)
(\(\dfrac{3}{7}\) - \(\dfrac{2}{3}\)) \(\times\) \(x\) = \(\dfrac{10}{21}\)
- \(\dfrac{5}{21}\) \(\times\) \(x\) = \(\dfrac{10}{21}\)
\(x\) = \(\dfrac{10}{21}\) : (-\(\dfrac{5}{21}\))
\(x\) = -2
b, \(\dfrac{7}{35}\) : (\(x-\dfrac{1}{3}\)) = - \(\dfrac{2}{25}\)
\(x\) - \(\dfrac{1}{3}\) = \(\dfrac{7}{35}\) : (- \(\dfrac{2}{25}\))
\(x\) - \(\dfrac{1}{3}\) = - \(\dfrac{5}{2}\)
\(x\) = - \(\dfrac{5}{2}\) + \(\dfrac{1}{3}\)
\(x\) = - \(\dfrac{13}{6}\)
c, 3.(\(x\) - \(\dfrac{1}{2}\)) - 5.(\(x\) + \(\dfrac{3}{5}\)) = - \(x\)+ \(\dfrac{1}{5}\)
3\(x\) - \(\dfrac{3}{2}\) - 5\(x\) - 3 = - \(x\) + \(\dfrac{1}{5}\)
- \(x\) + 5\(x\) - 3\(x\) = - \(\dfrac{3}{2}\) - 3 - \(\dfrac{1}{5}\)
\(x\) = - \(\dfrac{47}{10}\)
NM
18 tháng 9 2023
\(a,\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\\ \Rightarrow x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\\ \Rightarrow x.-\dfrac{5}{21}=\dfrac{10}{21}\\ \Rightarrow x=-2\\ b,\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\\ \Rightarrow\dfrac{1}{5}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\\ \Rightarrow x-\dfrac{1}{3}=-\dfrac{5}{2}\\ \Rightarrow x=-\dfrac{13}{6}\\ c,3.\left(x-\dfrac{1}{2}\right)-5.\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\\ \Rightarrow3x-\dfrac{3}{2}-5x+5=-x+\dfrac{1}{5}\)
\(\Rightarrow x\left(3-5\right)-\dfrac{3}{2}+5=-x+\dfrac{1}{5}\\ \Rightarrow-2x-\dfrac{13}{2}=-x+\dfrac{1}{5}\\ \Rightarrow-x-\dfrac{13}{5}=\dfrac{1}{5}\\ \Rightarrow x=\dfrac{1}{5}-\dfrac{13}{5}\\ \Rightarrow x=-\dfrac{12}{5}.\)
NL
2
HP
21 tháng 9 2021
a. \(x-\dfrac{2}{35}=\dfrac{-2}{25}\)
<=> \(x=\dfrac{-2}{25}+\dfrac{2}{35}\)
<=> x = \(-\dfrac{4}{175}\)
b. \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)
<=> \(\dfrac{11}{12}-x-\dfrac{2}{5}=\dfrac{2}{3}\)
<=> \(-x=\dfrac{2}{3}-\dfrac{11}{12}+\dfrac{2}{5}\)
<=> \(-x=\dfrac{3}{20}\)
<=> \(x=\dfrac{-3}{20}\)
c. \(\dfrac{2}{5}+\dfrac{1}{4}x=\dfrac{-3}{10}\)
<=> \(\dfrac{1}{4}x=\dfrac{-3}{10}-\dfrac{2}{5}\)
<=> \(\dfrac{1}{4}x=\dfrac{-7}{10}\)
<=> \(x=\dfrac{-14}{5}\)
21 tháng 9 2021
a) \(x-\dfrac{2}{35}=-\dfrac{2}{25}\)
\(\Rightarrow x=-\dfrac{2}{25}+\dfrac{2}{35}\)
\(\Rightarrow x=-\dfrac{4}{175}\)
b) \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)
\(\Rightarrow x+\dfrac{2}{5}=\dfrac{11}{12}-\dfrac{2}{3}\)
\(\Rightarrow x+\dfrac{2}{5}=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}\)
\(\Rightarrow x=-\dfrac{3}{20}\)
c) \(\dfrac{2}{5}+\dfrac{1}{4}x=-\dfrac{3}{10}\)
\(\Rightarrow\dfrac{1}{4}x=-\dfrac{3}{10}-\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}x=-\dfrac{7}{10}\)
\(\Rightarrow x=-\dfrac{7}{10}:\dfrac{1}{4}\)
\(\Rightarrow x=-\dfrac{14}{5}\)
16 tháng 10 2023
\(A=\dfrac{9}{8}-\dfrac{8}{9}+\dfrac{3}{24}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{19}{25}-\dfrac{1}{9}+\dfrac{2}{25}-\dfrac{1}{81}\)
\(=\dfrac{9}{8}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{1}{8}-\dfrac{8}{9}-\dfrac{1}{9}-\dfrac{1}{81}+\dfrac{19}{25}+\dfrac{2}{25}\)
\(=\dfrac{10}{8}+\dfrac{1}{4}-\dfrac{5}{16}-1-\dfrac{1}{81}+\dfrac{21}{25}\)
\(=\dfrac{20+4-5}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{19}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{32891}{16\cdot81\cdot25}\)
b: \(B=-\dfrac{1}{3}-\dfrac{8}{35}-\dfrac{2}{9}-\dfrac{1}{35}+\dfrac{4}{5}-\dfrac{4}{9}+\dfrac{3}{7}\)
\(=\dfrac{-1}{3}-\dfrac{2}{9}-\dfrac{4}{9}-\dfrac{8}{35}-\dfrac{1}{35}+\dfrac{4}{5}+\dfrac{3}{7}\)
\(=\dfrac{-3-2-4}{9}+\dfrac{-9}{35}+\dfrac{28+15}{35}\)
\(=-1+\dfrac{-9+43}{35}=-1+\dfrac{34}{35}=-\dfrac{1}{35}\)
LT
1 tháng 10 2020
a, ĐK: \(x\ne24\)
580 :( x -24 ) =329 -150 : 2
<=> 580 :( x -24 ) = 329 - 75
<=> 580 :( x -24 ) = 254
<=> x - 24 = \(\frac{290}{127}\)
<=> x = \(\frac{3338}{127}\left(TM\right)\)
Vậy \(x=\frac{3338}{127}\)
b, 7 (x-1 ) +35= 25 + 279 :9
<=> 7x - 7 + 35 = 25 + 31
<=> 7x +28 = 56
<=> 7x = 28
<=> x = 4
Vậy x =4
c,4 ( 2x+ 7 ) -3 (3x -2 ) =24
<=> 8x + 28 - 9x + 6 = 24
<=> 34 - x = 24
<=> x = 10
Vậy x = 10
d,( x-1 ) (x-2) =3(x-1)
<=> ( x-1 ) (x-2) - 3(x-1) = 0
<=> (x- 1)(x - 2 - 3) = 0
<=> (x -1)(x - 5) = 0
<=> \(\left[{}\begin{matrix}x-1=0\\x-5=0\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x=1\\x=5\end{matrix}\right.\)
Vậy x ={1; 5}
1 tháng 10 2020
e, (x + 3) + (x + 7) + (x + 11) + ... + (x + 79) = 860
x + 3 + x + 7 + x + 11 + ... + x + 79 = 860
Có tất cả: (79 - 3) : 4 + 1 = 20 số hạng \(\Rightarrow\) có 20x
hay x + 3 + x + 7 + x + 11 + ... + x + 79 = 860
\(\Rightarrow\) 20x + (3 + 7 + ... + 79) = 860
3 + 7 + ... + 79 = (79 + 3) x 20 : 2 = 820
\(\Rightarrow\) 20x + (3 + 7 + ... + 79) = 860
\(\Rightarrow\) 20x + 820 = 860
\(\Rightarrow\) 20x = 40
\(\Rightarrow\) x = 2
Vậy x = 2
Chúc bn học tốt!
NL
2
28 tháng 8 2017
7/35:(x-1/3)=-2/25
<=>x-1/3=7/35:-2/25
<=>x-1/3=-5/2
<=>x=-13/6
vậy x =-13/6
30 tháng 8 2017
a) \(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\)
<=> \(x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\)
<=> \(x.\left(-\dfrac{5}{21}\right)=\dfrac{10}{21}\)
<=> \(x=-2\)
b) \(\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\)
<=> \(x-\dfrac{1}{3}=-\dfrac{5}{2}\)
<=> \(x=-\dfrac{13}{6}\)
30 tháng 8 2017
a, \(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\)
\(\Leftrightarrow x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\)
\(\Leftrightarrow x.\dfrac{-5}{21}=\dfrac{10}{21}\)
\(\Leftrightarrow x=-2\)
Vậy ...
b, \(\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=\dfrac{-2}{25}\)
\(\Leftrightarrow x-\dfrac{1}{3}=\dfrac{-5}{2}\)
\(\Leftrightarrow x=\dfrac{-13}{6}\)
Vậy ...
B
1
26 tháng 7 2023
=> x-1/2 = 6/35 : (-3/25)
=> x-1/2= -10/7
=> x= (-10/7) + 1/2
=> x= -13/14
Vậy x= -13/14
BV
5 tháng 9 2018
a, \((\frac{3}{7}-\frac{2}{3})\) .x =\(\frac{10}{21}\)
\(\frac{-5}{21}\).x=\(\frac{10}{21}\)
x= -2
Mk chỉ làm 1 phần các phằn còn lại tương tự
\(\frac{7}{35}\div\left(x-\frac{1}{3}\right)=\frac{2}{25}\)
\(\left(x-\frac{1}{3}\right)=\frac{7}{35}\div\frac{2}{25}\)
\(x-\frac{1}{3}=\frac{7}{35}\times\frac{25}{2}\)
\(x-\frac{1}{3}=\frac{175}{70}\)
\(x=\frac{175}{70}+\frac{1}{3}\)
\(x=\frac{525}{210}\)