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{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
a) \(2^2.3^{3x}-27^x=9^5\)
\(4.3^{3x}-\left(3^3\right)^x=\left(3^2\right)^5\)
\(4.3^{3x}-3^{3x}=3^{10}\)
\(3^{3x}\left(4-1\right)=3^{10}\)
\(3^{3x}.3=3^{10}\)
\(3^{3x+1}=3^{10}\)
3x + 1 = 10
3x = 9
x = 3.
b. \(5.3^x=135\)
\(3^x=27\)
\(3^x=3^3\)
x = 3.
c. \(5^x.5^4=5^{20}\)
\(5^{x+4}=5^{20}\)
x + 4 = 20
x = 16
Mấy cái này mũ thấp:
a) 48+288:(x-3)2=50 <=> 288:(x-3)2=2 <=> (x-3)2=144 <=> \(\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)<=>\(\orbr{\begin{cases}x=9\\x=-15\end{cases}}\).Vậy,...
b) x2-15=1 <=> x=+-4. Vậy,...
c) 45:x=5 <=> x=9. Vậy,...
\(5.3^5:\left(3^8:3^5\right)-2^3.5\)\(=\)
\(5.3^5:3^3-2^3.5\)\(=\)
\(5.3^2-2^3.5\)\(=\)
\(5\left(3^2-2^3\right)\)\(=\)\(5\)
1/(6x-32).35=5.37
(6x-9) = 5. 2187
(6x-9) = 10935
6x = 10935 + 9 =10944
x = 10944 : 6 =1824
2/8x-5.23=(5.2)3-53.23
/8x-5.8=1000-125.8
8x -40 = 0
8x = 40
x = 40 : 8 =5
Phần trong ngoặc.........phân tích cơ số ra thừa số nguyên tố:
\(125^3\cdot7^5-175^5:5=\left(5^3\right)^3\cdot7^5-\left(5^2\cdot7\right)^5:5=5^9\cdot7^5-5^9\cdot7^5=0\)
70-5 . (x-3) = 5.32
=> 70-5.(x-3)=5.9
=> 70-5.(x-3)=45
=> 5.(x-3)=70-45
=> 5.(x-3)=25
=> x-3=25:5
=> x-3=5
=> x=5+3
=> x=8