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6 tháng 8 2020

\(\frac{5}{6}=\frac{x-1}{x}\left(đk:x\ne0\right)\)

\(< =>5x=6\left(x-1\right)< =>5x=6x-6\)

\(< =>6x-5x=6< =>x=6\left(tmđk\right)\)

\(\frac{1}{2}=\frac{x+1}{3x}\left(đk:x\ne0\right)\)

\(< =>3x=2\left(x+1\right)< =>3x=2x+2\)

\(< =>3x-2x=2< =>x=2\left(tmđk\right)\)

\(\frac{3}{x+2}=\frac{5}{2x+1}\left(đk:x\ne-2;-\frac{1}{2}\right)\)

\(< =>3\left(2x+1\right)=5\left(x+2\right)< =>6x+3=5x+10\)

\(< =>6x-5x=10-3< =>x=7\left(tmđk\right)\)

\(\frac{5}{8x-2}=-\frac{4}{7-x}\left(đk:x\ne\frac{1}{4};7\right)\)

\(< =>\frac{5}{8x-2}=\frac{4}{x-7}< =>5\left(x-7\right)=4\left(8x-2\right)\)

\(< =>5x-35=32x-8< =>32x-5x=-35+8\)

\(< =>27x=-27< =>x=-1\)

6 tháng 8 2020

\(\frac{4}{3}=\frac{2x-1}{3}< =>4.3=\left(2x-1\right).3\)

\(< =>12=6x-3< =>6x=12+3\)

\(< =>6x=15< =>x=\frac{15}{6}=\frac{5}{2}\)

\(\frac{2x-1}{3}=\frac{3x+1}{4}< =>4\left(2x-1\right)=3\left(3x+1\right)\)

\(< =>8x-4=9x+3< =>9x-8x=-4-3\)

\(< =>9x-8x=-7< =>x=-7\)

\(\frac{4}{x+2}=\frac{7}{3x+1}\left(đk:x\ne-2;-\frac{1}{3}\right)\)

\(< =>4\left(3x+1\right)=7\left(x+2\right)< =>12x+4=7x+14\)

\(< =>12x-7x=14-4< =>5x=10\)

\(< =>x=\frac{10}{5}=2\left(tmđk\right)\)

\(-\frac{3}{x+1}=\frac{4}{2-2x}\left(đk:x\ne-1;1\right)\)

\(< =>-3\left(2-2x\right)=4\left(x+1\right)< =>-6+6x=4x+4\)

\(< =>6x-4x=4+6< =>2x=10\)

\(< =>x=\frac{10}{2}=5\left(tmđk\right)\)

\(\frac{x+1}{3}=\frac{3}{x+1}\left(đk:x\ne-1\right)\)

\(< =>\left(x+1\right)\left(x+1\right)=3.3\)

\(< =>x^2+2x+1=9< =>x^2+2x+1-9=0\)

\(< =>x^2+2x-8=0< =>x^2-2x+4x-8=0\)

\(< =>x\left(x-2\right)+4\left(x-2\right)=0< =>\left(x+4\right)\left(x-2\right)=0\)

\(< =>\orbr{\begin{cases}x+4=0\\x-2=0\end{cases}< =>\orbr{\begin{cases}x=-4\\x=2\end{cases}}}\left(tmđk\right)\)

a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)

\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)

\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)

hay \(x=-\dfrac{41}{12}\)

Vậy: \(x=-\dfrac{41}{12}\)

26 tháng 7 2021

giải nhanh giup mình nhé

5 tháng 5 2015

Sao toàn viết chữ thế ? Đọc sao nổi ? Viết lại ra số đi

5 tháng 5 2015

\(a.\frac{2}{3}+\frac{1}{5}\cdot\frac{10}{7}\)

\(=\frac{2}{3}+\frac{1\cdot2}{1\cdot7}\)

\(=\frac{2}{3}+\frac{2}{7}=\frac{2\cdot7}{21}+\frac{2\cdot3}{21}=\frac{14}{21}+\frac{6}{21}=\frac{20}{21}\)

\(b.\frac{2}{7}\cdot\frac{4}{7}+\frac{2}{7}\cdot\frac{3}{7}\)

\(=\frac{2}{7}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)\)

\(=\frac{2}{7}\cdot\frac{7}{7}=\frac{2}{7}\cdot1=\frac{2}{7}\)

\(c.\left[-\frac{1}{4}+\frac{3}{10}\right]:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\left[-\frac{5}{20}+\frac{6}{20}\right]:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\frac{1}{20}:\left(-\frac{3}{5}\right)-\frac{7}{6}\)

\(=\frac{1}{20}\cdot\left(-\frac{5}{3}\right)-\frac{7}{6}\)

\(=\frac{1\cdot\left(-1\right)}{4\cdot3}-\frac{7}{6}\)

\(=\left(-\frac{1}{12}\right)-\frac{7}{6}=\left(-\frac{1}{12}\right)-\frac{14}{12}=-\frac{15}{12}\)

bài 2 :a) \(2x-2\frac{2}{7}=2\frac{5}{7}\)

\(2x=2\frac{5}{7}-2\frac{2}{7}\)

\(2x=\left(2-2\right)+\left(\frac{5}{7}-\frac{2}{7}\right)\)

\(2x=0+\frac{3}{7}\)

\(2x=\frac{3}{7}\)

\(x=\frac{3}{7}:2=\frac{3}{7}\cdot\frac{1}{2}=\frac{3}{14}\)

\(b.\frac{17}{13x}=\frac{4}{39}\)

\(\Rightarrow13x\cdot4=17\cdot39\)

\(\Rightarrow13x\cdot4=663\)

\(\Rightarrow13x=663:4\)

\(\Rightarrow13x=165,75\)

\(\Rightarrow x=165,75:13\)

\(\Rightarrow x=12,75\)

\(****nha!!!!!!!!!!!!\)

 

12 tháng 4 2020

a/ \(2x+\frac{1}{7}=\frac{1}{3}\)

=> \(2x=\frac{1}{3}-\frac{1}{7}=\frac{7}{21}-\frac{3}{21}\)

=> \(2x=\frac{4}{21}\)

=> \(x=\frac{4}{21}:2=\frac{4}{21}.\frac{1}{2}=\frac{2}{21}\)

b/ \(3\left(x-\frac{1}{2}\right)=\frac{4}{9}\)

=> \(x-\frac{1}{2}=\frac{4}{9}:3=\frac{4}{9}.\frac{1}{3}\)

=> \(x-\frac{1}{2}=\frac{4}{27}\)

=> \(x=\frac{4}{27}+\frac{1}{2}=\frac{8}{54}+\frac{27}{54}=\frac{35}{54}\)

c/ \(\left(x-5\right)^2+4=68\)

=> \(\left(x-5\right)^2=68-4=64\)

=> \(\left[{}\begin{matrix}x-5=8\\x-5=-8\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=8+5=13\\x=-8+5=-3\end{matrix}\right.\)

d/ \(\left(\left|x\right|-\frac{1}{2}\right)\left(2x+\frac{3}{2}\right)=0\)

=> \(\left[{}\begin{matrix}\left|x\right|-\frac{1}{2}=0\\2x+\frac{3}{2}=0\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}\left|x\right|=0+\frac{1}{2}=\frac{1}{2}\\2x=0-\frac{3}{2}=-\frac{3}{2}\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}\left[{}\begin{matrix}x=\frac{1}{2}\\x=-\frac{1}{2}\end{matrix}\right.\\x=-\frac{3}{2}:2=-\frac{3}{2}.\frac{1}{2}=-\frac{3}{4}\end{matrix}\right.\)

e) \(5x+2=3x+8\)

=> \(5x-3x=8-2=6\)

=> \(2x=6\)

=> \(x=6:2=3\)

f/ \(26-\left(5-2x\right)=27\)

=> \(5-2x=26-27=-1\)

=> \(2x=5-\left(-1\right)=5+1=6\)

=> \(x=6:2=3\)

g/ \(\left(4x-8\right)-\left(2x-6\right)=4\)

=> \(4x-8-2x+6=4\)

=> \(\left(4x-2x\right)+\left(-8+6\right)=4\)

=> \(2x+-2=4\)

=> \(2x=4+2=6\)

=> \(x=6:2=3\)

h/ \(\left(x+3\right)^3:3-1=-10\)

=> \(\left(x+3\right)^3:3=-10+1=-9\)

=> \(\left(x+3\right)^3=-9.3=-27\)

=> \(x+3=-3\)

=> \(x=-3-3=-6\)

12 tháng 4 2020

Thank

21 tháng 7 2018

a) \(\frac{x-5}{7}=\frac{5}{3}\)                                                                         

\(\Rightarrow\left(x-5\right)\cdot3=7\cdot5\)

\(\Rightarrow3x-15=35\)

\(\Rightarrow3x=15+35\)

\(\Rightarrow3x=50\)

\(\Rightarrow x=\frac{50}{3}\)

b) \(\frac{x-3}{3}=\frac{12}{x-3}\)

\(\Rightarrow\left(x-3\right)\cdot\left(x-3\right)=3\cdot12\)

\(\Rightarrow\left(x-3\right)^2=36\)

\(\Rightarrow\left(x-3\right)^2=6^2\)hoặc \(\left(x-3\right)^2=\left(-6\right)^2\)

\(\Rightarrow x-3=6\)                      \(x-3=-6\)

\(\Rightarrow x=6+3\)                       \(x=-6+3\)

\(\Rightarrow x=9\)                    hoặc     \(x=-3\)

21 tháng 7 2018

c) \(\frac{5-2x}{4}=\frac{7}{3}\)

\(\Rightarrow\left(5-2x\right)\cdot3=4\cdot7\)

\(\Rightarrow15-6x=28\)

\(\Rightarrow6x=15-28\)

\(\Rightarrow6x=-13\)

\(\Rightarrow x=-\frac{13}{6}\)

d) \(\frac{x+1}{4}=\frac{7}{3}\)

\(\Rightarrow\left(x+1\right)\cdot3=2\cdot7\)

\(\Rightarrow3x+3=28\)

\(\Rightarrow3x=28-3\)

\(\Rightarrow3x=25\)

\(\Rightarrow x=\frac{25}{3}\)

Chúc bạn học tốt !!!

9 tháng 4 2018

a )  \(-\frac{3}{7}.\frac{3}{11}+-\frac{3}{7}.\frac{8}{11}+1\frac{3}{7}\)

\(=-\frac{3}{7}.\left(\frac{3}{11}+\frac{8}{11}\right)+\frac{10}{7}\)

\(=-\frac{3}{7}.\frac{11}{11}+\frac{10}{7}\)

\(=-\frac{3}{7}.1+\frac{10}{7}\)

\(=\frac{10}{7}\)

b )   \(75\%.10,5=\frac{3}{4}.10,5=7,875\)

c )  \(5-3.\left(\left|-4\right|-30:15\right)\)

\(=5-3.\left(4-2\right)\)

\(=5-3.2\)

\(=5-6\)

\(=-1\)

d )  \(-\frac{5}{7}.\frac{2}{11}+-\frac{5}{7}.\frac{9}{11}+1\frac{5}{7}\)

\(=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

\(=-\frac{5}{7}.1+\frac{12}{7}\)

\(=\frac{7}{7}\)

\(=1\)

Chúc bạn học tốt !!! 

14 tháng 1 2017

\(A=\frac{1}{3.5}+\frac{1}{5.7}+..+\frac{1}{\left(2x+1\right)\left(2x+3\right)}=\frac{100}{609}\\ \)

\(2A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+..+\frac{1}{2x+1}-\frac{1}{2x+3}=\frac{1}{3}-\frac{1}{2x+3}\)\(=\frac{2x}{3\left(2x+3\right)}\)

\(A=\frac{x}{3\left(2x+3\right)}=\frac{100}{609}=\frac{100}{3.203}=\frac{100}{3\left(2.100+3\right)}\)\(\Rightarrow x=100\)