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\(=\dfrac{2^{36}.3^{36}\left(2.5^2.5^{40}-2.5.5^{34}\right)}{2^{30}.3^{30}.5^{30}.2^4.5^4\left(2^2.5^2.3^5.5^5-2^2.3^5\right)}=\dfrac{2^{36}.3^{36}\left(2.5^{42}-2.5^{35}\right)}{2^{34}.3^{30}.5^{34}\left(2^2.3^5.5^7-2^2.3^5\right)}\)
\(=\dfrac{2^2.3^6.2.5^{35}\left(5^7-1\right)}{2^2.3^5\left(5^7-1\right)}=3.2.5^{35}=6.5^{35}\)
\(20.100+10.200-10.200\)
\(=2000+0\)
\(=2000\)
Chúc bạn học tốt
20 . 100 + 10 . 200 - 10 . 200
= 20 . 100 + 10 . 2 . 100 - 10 . 2 . 100
= 20 . 100 + 20 . 100 - 20 . 100
= 20 ( 100 + 100 - 100 )
= 20 . 100
= 2000
\(\text{15.(-176)+15.76+100.15}\)
\(=15.\left(-176+76+100\right)\)
\(=15.0\)
\(=0\)
\((-18)+(-31)+98+\left|-18\right|+(-69)\)
\(=(-18)+(-31)+98+18+(-69)\)
\(=(-18)+18+(-31)+(-69)+98\)
\(=0+(-100)+98=-2\)
A=20/1.21+20/2.22+...+20/80.100
=1-1/21+1/2-1/22+...+1/80-1/100
=(1+1/2+...+1/80)-(1/21+1/22+...+1/100)
80B=80/1.81+80/2.82+...+8/20.100
=1-1/81+1/2-1/82+...+1/20-1/100
=(1+1/2+...+1/20)-(1/81+1/82+...+1/100)
=(1+1/2+1/3+...+1/20+1/21+1/22+...+1/80)-(1/21+1/22+...1/80+1/81+1/82+...1/100)
=>20A=80B
=>A=4B
A=20/1.21+20/2.22+...+20/80.100
=1-1/21+1/2-1/22+...+1/80-1/100
=(1+1/2+...+1/80)-(1/21+1/22+...+1/100)
80B=80/1.81+80/2.82+...+8/20.100
=1-1/81+1/2-1/82+...+1/20-1/100
=(1+1/2+...+1/20)-(1/81+1/82+...+1/100)
=(1+1/2+1/3+...+1/20+1/21+1/22+...+1/80)-(1/21+1/22+...1/80+1/81+1/82+...1/100)
=>20A=80B
=>A=4B
\(65.142+100.15-42.65+20.100\)
\(=65.\left(142-42\right)+100.\left(15+20\right)\)
\(=65.100+100.35\)
\(=100.\left(65+35\right)\)
\(=100.100\)
\(=10000\)
142,742 nếu đúng thì k cho mình nha !!!