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1)
= (6 x 25 - 13 x 7) x 2 - 8 x (7-3)^ 2
= (150 - 91) x 2 - 8 x 4^2
= 59 x 2 - 8 x 16
= 118 - 128
= -10 (Nếu bạn chưa học số âm thì nói là Không có kết quả)
a, Ix-2I*(x-5)<0
lx-2l lớn hơn or bằng 0 nên (x-5)<0 hay x<5
b, Ix-2I*(x-5)>0
lx-2l lớn hơn or bằng 0 nên (x-5)>0 hay x>5
\(\frac{12}{7}\times\frac{2}{11}+\frac{12}{11}\times\frac{15}{7}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\frac{2}{11}+\frac{12}{7}\times\frac{15}{11}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\left(\frac{2}{11}+\frac{15}{11}-\frac{6}{11}\right)\)
\(=\frac{12}{7}\times1=\frac{12}{7}\)
\(\frac{12}{7}.\frac{2}{11}+\frac{12}{11}.\frac{15}{7}-\frac{12}{7}.\frac{6}{11}\)
= \(\frac{24}{77}\)+\(\frac{180}{77}\)-\(\frac{72}{77}\)
=\(\frac{132}{77}\)
+) -11-|25-x|=(-8).2
-11-|25-x|=-16
|25-x|=5
\(\Leftrightarrow\)\(\orbr{\begin{cases}25-x=5\\25-x=-5\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=20\\x=30\end{cases}}\)
Vậy x \(\in\){20;30}
+) 3x2-53=-5
3x2=48
x2=16
x=\(\pm\)4
Vậy x=\(\pm\)4
+) 5x5+12=-148
5x5 = -160
x5= -32
x= -2
Vậy x= -2
+) 3.(-2)x -5 = -101
3.(-2)x = -96
(-2)x = -32
(-2)x= (-2)5
x=5
Vậy x=5
Chúc bạn học tốt
\(-11-\left|25-x\right|=\left(-8\right).2\)
\(\Rightarrow\left|25-x\right|=5\)
\(\Leftrightarrow\orbr{\begin{cases}25-x=5\\25-x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=20\\x=30\end{cases}}\)
\(3x^2-53=-5\)
\(\Rightarrow3x^2=48\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=\pm4\)
\(5x^5+12=-148\)
\(5x^5=-160\)
\(\Rightarrow x^5=-32\)
\(\Rightarrow x=-2\)
\(3\left(-2\right)^x-5=-101\)
\(\Rightarrow3.\left(-2\right)^x=-96\)
\(\Rightarrow\left(-2\right)^x=-32=\left(-2\right)^5\)
\(\Rightarrow x=5\)
\(a,\frac{62}{7}:x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}:x=\frac{1624}{27}\)
\(x=\frac{62}{7}:\frac{1624}{27}=\frac{837}{5684}\)
\(b,\frac{1}{5}:x=\frac{1}{5}-\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{2}{35}\)
\(x=\frac{1}{5}:\frac{2}{35}=\frac{7}{2}\)
\(c,\frac{2}{3}.x-\frac{4}{7}=\frac{1}{7}\)
\(\frac{2}{3}.x=\frac{1}{7}+\frac{4}{7}=\frac{5}{7}\)
\(x=\frac{5}{7}:\frac{2}{3}=\frac{15}{14}\)
\(d,\frac{2}{7}-\frac{8}{9}.x=\frac{2}{3}\)
\(\frac{8}{9}.x=\frac{2}{7}-\frac{2}{3}=-\frac{8}{21}\)
\(x=-\frac{8}{21}:\frac{8}{9}=-\frac{3}{7}\)
\(e,\frac{4}{7}+\frac{5}{9}:x=\frac{1}{5}\)
\(\frac{5}{9}:x=\frac{1}{5}-\frac{4}{7}=-\frac{13}{35}\)
\(x=\frac{5}{9}:-\frac{13}{35}=\frac{175}{117}\)
\(i,\frac{2}{5}-\frac{2}{5}.x=\frac{2}{5}\)
\(\frac{2}{5}.\left(1-x\right)=\frac{2}{5}\)
\(1-x=\frac{2}{5}:\frac{2}{5}=1\)
\(x=1-1=0\)
\(g,\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\frac{1}{3}:x=-1-\frac{2}{3}=-\frac{5}{3}\)
\(x=\frac{1}{3}:-\frac{5}{3}=-\frac{1}{5}\)
học tốt nha
1, Tìm x thuộc Z:
a) x2=100
=> x^2 = 10^2
=> x = 10
Vậy x = 10
b) ( x-5)2-7=9
=> ( x - 5 )^2 = 9 + 7
=> ( x - 5 )^2 = 16
=> ( x - 5 )^2 = 4 ^ 2
=> x - 5 = 4
=> x = 5 + 4
=> x = 9
kick nhé
a) \(x^2=100\)
\(=>x^2=10^2\)
\(=>x=10\)
b) \(\left(x-5\right)^2-7=9\)
\(=>\left(x-5\right)^2=9+7\)
\(=>\left(x-5\right)^2=16\)
\(=>\left(x-5\right)^2=4^2\)
\(=>x-5=4\)
\(=>x=4+5\)
\(=>x=9\)
5*x-x=29-6^2/2^2
5*x-x=29-36/4
5*x-x=29-9
5*x-x=20
(5-1)x=20
4x=20
x=5
5x - x = 29 - 6^2/2^2
5x - x = 29 - 36/4
5x - x = 29 - 9
5x - x = 20
=> x = 5