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Ta có : 5x-2 + 5x = 130
=> 5x . \(\frac{1}{25}\)+ 5x = 130
=> 5x . 1.04 = 130
=> 5x = 125 => x=3
\(2^{x-5}=8\cdot2^{130}\)
\(2^{x-5}=2^3\cdot2^{130}=2^{133}\)
\(\Rightarrow x-5=133\)
\(\Rightarrow x=138\)
Vậy,........
2x-5=8.2130
2x-5=23.2130
2x-5=2133
=>x-5=133
x=133+5
x=128
k nha!
Bài 1 . Tìm x
a) 723 - ( 7x - 152 ) = 714
7x - 152 = 723 - 714
7x - 152 = 9
7x = 9 + 152
7x = 161
x = 161 : 7
x = 23
Vậy x = 23
b) ( 2x - 130 ) : 4 + 213 = 52 + 193
( 2x - 130 ) : 4 + 213 = 218
( 2x - 130 ) : 4 = 218 - 213
( 2x - 130 ) : 4 = 5
2x - 130 = 5 . 4
2x - 130 = 20
2x = 20 + 130
2x = 150
x = 150 : 2
x = 75
Vậy x = 75
c) ( x - 6 )2 = 9
( x - 6 )2 = 32
x - 6 = 3 <=> x = 3 + 6 <=> x = 9
x - 6 = -3 <=> x = -3 + 6 <=> x = 3
a) 5x - 2 + 5x = 130
<=> 5x : 25 + 5x = 130
<=> 5x ( 1/25 + 1 ) = 130
<=> 5x .26/25 = 130
<=> 5x = 125
<=> x = 3
b) 3x + 2 +3x = 1000 - 190
<=> 3x . 9 + 3x = 810
<=> 3x ( 9 + 1 ) = 810
<=> 3x = 81
<=> x= 4
Ta có:
a) 5x - 2 + 5x = 130
=> 5x . 1/25 + 5x = 130
=> 5x. (1/25 + 1) = 130
=> 5x = 130 : 26/25
=> 5x = 125
=> 5x = 53
=> x = 3
b) 3x + 2 + 3x = 1000 - 190
=> 3x.9 + 3x = 810
=> 3x (9 + 1) = 810
=> 3x.10 = 810
=> 3x = 810/10 = 81
=> 3x = 34
=> x =4
tìm x
a, 2.x -138=2³.3²
\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x=72+138\)
\(2.x=210\)
\(x=210:2\)
\(x=105\)
\(\Rightarrow x=105\)
b, 2x-5=8.2-130
Sai đề bài !
a) 80 - [130 - (12 -4)2 ]
= 80 - ( 130 - 82 )
= 80 - 116
= -36
b) 541 + (218 - b) = 735
218 - b = 194
b = 24
c) 5(x + 35) =515
x+35 = 103
x = 68
d) 96 - 3(x + 1) = 42
3(x+1) = 54
x+1 = 18
x = 17
12x - 33 = 32 . 33
12x - 33 = 243
12x = 276
x = 23
\(1.125+\left(x-5\right)=130\)
\(\Leftrightarrow125+x+5=130\)
\(\Leftrightarrow x=0\)
\(2.127-\left(5-x\right)=120\)
\(\Leftrightarrow127-5+x=120\)
\(\Leftrightarrow122+x=120\)
\(\Leftrightarrow x=-2\)
\(3.25-\left(x-3\right)=12-x\)
\(\Leftrightarrow25-x+3=12-x\)
\(\Leftrightarrow\left(25-x+3\right)-\left(12-x\right)=0\)
\(\Leftrightarrow25-x+3-12+x=0\)
\(\Leftrightarrow-x+x=-16\)
Vì \(x\in Z\) Nên \(x\) không tồn tại.
\(4.\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\Leftrightarrow-8-x+5-x=-3\)
\(\Leftrightarrow-2x=-3+8-5\)
\(\Leftrightarrow-2x=0\)
\(\Leftrightarrow x=0\)
\(5.\left(-2\right)^2-\left(6-x\right)=13\)
\(\Leftrightarrow4-6+x=13\)
\(\Leftrightarrow-2+x=12\)
\(\Leftrightarrow x=14\)
1, 125 + (x-5)=130
125+x-5=130
x-5=130-125
x-5=5
x=5+5=10
2, 127-(5-x)=120
127+5+x=120
5+x=120-127
5+x=-7
x=-7-5
x=-12
3, 25-(x-3)=12-x
25+x+3=12-x
28+x=12-x
x+x=12-28
2x=16
x=-8
4, \(\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\left(-2\right)^3\)+x+5=-3+x
\(\left(-2\right)^3\)+5+(-3)=x+x
-8+5-3=2x
-6=2x
x=-3
5, 3.\(\left(-2\right)^2\)-(6-x)=13
3.(-4)+6+x=13
-12+6+x=13
-6+x=13
x=13+6
x=19
\(\left(x+5\right)^3+5=130\)
\(\Leftrightarrow\left(x+5\right)^3=125=5^3\)
\(\Leftrightarrow x+5=5\)
\(\Leftrightarrow x=0\)
(x + 5)3 + 5 = 130
(x + 5)3 = 130 - 5
(x + 5)3 = 125
(x + 5)3 = 53
x + 5 = 5
x = 5 - 5
x = 0
5x-1 + 5 = 130
<=> 5x-1 = 125
<=> 5x-1 = 53
<=> x - 1 = 3
<=> x = 4
Vậy x = 4
_Hok tốt_
ta có 5^x-1 +5=130
=>5^x-1=125
<=>x-1=3
<=>x=4