Question

[dung doan]

\(5\dfrac{1}{5}\)+\(\dfrac{1}{2}\)-​\(\sqrt{20}\)+\(\sqrt{5}\)

\(\sqrt{\dfrac{1}{2}}\)+\(\sqrt{4.5}\)+\(\sqrt{12.5}\)

\(\sqrt{20}\)-\(\sqrt{45}\)+\(3\sqrt{18}\)+\(\sqrt{77}\)

\(0.1\sqrt{200}\)+\(2\sqrt{0.08}\)+\(0.4\sqrt{50}\)

\(\dfrac{1}{2}\sqrt{48}\)-\(2\sqrt{75}\)-\(\dfrac{\sqrt{33}}{\sqrt{11}}\)+\(5\sqrt{1\dfrac{1}{3}}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: Sửa đề: \(5\dfrac{1}{5}-\dfrac{1}{2}\sqrt{20}+\sqrt{5}\)

\(=5.2-\dfrac{1}{2}\cdot2\sqrt{5}+\sqrt{5}=5.2\)

b: \(=\dfrac{1}{2}\sqrt{2}+\dfrac{3}{2}\sqrt{2}+\dfrac{5}{2}\sqrt{2}=\dfrac{9}{2}\sqrt{2}\)

c: \(=2\sqrt{5}-3\sqrt{5}+9\sqrt{2}+\sqrt{77}=-\sqrt{5}+9\sqrt{2}+\sqrt{77}\)

d: \(=\dfrac{1}{10}\cdot10\sqrt{2}+\dfrac{2}{5}\sqrt{2}+0.4\cdot5\sqrt{2}\)

\(=\dfrac{17}{5}\sqrt{2}\)