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\(565-13x=370\\ 13x=565-370=195\\x=\dfrac{195}{13}=15\)
\(105-\left(135-7x\right):9=97\\ \dfrac{135-7x}{9}=105-97=8\\ 135-7x=9.8=72\\ 7x=135-72=63\\ x=\dfrac{63}{7}=9\)
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565 - 13x = 370
13x = 565 - 370 = 195
x = 195 : 13
x = 15
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a) 565 - 13.x = 370
13.x = 565 - 370
13.x = 195
x = 195 : 13
x = 15
b) 105 - (135 - 7x) : 9 = 97
(135 - 7x) : 9 = 105 - 97
(135 - 7x) : 9 = 8
135 - 7x = 8 x 9
135 - 7x = 72
7x = 135 - 72
7x = 63
x = 63 : 7
x = 9
a) 565 - 13.x = 370
13.x = 565 - 370
13.x = 195
x = 195 : 13
x = 15
b) 105 - (135 - 7x) : 9 = 97
(135 - 7x) : 9 = 105 - 97
(135 - 7x) : 9 = 8
135 - 7x = 8 x 9
135 - 7x = 72
7x = 135 - 72
7x = 63
x = 63 : 7
x = 9
cho like
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\(280000-\left\{3^6.\left[370-\left(2^4:2^2.13\right)\right]\right\}\)
\(=280000-\left\{729.\left[370-\left(16:4.13\right)\right]\right\}\)
\(=280000-\left\{729.\left[370-52\right]\right\}\)
\(=280000-\left\{729.318\right\}\)
\(=280000-231822\)
\(=48178\)
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1/ Dùng qui tắc dấu ngoặc để tính
a/ (125 - 545) + (45 - 499 - 1125)
= 125-545 + 45-499-1125
= - (1125-125) - (545-45) - 499
= -1000 - 500 - 499
= -1500 - 499
= -1999
b/ (567 - 789) - (4567 - 2999 + 211)
= 567 - 789 - 4567 + 2999 - 211
= -(4567-567) - (789 + 211) + 2999
= -4000 - 1000 + 2999
= -5000 + 2999
= -2001
c/ -597 - (869 + 403) + (942 - 131)
= -597 - 869 - 403 + 942 - 131
= - (597 + 403) - (869 + 131) + 942
= -1000 - 1000 + 942
= -2000 + 942
= -1058
2/ Dùng qui tắc dấu ngoặc và chuyển vế để tìm x
a/ (565 - x) - 742 = -37
565 - x = -37 + 742
565 - x = 705
- x = 705 - 565
- x = 140
=> x = -140
vậy_____
b/ -569 - (213- x) = -400
- (213 - x) = -400 + 569
- (213 - x) = 169
=> 213 - x = -169
=> - x = -169 - 213
=> - x = -382
=> x = 382
vậy____
x = 15 nha
13xX=195
X=65