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\(\frac{2}{3}+\frac{5}{8}+\frac{9}{3}:\frac{4}{7}.\left(\frac{2}{6}+\frac{1}{1}\right)\)
\(=\frac{2}{3}+\frac{5}{8}+3:\frac{4}{7}.\left(\frac{1}{3}+1\right)\)
\(=\frac{2}{3}+\frac{5}{8}+\frac{21}{4}.\frac{4}{3}\)
\(=\frac{2}{3}+\frac{5}{8}+7\)
\(=\frac{16}{24}+\frac{15}{24}+7\)
\(=\frac{31}{24}+7\)
\(=\frac{19}{12}\)
Mình không biết đúng hay sai, nhưng mà kết bạn nha!
\(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}\)
\(=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\)
\(=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\right)\)
\(=1+\frac{28}{5}\)
\(=\frac{33}{5}\)
Ta có:
a) \(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{9}{15}=1+1+\frac{9}{15}=1\frac{9}{15}\)
b)\(\frac{10}{18}+\frac{4}{9}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{16}{128}+\frac{8}{128}+\frac{4}{128}+\frac{2}{128}+\frac{1}{128}\right)\)
\(=1+\frac{31}{128}=1\frac{31}{128}\)
8,96 : X =2,03 -0,5
8,96 :X = 1,53
X = 8,96 -1,53
X = 7,43
1,2 .X = 0,54 - 0,06
1,2 .X = 0,48
X = 1,2 : 0,48
X = 2,5
\(\frac{17}{5}\)= 2\(\frac{7}{5}\); \(\frac{139}{12}\)= 10\(\frac{19}{12}\); \(\frac{150}{13}\)= 11\(\frac{7}{13}\)
NHỚ TK CHO MÌNH NHÉ
\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-...+\frac{1}{101}-\frac{1}{103}\)
\(A=\frac{1}{3}-\frac{1}{103}\)
\(A=\frac{100}{309}\)
\(A=\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}+...+\frac{2}{99\times101}+\frac{2}{101\times103}\)
\(A=1\times\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}+\frac{1}{101}-\frac{1}{103}\right)\)
\(A=1\times\left(\frac{1}{3}-\frac{1}{103}\right)\)
\(A=1\times\frac{100}{309}\)
\(A=\frac{100}{309}\)
Nhớ tui ko ?
55 + 88 - 77 + 6666 - 4444 = 2288
K nhoa
#Na
2288
MÌN