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\(\frac{6^3+3.6^2+3^3}{13}=\frac{6^3+108+3^3}{13}.\)
\(=\frac{216+108+27}{13}=\frac{324+27}{13}\)
\(=\frac{351}{13}=27\)
\(\frac{6^3+3\cdot6^2+3^3}{13}=\frac{2^3\cdot3^3+3\cdot3^2\cdot2^2+3^3}{13}=\frac{3^3\left(2^3+2^2+1\right)}{13}=\frac{27\cdot13}{13}=27\)
\(\frac{8^2.4^3}{16^3}=\frac{\left(2^3\right)^2.\left(2^2\right)^3}{\left(2^4\right)^3}=\frac{2^6.2^6}{2^{12}}=1\)
\(\frac{25^2.125}{5^3.5^4}=\frac{\left(5^2\right)^2.5^3}{5^4.5^3}=\frac{5^4.5^3}{5^4.5^3}=1\)
\(\frac{8^2.4^3}{16^3}=\frac{\left(2^3\right)^2.\left(2^2\right)^3}{\left(2^4\right)^3}=\frac{2^6.2^6}{2^{12}}=1\)
\(\frac{25^2.125}{5^3.5^4}=\frac{\left(5^2\right)^2.5^3}{5^3.5^4}=\frac{5^4.5^3}{5^3.5^4}=1\)
a, (1/5)5x(3)5
=1/3125.243
=243/3125
b, (0,125)^3.512
=1/512.512
=1
c,(0,25)^4.1024
=1/256.1024
=4
2,hầu như chịu hết
a: \(=\dfrac{2^6\cdot3^3}{3^{-4}\cdot2^6}=\dfrac{3^3}{3^{-4}}=3^7\)
c: \(=5^4\cdot5^3\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{4}{100}\)
\(=5^7\cdot\left(\dfrac{2}{5}\right)^5\cdot\left(\dfrac{1}{5}\right)^2\)
\(=5^2\cdot\left(\dfrac{1}{5}\right)^2\cdot5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)
=2^12.3^5-(2^2)^6.(3^2)^2/2^12.3^6+(2^3)^4.3^5
=2^12.3^5-2^12.3^4/2^12.3^6+2^12.3^5
=2^12.3^4.(3-1)/2^12.3^4.(3^2+3)
=2/12
=1/6
CẬU XEM LẠI GIÙM MÌNH NHÉ!
\(\frac{\left(5^4-5^3\right)^3}{125^4}=\frac{\left(5^1\right)^3}{244140625}=\frac{5^3}{244140625}\)
\(=\frac{125}{244140625}=\frac{1}{1953125}\)
\(\frac{\left(625-125\right)^3}{125^4}\)=\(\frac{500^3}{\left(5^3\right)^4}\)=\(\frac{\left(4.5^3\right)^3}{5^{12}}\)=\(\frac{4^3.5^9}{5^{12}}\)=\(\frac{4^3.5^9}{5^9.5^3}\)=\(\frac{4^3}{5^3}\)=\(\frac{64}{125}\)