Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Lớp học online hay j mà lắm giáo viên thế🤔🤔 Lớp học của tri thức à?
\(\dfrac{2}{5}\) x y : \(\dfrac{7}{4}\) = \(\dfrac{7}{8}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{7}{8}\) x \(\dfrac{7}{4}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{49}{32}\)
y = \(\dfrac{49}{32}\) : \(\dfrac{2}{5}\)
y = \(\dfrac{245}{64}\)
2\(\dfrac{2}{5}\): y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}\): y x \(\dfrac{5}{4}\) = \(\dfrac{13}{5}\)
\(\dfrac{12}{5}\): y = \(\dfrac{13}{5}\): \(\dfrac{5}{4}\)
\(\dfrac{12}{5}\): y = \(\dfrac{52}{25}\)
y = \(\dfrac{12}{5}\): \(\dfrac{52}{25}\)
y = \(\dfrac{15}{13}\)
2: y \(\times\) \(\dfrac{3}{5}\) = \(\dfrac{9}{10}\)
2:y = \(\dfrac{9}{10}\) : \(\dfrac{3}{5}\)
2: y = \(\dfrac{3}{2}\)
y = 2 : \(\dfrac{3}{2}\)
y = \(\dfrac{4}{3}\)
\(\dfrac{5}{4}\) - \(\dfrac{2}{5}\) : y = 1
\(\dfrac{2}{5}\) : y = \(\dfrac{5}{4}\) - 1
\(\dfrac{2}{5}\): y = \(\dfrac{1}{4}\)
y = \(\dfrac{2}{5}\) : \(\dfrac{1}{4}\)
y = \(\dfrac{8}{5}\)
\(\dfrac{3}{4}\) \(\times\) ( \(\dfrac{7}{2}\) - y) = \(\dfrac{3}{2}\)
\(\dfrac{7}{2}\) - y = \(\dfrac{3}{2}\) : \(\dfrac{3}{4}\)
\(\dfrac{7}{2}\) - y = 2
y = \(\dfrac{7}{2}\) - 2
y = \(\dfrac{3}{2}\)
\(y+y.\frac{1}{3}.\frac{9}{2}+y.\frac{7}{2}=25\)
\(y+y.6+y.\frac{7}{2}=25\)
\(y.\left(1+6+\frac{7}{2}\right)=25\)
\(y.\frac{21}{2}=25\)
\(y=25:\frac{21}{2}\)
\(y=25.\frac{2}{21}\)
\(y=\frac{50}{21}\)
\(y.5+y.3+y+y=50\)
\(y.\left(5+3+1+1\right)=50\)
\(y.10=50\)
\(y=5\)
`(y+2/9) xx 1/5 = 7/15`
`=> y +2/9 = 7/15 : 1/5`
`=> y +2/9 = 7/15 xx 5`
`=> y +2/9= 35/15`
`=> y= 35/15 -2/9`
`=> y= 7/3 -2/9`
`=> y= 21/9-2/9`
`=> y= 19/9`
Vậy `y=19/9`
__
`yxx(12/7 +4/3) = 5/6`
`=> y xx 64/21 = 5/6`
`=> y= 5/6 : 64/21`
`=> y=5/6 xx 21/64`
`=> y=35/128`
Vậy `y= 35/128`
\(\left(y+\dfrac{2}{9}\right)\times\dfrac{1}{5}=\dfrac{7}{15}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}:\dfrac{1}{5}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}\times5\)
\(y+\dfrac{2}{9}=\dfrac{7}{3}\)
\(y=\dfrac{7}{3}-\dfrac{2}{9}\)
\(y=\dfrac{21}{9}-\dfrac{2}{9}\)
\(y=\dfrac{19}{9}\)
========================
\(y\times\left(\dfrac{12}{7}+\dfrac{4}{3}\right)=\dfrac{5}{6}\)
\(y\times\left(\dfrac{36}{21}+\dfrac{28}{21}\right)=\dfrac{5}{6}\)
\(y\times\dfrac{64}{21}=\dfrac{5}{6}\)
\(y=\dfrac{5}{6}:\dfrac{64}{21}\)
\(y=\dfrac{5}{6}\times\dfrac{21}{64}\)
\(y=\dfrac{35}{128}\)
\(\dfrac{5}{3}\times y+\dfrac{7}{3}\times y=\dfrac{7}{2}\)
y x ( \(\dfrac{5}{3}+\dfrac{7}{3}\) )= \(\dfrac{7}{2}\)
y x 4 = \(\dfrac{7}{2}\)
y = \(\dfrac{7}{2}:4\)
y = \(\dfrac{7}{8}\)