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2: 12-10x=25-30x
=>20x=13
=>x=13/20
3: \(3\left(2x+3\right)-2\left(4x-5\right)=10x+21\)
=>6x+9-8x+10=10x+21
=>10x+21=-2x+19
=>12x=-2
=>x=-1/6
4: \(\Leftrightarrow25x-15-6x+12=11-5x\)
=>19x-3=11-5x
=>24x=14
=>x=7/12
5: \(\Leftrightarrow8-12x-5+10x=4-6x\)
=>4-6x=-2x+3
=>-4x=-1
=>x=1/4
6: \(\Leftrightarrow32x-24-6+9x=13-40x\)
=>41x-30=13-40x
=>81x=43
=>x=43/81
7: \(\Leftrightarrow10x-5+20x=5x-11\)
=>30x-5=5x-11
=>25x=-6
=>x=-6/25
1: =>25x-15-6x+12=11-5x
=>19x-3=11-5x
=>24x=14
=>x=7/12
2: =>8-12x-5+10x=4-6x
=>4-6x=-2x+3
=>-4x=-1
=>x=1/4
Bài 1:
1; 5\(x\) + \(x\) = 39 - 311 : 39
\(x\).(5 + 1) = 39 - 32
\(x.6\) = 39 - 9
\(x.6\) = 30
\(x\) = 30 : 6
\(x\) = 5
Vậy \(x\) = 5
2; 5\(x\) + \(x\) = 150 : 2 + 3
\(x\).(5 + 1) = 75 + 3
\(x.6\) = 78
\(x\) = 78 : 6
\(x\) = 13
Vậy \(x=13\)
\(A.3x-\frac{3}{2}-5x+\frac{10}{3}=1\)
\(3x-\frac{3}{2}-5x=-\frac{7}{3}\)
\(3x-5x=-\frac{7}{3}+\frac{3}{2}\)
\(-2x=-\frac{5}{6}\)
\(x=-\frac{5}{6}:\left(-2\right)\)
\(x=\frac{5}{12}\)
a)5x -201 = 24.4
=> 5x - 201 = 16.4
=> 5x - 201= 64
=> 5x= 64+ 201
=> 5x= 265
=> x= 265:5
=> x= 53
b) 20+ 5x= 55:53
=>20+5x= 55:53
=>20+5x=55-3
=>20+5x=52
=>20+5x=25
=>5x=25-20
=>5x=5
=>x=5:5
=>x=1
\(5x-201=2^4.4\)
\(\Leftrightarrow5x-201=2^4.2^2\)
\(\Leftrightarrow5x-201=2^6\)
\(\Leftrightarrow5x-201=64\)
\(\Leftrightarrow5x=265\)
\(\Leftrightarrow x=53\)
`5^2 +5x = 3`
`25+5x=3`
`5x=25-3`
`5x=22`
`x=22:5`
`x=22/5`
Vậy `x=22/5`
`5^2+5x=3`
`5x=3-5^2`
`5x=3-25`
`5x=-22`
\(x=\dfrac{-22}{5}\)