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C = 39.42 + 24.61 - 39.18
= 39.(42 - 18) + 24.61
= 39.24 + 24.61
= 24.(39 + 61)
= 24.100
= 2400
515+[72+(-515)+(-32)]
=[515+(-515)]+[72+(-32)]
=0+40
=40
\(515.\left(2-128.128\right).\left(-515\right)\)
\(=515.\left(2-16384\right).\left(-515\right)\)
\(=515.\left(-16382\right).\left(-515\right)\)
\(=\left(-8436730\right).\left(-515\right)\)
\(=4344915950\)
Đặt \(A=\frac{6}{15.18}+\frac{6}{18.21}+\frac{6}{21.24}+...+\frac{6}{87.90}\)
\(A=2.\left(\frac{3}{15.18}+\frac{3}{18.21}+\frac{3}{21.24}+...+\frac{3}{87.90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+\frac{1}{21}-\frac{1}{24}+...+\frac{1}{87}-\frac{1}{90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{90}\right)\)
\(A=2.\frac{1}{18}=\frac{1}{9}\)
Vậy...
\(A=2.\left(\frac{3}{15.18}+\frac{3}{18.21}+\frac{3}{21.24}+...+\frac{3}{87.90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{18}+.......+\frac{1}{87}-\frac{1}{90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{90}\right)\)
*) (-7) - (-12) + (-5)
= [(-7) + (-5)] + 12
= (-12) + 12
= 0
*) (-2) . 32 + 7 . (-4) - (-34)
= (-2) . 9 + (-28) + 34
= -18 + (-28) + 34
= -46 + 34
= -12
*) 12 . (-82) + (-12).18
= (-12) . 82 + (-12) . 18
= (-12) . (82 + 18)
= (-12) . 100
= -1200
27x18+72x16-41x18
=3x9x9x2 +9x8x8x2 +41x9x2
=9x2x(3x9+8x8-41)
=18x(27+64-41)
=18x50
=900
chúc bn học tốt
=> y . 1/8 + y.1/3 .18 - y . 1/5 . 10 = 120
=> y . 1/8 + y . 6 - y . 2 = 120
=> y . (1/8 + 6 - 2) = 120
=> y . \(\frac{33}{8}\) = 120
=> y = 120 : \(\frac{33}{8}\) = \(\frac{320}{11}\)
Y:8 + Y : 3 x18 - Y : 5 x 10 = 120
=Y :(8+3 . 18 - 5 ) . 10 =120
=Y: 57 .10 = 120
= Y :57 =120:10
=Y:57 =12
Y = 12 . 57
Y=684
a)x+10x=20
11x=20
x=20:11
x=20/11
b)x-10x=5
-9x=5
x=5:-9
x=-5/9
\(\left(5^{15}.18-5^{15}.7\right):5^{17}\)
= \([5^{15}(18-7)]:5^{17}\)
= \([5^{15}.11]:5^{17}\)
= \(\frac{5^{15}.11}{5^{17}}=\frac{11}{5^2}=\frac{11}{25}=0,44\)
\(5^{15}\). ( 18 - 7) : \(5^{17}\) = \(5^{15}\). 11 : \(5^{17}\)
= 1678466796875 : \(5^{17}\)
= 1678466796875 : 762939453125
= 2,2