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a.=47-[45.16-25.12]:14]
=47-420:14
=47-30
=17
b.=50-[12:2+34]
=50-40
=10
c.=100-60:10
=100-6
=94
d.50-[(50-40);2+3]
=50-(10:2+3)
=50-8
=42
\(47-\left[\left(45.2^4-5^2.12\right):14\right]\) \(50-\left[\left(20-2^3\right):2+34\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\) \(=50-\left[\left(20-8\right):2+34\right]\)
\(=47-\left[\left(720-300\right):14\right]\) \(=50-\left[12:2+34\right]\)
\(=47-\left(420:14\right)=47-30\) \(=50-\left[6+34\right]=50-40\)
\(=17\) \(=10\)
a) \(47-\left[\left(45\cdot2^4-5^2\cdot12\right):14\right]\)
\(=47-\left[\left(45\cdot16-25\cdot12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]=47-30=17\)
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
a/ -3x=-60+30
=> -3x=-30
=> x=(-30):(-3)
=> x=10
Ban oi phai x,y∈Z thi moi lam dc
b/x.y=7
Vi x,y∈U(7)=(1,-1,7,-7)
Với x=1 => y=7 y=1=>x=7
x=-1 =>x=-7 y=-1=>x=-7
x=7 => x=1 y=7=>x=7
x=-7 => x=-1 y=-7=>x=-1
c/(x-1)(y+2)=-7
x-1 va y+2∈U(-7)=(1,-1,7,-7)
Bạn giải giống câu b/ nhưng x,y trái đâu nhé
d/2x-3=5x-7
=>(-3)+7=5x-2x
=>4=3x
=>x=4/3
e/(-2)2-8x=20
=>4-8x=20
=>4-20=8x
=>-16=8x
=>x=-2
f/17-(-31)+3x=2x-(-50)
=>17+31+3x=2x+50
=>49+3x=2x+50
=> 3x-2x=50-49
=> x=1
g/2y2-16=34
=>2y2=34+16
=>2y2=50
=>y2=50:2
=>y2=25=52=(-5)2
=>y=5 va y=-5
a) \(\left(-3\right)x-30=-60\)
\(\Leftrightarrow\left(-3\right)x=-60+30\)
\(\Leftrightarrow\left(-3\right)x=-30\)
\(\Leftrightarrow x=\left(-30\right):\left(-3\right)\)
\(\Leftrightarrow x=10\)
b) \(xy=7\)
\(\Rightarrow xy=1.7=7.1=\left(-1\right).\left(-7\right)=\left(-7\right).\left(-1\right)\)
Ta có bảng sau:
\(x\) | \(1\) | \(7\) | \(-1\) | \(-7\) |
\(y\) | \(7\) | \(1\) | \(-7\) | \(-1\) |
KL: Các cặp số (x; y)...
c) \(\left(x-1\right)\left(y+2\right)=-5\)
\(\Rightarrow\left(x-1\right)\left(y+2\right)=1.\left(-5\right)=\left(-5\right).1=\left(-1\right).5=5.\left(-1\right)\)
Ta có bảng sau:
\(x-1\) | \(1\) | \(-5\) | \(5\) | \(-1\) |
\(y+2\) | \(-5\) | \(1\) | \(-1\) | \(5\) |
\(x\) | \(2\) | \(-4\) | \(6\) | \(0\) |
\(y\) | \(-7\) | \(-1\) | \(-3\) | \(3\) |
KL: Các cặp số (x; y)...
d) \(2x-3=5x-7\)
\(\Leftrightarrow2x-5x=-7+3\)
\(\Leftrightarrow-3x=-4\)
\(\Leftrightarrow x=\dfrac{4}{3}\)
e) \(\left(-2\right)^2-8x=20\)
\(\Leftrightarrow4-8x=20\)
\(\Leftrightarrow8x=4-20\)
\(\Leftrightarrow8x=-16\)
\(\Leftrightarrow x=-2\)
f) \(17-\left(-31\right)+3x=2x-\left(-50\right)\)
\(\Leftrightarrow17+31+3x=2x+50\)
\(\Leftrightarrow48+3x=2x+50\)
\(\Leftrightarrow3x-2x=50-48\)
\(\Leftrightarrow x=2\)
g) \(2y^2-16=34\)
\(\Leftrightarrow2y^2=34+16\)
\(\Leftrightarrow2y^2=50\)
\(\Leftrightarrow y^2=50:2=25\)
\(\Leftrightarrow y^2=5^2=\left(-5\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}y=5\\y=-5\end{matrix}\right.\)
a. (-34) . (1 + 71) - 29
= (-34). 72 - 29
= -2448 - 29 = -2477
(thực ra có thể bạn chép sai đề vì nếu là (-34) x 29 thì số sẽ đẹp hơn)
b. 120 - 20.((-36) : 9) + 1
= 120 - 20 . (-4) +1
= 120 + 80 + 1 = 201
(máy mình k bấm đc ngoặc vuông)
\(\left(50-6x\right).18=2^3.3^2.5\)
\(\Leftrightarrow\left(50-6x\right).18=360\)
\(\Leftrightarrow50-6x=360:18\)
\(\Leftrightarrow50-6x=20\)
\(\Leftrightarrow6x=50-20\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=30:6\)
\(\Leftrightarrow x=5\)
Vậy...
( 50 - 6x ) x 18 = 360
=> 50 - 6x = 20
=> 6x = 70
=> x = 35 / 3
Vậy x = 35 / 3
( mình khoong viết hẳn phép tính , chỉ tính thôi , bạn tự suy luận nhé !!!!)
a) 47 - [(45.16 - 25.12 ) : 14]
= 47 - [ (720 - 300 ) : 14
= 47 - [ 420 : 14 ]
= 47 - 30
= 17
b) 50 - [ (20 - 8 ) : 2 + 34 ]
= 50 - [ 12 : 2 + 34 ]
= 50 - [ 6 + 34 ]
= 50 - 40
= 10
c) 100 - [ 60 : ( 15625 : 625 - 15 )
= 100 - [ 60 : ( 25 - 15 ) ]
= 100 - [ 60 : 10 ]
= 100 - 6
= 94
d)50-[(50-235)/2+3
=50-(10/2+3)
=50-8
=42
minh chi giupban duoc den do thoi ha
bai 1
20:(24-(3^2.4-34)^2)-20
=20:(24-(9.4-34)^2)-20
=20:(24-2^2)-20
=20:20-20
=-19
bai 2
a
14+5x=4^6:4^3
14+5x=4^3
14+5x=64
5x=64-14
5x=50
x=50:5
x=10
b
189-2.(93-x)=59
2..(93-x)=189-59
2.(93-x)=130
(93-x)=130:2
93-x=65
x=93-65
x=28
1) \(20:\left[24-\left(3^2.4-34\right)^2\right]-20\)
\(=20:\left[24-\left(9.4-34\right)^2\right]-20\)
\(=20:\left[24-4\right]-20\)
\(=20:20-20\)
\(=1-20\)
\(=-19\)
2)a.\(14+5x=4^6:4^3\)
\(14+5x=64\)
\(5x=64-14\)
\(5x=50\)
\(\Rightarrow x=10\)
b) 189-2(93-x)=59
2(93-x) =189-59
2(93-x) =130
93-x =130:2
93-x =65
x =93-65
x =28
Học tốt nha!!!
50 - [ ( 20 - 23 ) : 2 + 34]
= 50 - [ ( 20 - 8 ) : 2 + 34 ]
= 50 - [ 12 : 2 + 34 ]
= 50 - [ 6 + 34 ]
= 50 - 40
=10.
\(50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right):2+34\right]\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]=50-40=10\)