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13 tháng 9 2017
a)1/3+1/4+2/3+3/4
=(1/3+2/3)+(1/4+3/4)
=1+1
=2.
b)1/2+1/3-1/5+1/6
=(1/2+1/3+1/6)-1/5
=1-1/5
=4/5
c)2/3x4/5+1/3x4/5
=4/5x(2/3+1/3)
=4/5x1
=4/5
d)2/3x4/5-1/3x4/5
=4/5x(2/3-1/3)
=4/5x1/3
=4/15
MD
2
11 tháng 6 2016
a) x* 1/5 - x* 2 * 2/15 = 4
x * 1/5 - x * 2 = 4 : 2/15
x * 15 - x * 2 = 30
x * ( 15 - 2 ) = 30
x * 13 = 30
x = 30 : 13
x = 30/13
b) ( x + x * 2 ) - 3 : 1/2 = 8
( x * 1 + x * 2 ) - 3 = 8 x 1/2
( x * 1 + x * 2 ) - 3 = 4
x * 1 + x * 2 = 4 + 3
x * 1 + x * 2 = 7
x * ( 1 + 2 ) = 7
x * 3 = 7
x = 7 : 3
x = 7/3
c)5 +( x * 1/2 - 4 ) = 15
x * 1/2 - 4 = 15 - 5
x * 1/2 - 4 = 10
x * 1/2 = 10 + 4
x * 1/2 = 14
x = 14 : 1/2
x = 7
TB
11 tháng 6 2016
a)x*1/5-x*2*2/15=4
x*1/5-x*4/15=4
x*1/5-4/15=4
x*(-1/15)=4
x=4:-1/15
x=-60
20 tháng 6 2015
a.\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{2015}\right)=\frac{1}{2}.\frac{2}{3}...\frac{2014}{2015}=\frac{1.2.3...2014}{2.3...2015}=\frac{1}{2015}\)
b.\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{128}-\frac{1}{256}=1-\frac{1}{256}=\frac{255}{256}\)
c.\(\frac{5}{2}+\frac{5}{4}+\frac{5}{8}+...+\frac{5}{256}=5\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\right)=5.\frac{255}{256}=\frac{1275}{256}\)
d.14,35+(13,7-13,6).1=14,35+0,1.1=14,35+0,1=14,45
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
21 tháng 9 2024
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
21 tháng 9 2024
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
CC
1
VD
13 tháng 8 2018
\(\frac{1}{2}\times\frac{1}{2}+\frac{1}{2}\times\frac{1}{3}+\frac{1}{3}\times\frac{1}{4}+\frac{1}{4}\times\frac{1}{5}+\frac{1}{5}\times\frac{1}{6}\)
\(=\frac{1}{2\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)
\(=\frac{1}{2}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}\)
\(=\frac{1}{3}\)
\(5=\left(x+\frac{1}{2}\right):\frac{1}{4}\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{1}{4}.5\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{5}{4}\)
\(\Leftrightarrow x=\frac{3}{4}\)
Vậy ...........
\(5=\left(x+\frac{1}{2}\right)\text{ : }\frac{1}{4}\)
\(x+\frac{1}{2}=5\cdot\frac{1}{4}\)
\(x+\frac{1}{2}=\frac{5}{4}\)
\(x=\frac{5}{4}-\frac{1}{2}\)
\(x=\frac{3}{4}\)