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Bài giải:
Câu 1: a, \(\left(-2\right).4.5.38.\left(-25\right)\)
\(=\left[\left(-2\right).5\right].\left[4.\left(-25\right)\right].38\)
\(=\left(-10\right).\left(-100\right).38\)
\(=1000.38=38000\)
b,\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}\)
\(=\left(\frac{1}{3}+\frac{3}{8}\right)-\frac{7}{12}\)
\(=\frac{17}{24}-\frac{7}{12}=\frac{1}{8}\)
c, \(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{3}{2}\)
Câu 2: a, \(x-\frac{2}{5}=0,24\)
\(x-0,4=0,24\)
\(x=0,24+0,4\)
\(\Rightarrow x=0,64\left(\frac{16}{25}\right)\)
b,\(\frac{2}{3}.x+\frac{1}{12}=\frac{1}{10}\)
\(\frac{2}{3}.x=\frac{1}{10}-\frac{1}{12}\)
\(\frac{2}{3}.x=\frac{1}{60}\)
\(x=\frac{1}{60}:\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{40}\)
c, \(\left(3\frac{1}{2}-2x\right).1\frac{1}{3}=7\frac{1}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{11}{2}\)
\(2x=\frac{7}{2}-\frac{11}{2}\)
\(2x=-2\)
\(\Rightarrow x=-2:2\)
\(x=-1\)
Hỗn số (3 1/3 + 2,5) : ( hỗn số 3 1/6 - hỗn số 4 1/5 ) - 11/31
=(10/3+2,5)/(19/6-21/5)-11/31
=(17,5/3)/(-31/30)-11/31
=-175/31-11/31
=-186/31
=-6
\(2\frac{3}{12}:2.5-0.25\frac{4}{5}-\frac{2}{5}\)
đúng đề chưa
\(4\dfrac{3}{4}+\left(-0,37\right)+\dfrac{1}{8}+\left(-2,5\right)+5\dfrac{1}{2}\)
\(=\dfrac{19}{4}-0,37+\dfrac{1}{8}-\dfrac{5}{2}+\dfrac{11}{2}\)
=\(\left(\dfrac{19}{4}+\dfrac{1}{8}\right)+\left(-\dfrac{5}{2}+\dfrac{11}{2}\right)-0,37\)
=\(\dfrac{39}{8}+3-0,37\)
= 4,875+3-0,37
= 7,505
a, 64 . 23 + 37 . 23 - 23
= 23. (64 + 37 - 1)
= 23 . 100
=2300
b, 33,76 + 19,52 + 6,24
= (33,76 + 6,24) + 19,52
= 40 + 19,52
= 59,52
c, 38/11 + (16/13 + 6/11)
= 38/11 + 16/13 + 6/11
= (38/11 + 6/11) + 16/13
= 4 + 16/13
= 52/13 + 16/13
= 68/13
d, 3/4 : 3/5 - 1/5
= 3/4 . 5/3 - 1/5
= 5/4 - 1/5
= 25/20 - 4/20
= 21/20
e, \(5\frac{3}{4}\div\frac{12}{13}+6\frac{1}{4}\div\frac{12}{13}\)
\(=\frac{23}{4}\cdot\frac{13}{12}+\frac{25}{4}\cdot\frac{13}{12}\)
\(=\frac{13}{12}\cdot\left(\frac{23}{4}+\frac{25}{4}\right)\)
\(=\frac{13}{12}\cdot12=13\)
f, S = 1 + 2 + 3 + 4 + ... + 99 + 100
Số số hạng của S là :
(100 - 1) : 1 + 1 = 100 (số hạng)
Tổng của S là :
(1 + 100) . 100 : 2 = 5050
Vậy S = 5050
Dấu " . " là dấu nhân nhé :D
( 5 + 3 ) + ( \(\frac{2}{12}\) + \(\frac{3}{12}\) )
= 8 + \(\frac{5}{12}\)
= 8\(\frac{5}{12}\)
\(\text{Ta có:}\)
\(5\frac{2}{12}+3\frac{3}{12}\)
\(=5+\frac{2}{12}+3+\frac{3}{12}\)
\(=\left(5+3\right)+\left(\frac{2}{12}+\frac{3}{12}\right)\)
\(=8+\frac{5}{12}\)
\(=8\frac{5}{12}\)