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\(129-5\left[29\left(6-1^2\right)\right]\)
\(=129-5\left[29\left(6-1\right)\right]\)
\(=129-5\left(29\cdot5\right)\)
\(=129-5\cdot145\)
\(=129-725\)
\(=-596\)
mn giải đáp án ra giúp mik nha,mik cảm ơn nhiều!Thank you!
Bài 5:Thực hiện phép tính:
a)-(-129)+315+(-129)-215
b)(-25).(-38).8.(-125).(-4)
c)12.(35+18)-18.(12-35)
a. -(-129) + 315 + (-129) - 215
= 129 + (-129) + (315 - 215)
= 0 + 100
= 100
b. (-25).(-38).8.(-125).(-4)
= [ (-25).(-4) ] . [ (-125).8 ] . (-38)
= 100 . (-1000) . (-38)
= 3800000
c. 12.(35 + 18) - 18.(12 - 35)
= 12.35 + 12.18 - 18.12 + 18.35
= 12.35 + 18.35 + 12.18 - 18.12
= 35 . (12 + 18) + 0
= 35 . 30
= 1050
\(129-3.\left[\left(x+1\right):4-5\right]=6\)
\(\Rightarrow3\left[\left(x+1\right):4-5\right]=123\)
\(\Rightarrow\left(x+1\right):4-5=123:3\)
\(\Rightarrow\left(x+1\right):4-5=41\)
\(\Rightarrow\left(x+1\right):4=41+5\)
\(\Rightarrow\left(x+1\right):4=46\)
\(\Rightarrow x+1=46.4\)
\(\Rightarrow x+1=184\)
\(\Rightarrow x=183\)
129 -5[29-(6-1) ^2]
=129 - 5[29- 5^2]
= 129 -5[ 29-25]
=129 - 5 × 4
=129 - 20
=109
Ta có: \(129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\cdot4\)
=109
a) $34-29+(-14)+129-(-114)$
$=34-29-14+129+114$
$=34+(129-29)+(114-14)$
$=34+100+100$
$=234$
b) $27\cdot(-35)+(-27)\cdot64-27$
$=(-27)\cdot35+(-27)\cdot64+(-27)\cdot1$
$=(-27)\cdot(35+64+1)$
$=(-27)\cdot(99+1)$
$=(-27)\cdot100$
$=-2700$
c) $160-(4\cdot5^2-3\cdot2^3)\cdot2-(-12)$
$=160-(4\cdot25-3\cdot8)\cdot2+12$
$=160-(100-24)\cdot2+12$
$=160-76\cdot2+12$
$=160-152+12$
$=160-(152-12)$
$=160-140$
$=20$
a, 34 - 29 + (-14) + 129 - (-114)
= 34 + (129 - 29) + (114 - 14)
= 34 + 100 + 100
= 234
b, 27.(-35) + (-27).64 - 27
= (-27).(35 + 64 + 1)
= - 27 . 100
= - 2700
c, 160 - (4.52 - 3.23).2 - (-12)
= 160 - (4.25 - 3.8).2 + 12
= 160 - (100 - 24).2 + 12
= 160 - 76.2 + 12
= 160 - 152 + 12
= 8 + 12
= 20
5 - ( 12 - x ) = 129 - ( 6 + 129 )
5 - 12 + x = 129 - 6 - 129
( -7 ) + x = ( -6)
x = ( - 6 ) + 7
x = 1
Vậy x = 1
5-(12-x)=129-(6+129)
5-(12-x)=129-135
5-(12-x)=-6
12-x =5-(-6)
12-x=11
x=12-11
x=1