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\(4\left(x+41\right)-200=400\)
\(4x+164=400+200\)
\(4x+164=600\)
\(4x=600-164\)
\(4x=436\)
\(x=109\)
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\(4\left(x+41\right)-200=400\)
\(4\left(x+41\right)=400+200\)
\(4\left(x+41\right)=600\)
\(x+41=600:4\)
\(x+41=650\)
\(x=650-41\)
\(x=609\left(TM\right)\)
Vậy \(x=609\) là giá trị cần tìm
![](https://rs.olm.vn/images/avt/0.png?1311)
4(x+41)=400
=>x+44=400 : 4
x+41=100
=> x=100-41
x=59
\(4\left(x+41\right)=400\)
\(\Rightarrow4x+164=400\)
\(\Rightarrow4x=400-164=236\)
\(\Rightarrow x=236:4=59\)
k mk nhé,sau đó mk sẽ kb vs bn
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (-4).(x+41)=400
=> x + 41 = 400 : ( -4)
=> x + 41 = -100
=> x = -100 - 41
=> x = -141
b) 9-25=(7-x)-(25+7)
=> -16 = ( 7 - x ) - 32
=> 7 - x = 32 - ( -16 )
=> 7 - x = 48
=> x = 7 - 48
=> x = -41
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1)\(2x-5=-17\)
\(\Leftrightarrow2x=-12\)
\(\Leftrightarrow x=-6\)
2) \(4\left(x+41\right)=400\)
\(\Leftrightarrow x+41=100\)
\(\Leftrightarrow x=59\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đề bài : Tìm số nguyên x
2x-5=-17
2x=(-17)+5
2x=-12
x=(-12):2
x=-6
Vậy x=-6.
4(x+41)=400
x+41=400:4
x+41=100
x=100-41
x=59
Vậy x=59
219-7(x+1)=102
219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
x=17-1
x=16
Vậy x=16.
![](https://rs.olm.vn/images/avt/0.png?1311)
1. 4(x+41)=400
<=>x+41=100
<=>x=59
2.11(x-9)=77
<=>x-9=7
<=>x=16
3.5(x-9)=350
<=>x-9=70
<=>x=79
4.2x-49=3.32
<=>2x=3.32+49
<=>2x=76
<=>x=38
5.200-(2x+6)=43
<=>200-2x-6=64
<=>-2x=64-200+6
<=>-2x=-130
<=>x=65
1) 4(x+41)=400
x+41=400:4
x+41=100
x=100-41
x=59
2) 11(x-9)=77
x-9=77:11
x-9=7
x=7+9
x=16
3) 5(x-9)=350
x-9=350:5
x-9=70
x=70+9
x=79
4) 2x-49=3.3\(^2\)
2x-49=3\(^3\)
2x-49=27
2x=27+49
2x=76
x=76:2
x=38
5, 200-(2x+6)=4\(^3\)
200-(2x+6)=64
2x+6=200-64
2x+6=136
2x=136-6
2x=130
x=130:2
x=65
đúng nha
thanks bn nhìu
giups minhf voiws ban oi
nếu là tìm x thì giải như sau:
4.(x+41)=400
x+41=400:4
x+41=100
x=100-41
x=59
vậy x=59