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(6x-20)-(4x-8)+12=(-2)^3
<=>6x-20-4x+8+12=-8
<=>2x=-8
<=>x=-4
Vậy x=-4
chúc hok tốt

(3.4x-5.122):13 = 12
3.4x-5.144 = 156
432.4x-5 = 156
4x-5 = 13/36
4x : 45 = 13/36
4x = 13/36864
...

\(4x^3+12=120\)
\(\Rightarrow4x^3=108\)
\(\Rightarrow x^3=108:4=27=3^3\)
\(\Rightarrow x=3\)
\(3.2^x-3=45\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16=2^4\Rightarrow x=4\)
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Rightarrow\left(30x+40\right):x=50\)
\(\Rightarrow30x:x+40:x=50\)
\(\Rightarrow30+40:x=50\)
\(\Rightarrow40:x=20\Rightarrow x=2\)

Tìm x, biết:
a) 4x3+12=120
=>4x3=120-12
=>4x3=108
=>x3=108:4
=>x3=27
=>x3=33
=>x=3
b) 3.2x-3=45
=>3.(2x-1)=45
=>2x-1=45:3
=>2x-1=15
=>2x=15+1
=>2x=16
=>2x=24
=>x=4
4x^3+12=120
4x^3 =120-12
4x^3 =108
x^3 =108:4
x^3 =27
x^3 =3^3
\(\Rightarrow\)x=3
3.2^x-3=45
3.2^x=45+3
3.2^x=48
2^x=48:3
2^x=16
2^x=2^4
\(\Rightarrow\)x=4
tick mình nha bạn

2.3x = 10.312 + 8.312
2.3x = (10+8).312
2.3x = 18.312
2.3x = 2.32.312
2.3x = 2.314
=> x = 14
2.3^x=10.3^12+8.3^12
2.3^x=3^12.(10+8)
2.3^x=3^12.18
2.3^x=3^12.(3^2+3^2)
2.3^x=3^12.3^2+3^12.3^2
2.3^x=3^15+3^15
2.3^x=3^15.2
=> 3^x=3^15
=> x=15

a)120-3(x+4)=23
=>3(x+4)=120-23
=>3(x+4)=97
=>x+4=97:3
=>x+4=\(\frac{97}{3}\)
=>x=\(\frac{97}{3}\)-4
=>x=\(\frac{85}{3}\)
Vậy x=\(\frac{85}{3}\)
b)[(4x+28).3+55]:5=35
=>(4x+28).3+55=35.5
=>(4x+28).3+55=175
=>(4x+28).3=175-55
=>(4x+28).3=120
=>4x+28=120:3
=>4x+28=40
=>4x=40-28
=>4x=12
=>x=12:4
=>x=3
Vậyx= 3
c)\((12x-4^3).8^3=4.8^4\)
=>\(12x-64=4.8^4:8^3\)
=>12x-64=4.8
=>12x-64=32
=>12x=96
=>x=96:12
=>x=8
Vậy x=8
d)720:[41-(2x-5)]=23.5
=>720:[41-2x-5)]=40
=>41-(2x-5)=720:40
=>41-(2x-5)=18
=>2x-5=41-18
=>2x-5=23
=>2x=23+5
=>2x=28
=>x=28:;2
=>x=14
Vậy x=14
a, 120 - 3 [ x+4]=23
3 [x+4]= 120-23 = 97
3x = 97-4
3x= 93
x= 93:3
x=31
em bt làm mỗi bài này thui mà ko bt đúng ko

a.20-[7(x-3)+4]=2
[7(x-3)+4]=18
7(x-3)=18-4
7(x-3)=14
x-3=2
x=5
Vậy x=5
b.4x3+12=120
4x3=200-12
4x3=188
x3=188:4
x3=47
\(\Rightarrow x\in\notin\)
c.3 . 2x-3=45
2x-3=45:3
2x-3=15
2x=15+3
2x=18
\(\Rightarrow x\in\notin\)

64 : 2x+5 + 11 = 12
64 : 2x+5 = 1
2x+5 = 64 = 26
=> x + 5 = 6
x = 1

Bài 1:
a, 96 \(⋮x=>x\inư\left(96\right)\)
b, \(2^x.15+2^x.17=4^{30}\)
\(2^x\left(15+17\right)=4^{30}\)
\(2^x.32=4^{30}\)
\(2^x.2^5=2^{60}\)
\(2^x=2^{60}:2^5\)
\(2^x=2^{55}\)
=> x = 55
\(4x^2+12=120\)
\(\Leftrightarrow4x^2=108\)
\(\Leftrightarrow x^2=27\)
\(\Leftrightarrow x=\pm\sqrt{27}\)