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`#040911`
`175 - 4x^3 = 67`
`\Rightarrow 4x^3 = 175 - 67`
`\Rightarrow 4x^3 =108`
`\Rightarrow x^3 = 108 \div 4`
`\Rightarrow x^3 = 27`
`\Rightarrow x3 = 3^3`
`\Rightarrow x = 3`
Vậy, `x = 3.`
a)
\(5x-3=4x+6\)
\(\Rightarrow5x-4x=6+3\)
=> x = 9
Vậy x = 9
b)
\(7-2x=4x-67\)
\(\Rightarrow7+67=4x+2x\)
\(\Rightarrow6x=74\)
\(\Rightarrow x=\frac{37}{2}\)
Vậy x = 37 / 2
*5x -3 = 4x + 6
5x - 4x = 6 + 3
=> x = 9
Vậy x = 9.
*7 - 2x = 4x - 67
7 + 67 = 4x + 2x
74 = 6x
=> x = 37/3
Vậy x = 37/3.
a, 2x+15=67-(-18) b, 4x-12=3x-(-7) c, 2|x-1|+3=13
2x+15=67+18 4x-12=3x+7 2|x-1| = 13-3
2x+15= 85 4x-3x = 12+7 2|x-1| =10
2x =85-15 x = 19 |x-1| = 10:2
2x = 70 |x-1| = 5
x = 70:2 +) Nếu x=5 thì x-1=5 suy ra x=6
x = 35 +) Nếu x=-5 thì x-1= -5 suy ra x= -4
a, 2x + 15 = 67-(-18)
=> 2x + 15 = 67 + 18
=> 2x = 85 - 15
=> 2x = 70
=> x = 35
b, 4x - 12 = 3x-(-7)
=> 4x - 12 = 3x + 7
=> 4x - 3x = 7 + 12
=> x = 19
c, 2|x - 1| + 3 = 13
=> 2|x - 1| = 10
=> |x - 1| = 5
=> x - 1 = 5 hoặc x - 1 = -5
=> x = 6 hoặc x = -4
\(\left(123-4x\right)-67=8\)
\(\Rightarrow123-4x=75\)
\(\Rightarrow4x=48\)
\(\Rightarrow x=12\)
a) (123-4x)-67=8
123-4x =8+67
123-4x =73
4x =123-73
4x =60
x =60:4
x =15
a)(123-4x)-67= 8 =(123-4x) =8+67 = 4x =123-75 4x=48 x=48:4 x=12
\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)+\frac{1}{3}\)
\(=\left(-1\right)+1+\frac{1}{3}\)
\(=\frac{1}{3}\)
\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\\ =\left(\dfrac{103}{201}+\dfrac{13}{41}\right)-\dfrac{1363}{2747}\\ =\dfrac{6836}{8241}-\dfrac{1363}{2747}\\ =\dfrac{1}{3}\)
\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\\ =\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\\ =\dfrac{1}{3}+\left(\dfrac{12}{67}-\dfrac{79}{67}\right)+\left(\dfrac{13}{41}+\dfrac{28}{41}\right)\\ =\dfrac{1}{3}-\dfrac{67}{67}+\dfrac{41}{41}\\ =\dfrac{1}{3}-1+1\\ =\dfrac{1}{3}\)
4x-1+3=67
4x-1= 67-3
4x-1= 64
4x-1=43
\(\Rightarrow\)x-1=3
\(\Rightarrow\)x=3+1
\(\Rightarrow\)x=4
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