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\(\left(4x-1\right)^3=9^3\)
\(\Rightarrow4x-1=9\)
\(4x=10\)
\(x=\frac{5}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(2^x-15=17\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
2) \(\left(7x-11\right)^3=25\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=825\)
\(\Leftrightarrow7x-11=\sqrt[3]{825}\)
\(\Leftrightarrow7x=11+\sqrt[3]{825}\)
\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)
3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)
\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
4) \(4x+5\left(x+3\right)=105\)
\(\Leftrightarrow9x+15=105\)
\(\Leftrightarrow9x=90\)
\(\Rightarrow x=10\)
5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)
\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)
\(\Leftrightarrow3x+4=34\)
\(\Leftrightarrow3x=30\)
\(\Rightarrow x=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Nguyễn Khánh Phương
Bài 1 :
a) 149 - ( 35 : x + 3 ) x 17 = 13
( 35 : x + 3 ) x 17 = 149 - 13
( 35 : x + 3 ) x 17 = 136
( 35 : x + 3 ) = 136 : 17
( 35 : x + 3 ) = 8
35 - x = 8 - 3
35 - x = 5
x = 35 - 5
x = 30
b, 121 : 11 − ( 4x + 5 ) : 3 = 4
11 − 4x + 5 : 3 = 4
4x + 5 : 3 = 11 − 4
4x + 5 : 3 = 7
4x + 5 = 7 x 3
4x + 5 = 21
4x = 21 − 5
4x = 16
x = 16 : 4
x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x-2=2\left(x-1\right)\)
\(2xy-4x=2x\left(y-2\right)\)
\(2^8-2^7=2^7\left(2-1\right)=2^7\)
\(a^{2019}-a^{2017}=a^{2017}\left(a^2-1\right)\)
\(\left(x+1\right)^4-\left(x+1\right)^3=\left(x+1\right)^3\left(x+1-1\right)=\left(x+1\right)^3x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^x:2^5=1\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(7^2-\left(13+4x\right)=5.2^3\)
\(\Rightarrow13+4x=5.2^3+7^2=89\)
\(\Rightarrow4x=89-13=76\)
\(\Rightarrow x=19\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(318-5\left(x-64\right)=103\)
\(\Rightarrow5\left(x-64\right)=318-103\)
\(\Rightarrow5\left(x-64\right)=215\)
\(\Rightarrow x-64=43\)
\(\Rightarrow x=43+64\)
\(\Rightarrow x=107\)
_____________
\(4^x\cdot5+216=296\)
\(\Rightarrow4^x\cdot5=296-216\)
\(\Rightarrow4^x\cdot5-80\)
\(\Rightarrow4^x=16\)
\(\Rightarrow4^x=4^2\)
\(\Rightarrow x=2\)
___________
\(376-6^x:3=364\)
\(\Rightarrow6^x:3=376-364\)
\(\Rightarrow6^x:3=12\)
\(\Rightarrow6^x=36\)
\(\Rightarrow6^x=6^2\)
\(\Rightarrow x=2\)
___________
\(\left(4x-1\right)^2=121\)
\(\Rightarrow\left(4x-1\right)^2=11^2\)
\(\Rightarrow\left[{}\begin{matrix}4x-1=11\\4x-1=-11\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}4x=12\\4x=-10\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{2}\end{matrix}\right.\)
(4x-1)=3 mũ 2
4x-1 = 9
4x = 9 + 1
4x = 10
x = 10:4
x = 2,5
HT và $$$
---> 4x - 1 = 9
---> 4x = 10
---> x = 5/2
xin tiick