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A, \(\dfrac{7}{9}\) = \(\dfrac{7\cdot5}{9\cdot5}\) = \(\dfrac{35}{45}\) \(\dfrac{3}{5}\) = \(\dfrac{3\cdot9}{5\cdot9}\) = \(\dfrac{27}{45}\)
Vậy \(\dfrac{7}{9}\) > \(\dfrac{3}{5}\)
B, \(\dfrac{3}{4}\) = \(\dfrac{3\cdot6}{4\cdot6}\) = \(\dfrac{18}{24}\) \(\dfrac{5}{6}\) = \(\dfrac{5\cdot4}{6\cdot4}\) = \(\dfrac{20}{24}\)
Vậy \(\dfrac{3}{4}\) < \(\dfrac{5}{6}\)
C, \(\dfrac{1}{4}\) = \(\dfrac{1\cdot3}{4\cdot3}\) = \(\dfrac{3}{12}\) \(\dfrac{2}{3}\) = \(\dfrac{2\cdot4}{3\cdot4}\) = \(\dfrac{8}{12}\)
Vậy \(\dfrac{1}{4}\) < \(\dfrac{2}{3}\)
D, \(\dfrac{8}{9}\) = \(\dfrac{8\cdot2}{9\cdot2}\) = \(\dfrac{16}{18}\) \(\dfrac{1}{2}\) = \(\dfrac{1\cdot9}{2\cdot9}\) = \(\dfrac{9}{18}\)
Vậy \(\dfrac{8}{9}\) > \(\dfrac{1}{2}\)
\(\cdot\) là dấu nhân
Gọi số đó là x . ta có :
x - 2,1 + 4,5 = 10,9
x - 2,1 = 10,9 - 4,5
x - 2,1 = 6,4
x = 6,4 +2,1
x =8,5
A.1/2=2/4=3/6=4/8
B.1/4=2/8=3/12=5/20
C.2/5=8/20=10/25
k mình nhé
a)1/2,3/4,5/6,5/5
b)1/3,3/8,1/2
c)1/8,1/7,1/6,1/3
d)1/2,2/3,3/4,4/5,5/6
A. \(\frac{1}{2}=\frac{2}{4}=\frac{4}{8}=\frac{3}{6}\)
B> \(\frac{1}{4}=\frac{2}{8}=\frac{3}{12}=\frac{5}{20}\)
C. \(\frac{2}{5}=\frac{8}{20}=\frac{10}{25}\)
Câu 2.
a\(\frac{5}{7}=\frac{10}{14}=\frac{15}{21}=\frac{20}{28}=\frac{25}{35}\)b.. \(\frac{4}{9}=\frac{8}{18}=\frac{12}{27}=\frac{16}{36}=\frac{20}{45}=\frac{24}{54}\)