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\(x\cdot\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{1}{45}\right)=88\)
\(x\cdot\left(\frac{2}{\frac{2.3}{2}}+\frac{2}{\frac{3.4}{2}}+\frac{2}{\frac{4.5}{2}}+....+\frac{2}{\frac{9.10}{2}}\right)=88\)
\(x\cdot\left[2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\right]=88\)
\(x\cdot\left[2\left(\frac{1}{2}-\frac{1}{10}\right)\right]=88\)
\(x\cdot\left(2\cdot\frac{2}{5}\right)=88\)
\(x\cdot\frac{4}{5}=88\)
\(\Rightarrow x=88\div\frac{4}{5}=110\)
Vậy x = 110
a) \(\frac{28\times7-45\times7+7\times18}{45\times14}\)
\(=\frac{7\left(28-45+7\right)}{45\times14}\)
\(=\frac{7\times\left(-10\right)}{45\times14}=\frac{-1}{9}\)
b) \(\frac{12.3-2.6}{4.5.6}\)
\(=\frac{2.6.3-2.6}{4.5.6}\)
\(=\frac{2.6\left(3-1\right)}{2.2.5.6}\)
\(=\frac{2.6.2}{2.2.5.6}\)\(=\frac{1}{5}\)
a, (23. x + 45) : 6 = 19 b , (x : 23 + 45) . 67 = 6911
(23 . x + 45) = 19 x 6 ( x : 23 + 45) = 6911 : 67
(23 . x + 45) = 114 ( x : 23 + 45) = 6911/67
23 . x = 114 - 45 x : 23 = 6911/67 - 45
23 . x = 69 x : 23 = 3896/67
x = 69 : 23 x = 3896/67 x 23
x =3 x = 89608/67
c, x + (x + 1) + (x + 2) + ... + (x + 2011) = 2025078
x + x + x + ... + x + (1 + 2 + ... + 2011) = 2025078
2012x + 2024072 = 2025078
2012x = 2025078 - 2024072
2012x = 1006
=> x = 1/2 = 0,5
a) (23.x+45):6 = 19
23.x+45 = 19 . 6
23.x+45 = 114
23x = 114 - 45
23x = 69
x = 63 : 23
x = 3
b) (x:23+45) . 67 = 6911
x:23+45 = 6911 : 67
x:23+45 = \(\frac{6911}{67}\)
x:23 = \(\frac{6911}{67}-45\)
x:23 = \(\frac{3896}{67}\)
x = \(\frac{3896}{67}.23\)
x = \(\frac{89608}{67}\)
c) x + ( x + 1 ) + ( x + 2 ) + .....+ (x + 2011) = 2025078
=> có 2011 cặp và 1 số x
=> (x+x+x+...+x) + ( 1 + 2 + ... + 2011 ) = 2025078
=> 2012x + 2023066 = 2025078
2012x = 2025078 - 2023066
2012x = 2012
x = 2012 : 2012
x = 1
a]={23;24;25;26....;35}
b]={4;8;14;...}
c]{4}
Tim x thuoc N=thi ko biet nha!
1/6.x = 45% - 4,75
1/6. x = -4,3
x = -4/3 : 1/6
x=-129/5
hay