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a) \(x+\frac{18}{5}=\frac{43}{4}\)
\(x=\frac{43}{4}-\frac{18}{5}\)
\(x=\frac{143}{20}=7,15\)
b) \(x-4,2=42,19\)
\(x=42,19+4,2\)
\(x=46,39\)

\(6\frac{1}{7}x1\frac{6}{43}\)
= \(\frac{43}{7}x\frac{49}{43}\)
= \(\frac{49}{7}\)
= 7

a) 8/6 > 1
42/43 < 1
=>8/6 > 42/43
b) 17/18 < 1
4/3 > 1
=> 17/18 < 4/3

10:5/3= 10x3/5=6
5/3:10=5/3x1/10=1/6
12/35:35/25=12/35x25/35=300/1225=12/49
19/17:76/51=19/17x 51/76= 3/4
\(10:\frac{5}{3}=10x\frac{3}{5}=\frac{30}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}x\frac{1}{10}=\frac{5}{30}=\frac{1}{6}\)
\(\frac{12}{35}:\frac{35}{25}=\frac{12}{35}x\frac{25}{35}=\frac{12}{35}x\frac{5}{7}=\frac{12}{7}x\frac{1}{7}=\frac{12}{49}\)
\(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}x\frac{51}{76}=\frac{1}{1}x\frac{3}{4}=\frac{3}{4}\)
Thank you! Chúc bạn học tốt!

Ta thấy: 1/41+1/42+…+1/60<1/40.20=1/2
1/61+1/62+…+1/80<1/60.20=1/3
=>1/41+1/42+…+1/80<1/2+1/3=5/6
Vậy \(\frac{1}{41}+\frac{1}{42}+...+\frac{1}{80}<\frac{5}{6}\)
\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+....+\frac{1}{80}>\frac{40}{41}>\frac{5}{6}\)
Đang cần gấp
\(\frac{43}{18}-\left(1+\frac56\right)\)
\(=\frac{43}{18}-\frac{11}{6}\)
\(=\frac{43}{18}-\frac{33}{18}=\frac{10}{18}=\frac59\)