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a. (9x + 2).3 = 60
<=> 9x + 2 = 20
<=> 9x = 18
<=> x = 2
b. 71 + (26 - 3x):5 = 75
<=> (26 - 3x) : 5 = 4
<=> 26 - 3x = 4/5
<=> 3x = 26 - 4/5
<=> x = 42/5
c. 2x = 32
<=> 2x = 25
<=> x = 5
d. (x - 6)2 = 9
<=> x - 6 = 3
<=> x = 9
a) \(\left(9x+2\right)\times3=60\)
\(\Rightarrow9x+2=60:3\)
\(\Rightarrow9x+2=20\)
\(\Rightarrow9x=20-2\)
\(\Rightarrow9x=18\)
\(\Rightarrow x=18:9\)
\(\Rightarrow x=2\)
Vậy x = 2
b) \(71+\left(26-3x\right):5=75\)
\(\Rightarrow\left(26-3x\right):5=75-71\)
\(\Rightarrow\left(26-3x\right):5=4\)
\(\Rightarrow26-3x=4\times5\)
\(\Rightarrow26-3x=20\)
\(\Rightarrow3x=26-20\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=6:3\)
\(\Rightarrow x=2\)
Vậy x = 2
c) \(2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
d) \(\left(x-6\right)^2=9\)
\(\Rightarrow\orbr{\begin{cases}x-6=3\\x-6=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=9\\x=3\end{cases}}\)
Vậy x = 9 hoặc x = 3
_Chúc bạn học tốt_
d)
\(152-3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=-4\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=152-\left(-4\right)\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=156\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=156\div3\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=52\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=52-42\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=10\)
\(\Rightarrow2\left(36\div x^2+7\right)=32-10\)
\(\Rightarrow2\left(36\div x^2+7\right)=22\)
\(\Rightarrow36\div x^2+7=22\div2\)
\(\Rightarrow36\div x^2+7=11\)
\(\Rightarrow36\div x^2=11-7\)
\(\Rightarrow36\div x^2=4\)
\(\Rightarrow x^2=36\div4\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x^2=3^2\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
-43. 71+ 32 . 29 - 13. (- 32)=-3200
-64.71+32.29-13.(-32)
=(71+29).(64-13).32-(-32)
=100.51.0
=5100.0
=0