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1300
ai bấm sai thì cứ bấm
nhưng mình đúng thì vẫn là thật
\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)
1)
\(45\left(13+78\right)+9\left(87+22\right)5\)
\(=45\left(13+78\right)+45\left(87+22\right)\)
\(=45\left(13+78+87+22\right)\)
\(=45\left[\left(87+13\right)+\left(78+22\right)\right]\)
\(=45\left[100+100\right]\)
\(=45.200\)
\(=9000\)
2)
\(43+37+93.43+57.61+69.57\)
\(=43\left(37+93\right)+57.\left(61+69\right)\)
\(=43.130+57.130\)
\(=130\left(43+57\right)\)
\(=130.100\)
=13000
42 + 43 + 44 + 45 - 32 - 33 - 34 - 35
= (42 - 32)+(43 - 33)+(44 - 34)+(45 - 35)
= 10+10+10+10
= 40
(64+65+66+67+68) - (54+55+56+57+58)
= 64+65+66+67+68 - 54-55-56-57-58
= (64 - 54)+(65 - 55) +(66 - 56) + (67- 57) + (68 -58)
= 10+10+10+10+10
= 50
a) \(\dfrac{43}{47}=\dfrac{47-4}{47}=\dfrac{47}{47}-\dfrac{4}{47}=1-\dfrac{4}{47}\)
\(\dfrac{53}{57}=\dfrac{57-4}{57}=\dfrac{57}{57}-\dfrac{4}{57}=1-\dfrac{4}{57}\)
Vì \(\dfrac{4}{47}>\dfrac{4}{57}\)=>\(1-\dfrac{4}{47}< 1-\dfrac{4}{57}\)
=>\(\dfrac{43}{47}< \dfrac{53}{57}\)
b) Ta chọn phân số trung gian là: \(\dfrac{64}{81}\)
Vì \(\dfrac{64}{81}>\dfrac{64}{85}\)
Mà \(\dfrac{64}{81}< \dfrac{73}{81}\)
=> \(\dfrac{64}{85}< \dfrac{64}{81}< \dfrac{73}{81}\)
Vậy \(\dfrac{64}{85}< \dfrac{73}{81}\)
c) Ta chọn phân số trung gian là: \(\dfrac{18}{37}\)
Vì \(\dfrac{18}{37}>\dfrac{15}{37}\)
Mà \(\dfrac{18}{37}< \dfrac{18}{31}\)
=> \(\dfrac{15}{37}< \dfrac{18}{37}< \dfrac{18}{31}\)
Vậy \(\dfrac{18}{31}>\dfrac{15}{37}\)
=43.37+93.43+57.61+69.57
=43.(37+93)+57.(61+69)
=43.130+77.130
=130.(43+57)
=13000
a,12345679x45=12345679x9x5=111111111x5=555555555
b,43 x 37+93 x 43+57 x 61+69 x 57
=43x(37+93)+57(61+69)
=43 x 130+57 x 130
=130 x(43+57)
=130 x 100
=13000
2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40
= 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40
= 54.53+54.87-54.40
=54(53+87-40)
=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25
= 25 . ( 12+29+59)
=25 . 90
=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57
= 43.(37+93)+57(61+69)
=43.130+57.130
=130.(43+57)
=130.100
=13 000
12 . 53 + 53 . 172 - 53
=53(12+172-1)
=53.184
=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45
=35(54+58)+65(75+45)
=35.112+65.120
=3920+7800
=11720
39 . 8 + 70 . 3 + 31 . 8
=8(39+31)+70.3
=8.70+70.3
=70.(8+3)
=70.11
=770
43.37+43.73+57.66+57.44
=43.(37+73)+57.(66+44)
=43.110+57.110
=110.(43+57)
=110.100
=11000