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a) 14,7 + (-8,4) + (-4,7) = (14,7 - 4,7) + (-8,4)
= 10 - 8,4 = 1,6
b) (-4,2).5,1 + 5,1.(-5,8) = 5,1. (- 4,2 - 5,8)
= 5,1. (-10) = -51
c) (-0,4: 0,04 + 10) . (1,2.20 + 12.8)
= (-10 + 10). (1,2.20 + 12.8)
= 0. (1,2.20 + 12.8) = 0.
\(\frac{-1}{2}+\frac{5}{6}-3,12+5,1\)
= \(\frac{1}{3}-\frac{78}{25}+\frac{51}{10}\)
= \(\frac{-209}{75}\)+ 51/10
= 347/150
\(y+70y+70\%y=-5,1\)
\(\Leftrightarrow y\left(1+70+70\%\right)=-5,1\)
\(\Leftrightarrow y\left(1+70+\frac{70}{100}\right)=-5,1\)
\(\Leftrightarrow y\left(71+\frac{70}{100}\right)=-5,1\)
\(\Leftrightarrow y\left(\frac{710}{10}+\frac{7}{10}\right)=-5,1\)
\(\Leftrightarrow\frac{717}{10}x=-5,1\)
\(\Leftrightarrow x=-5,1\div\frac{717}{10}\)
\(\Leftrightarrow x=-5,1\times\frac{10}{717}\)
\(\Leftrightarrow x=\frac{-51}{717}\)
\(\dfrac{2}{3}\)cua 8,7 la :\(\dfrac{87}{10}\)\(\div\)\(\dfrac{2}{3}\)\(=\)\(\dfrac{261}{20}\)
\(2\dfrac{1}{3}\)của 5,1 là :\(\dfrac{7}{3}\)\(\div\)\(\dfrac{51}{10}\)=\(\dfrac{70}{153}\)
\(\dfrac{2}{7}\)cua \(\dfrac{-11}{6}\)la :\(\dfrac{-11}{6}\)\(\div\)\(\dfrac{2}{7}\)=\(\dfrac{-77}{12}\)
\(2\dfrac{7}{11}\)cua \(6\dfrac{5}{3}\)la : \(\dfrac{23}{3}\)\(\div\)\(\dfrac{29}{11}\)=\(\dfrac{253}{87}\)
a,\(\left(5,1-3,5\right)-\left(3,5+5,1\right)\)
\(=5,1-3,5-3,5-5,1\)
\(=\left[5,1-5,1\right]\)\(-\)\(\left[3,5-3,5\right]\)
\(=0-0\)
\(=0\)
b,c bn tự làm nha
5,1. [(-4,2)+ (-5,8)]
=5,1. (-10)
= -51
`(-4,2) . 5,1 + 5,1 . (-5,8)`
`= 5,1 . [-4,2 + (-5,8)]`
`= 5,1 . (-10)`
`= -51`