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Bài 1 :tính nhanh và nhớ là áp dụng quy tắc dấu ngoặc và quy tắc đổi dấu
a,(—273+411)—(727—589)+210
b,(117—213)—(217+478)—160
Bài 2 tìm x
a,(47—5x)—(62—4x)=15
b,(2x+1)3=27
Giúp mk na
Toán lớp 6
LÀm lun nha
a,=-273+411-727+589+210
=-273-727+411+589+210
=-1000+1000+210
=210
b,Hay cậu tính bình thường,mình không nghĩ ra cách làm nhanh
=117-213-217-478-160
=-951
Bài 2
47-5x-62+4x=15
47-62-(5x-4x)=15
-15-x=15
x=-15-15
=-30
Ta có:27=9x9x9=9^3
=>2x+1=9
2x=9-1
2x=8
x=8:2
x=4
a)210-5x=200
5x=210-200
5x=10
x=10:2
x=5
B)210-5(x-10)=200
5(x-10)=210-200
5(x-10)=10
x-10=10:5=2
x=2+10=12
c)450:[41-(2x-5)]=3 mũ 2 .5
450:[41+5-2x]=45
41+5-2x=450:45
41+5-2x=10
2x=36
x=18
D)210:x-10=20
210:x=20+10
210:x=30
x=210:30
x=7
E)(5x-39).7+3=80
(5x-39).7=77
5x-39=11
5x=50
x=10
F(2x+1):7=2 mũ 2 nhân 3 mũ 2
(2x+1):7=36
2x+1=252
2x=251
x=251/2
a)C=2^1+2^2+2^3+....+2^99+2^100
=>(2^1+2^2)+(2^3+2^4)+...+(2^99+2^100)
=>2.(1+2)+2^3.(1+2)+...+2^99+(1+2)
=>2.3+2^3.3+...+2^99+3
Vì 3 chia hết cho 3
=>C chia hết cho 3
b)D=7^1+7^2+7^3+....+7^210
=>(7^1+7^2)+(7^3+7^4)+...+(7^209+7^210)
=>7.91+7)+7^3+(1+7)+...+7^209(1+7)
=>7.8+7^3.8+...+7^209+8
Vì 8 chia hết cho 8
=>D chia hết cho 8
Tick cho tớ nha
\(a,210-5\left(x-11\right)=200\\ \Rightarrow5\left(x-11\right)=10\\ \Rightarrow x-11=2\\ \Rightarrow x=13.\\ b,\left(2x+1\right):7=2^2+3^2\\ \Rightarrow\left(2x+1\right):7=4+9\\ \Rightarrow\left(2x+1\right):7=13\\ \Rightarrow2x+1=91\\ \Rightarrow2x=90\\ \Rightarrow x=45.\\ c,450:\left[41-\left(2x-5\right)\right]=3^2.5\\ \Rightarrow450:\left[41-\left(2x-5\right)\right]=45\\ \Rightarrow41-\left(2x-5\right)=10\\ \Rightarrow2x-5=31\\ \Rightarrow2x=36\\ \Rightarrow x=18.\\ d,\left(5x-9\right).7+3=80\\ \Rightarrow\left(5x-9\right).7=77\\ \Rightarrow5x-9=11\\ \Rightarrow5x=20\\ \Rightarrow x=4.\)
a) \(210-5\left(x-11\right)=200\)
\(5.\left(x-11\right)=210-200\)
\(5.\left(x-11\right)=10\)
\(x-11=10:5\)
\(x-11=2\)
\(x=2+11\)
\(x=13\)
b) \(\left(2x+1\right):7=2^2+3^2\)
\(\left(2x+1\right):7=13\)
\(2x+1=13.7\)
\(2x=91-1\)
\(2x=90\)
\(x=90:2\)
\(x=45\)
c) \(450:\left[41-\left(2x-5\right)\right]=3^2.5\)
\(450:\left[41-\left(2x-5\right)\right]=45\)
\(\left[41-\left(2x-5\right)\right]=450:45\)
\(\left[41-\left(2x-5\right)\right]=10\)
\(2x-5=41-10\)
\(2x-5=31\)
\(2x=31+5\)
\(2x=36\)
\(x=36:2\)
\(x=18\)
d) \(\left(5x-9\right).7+3=80\)
\(\left(5x-9\right).7=80-3\)
\(5x-9=77:7\)
\(5x-9=11\)
\(5x=11+9\)
\(5x=20\)
\(x=20:5\)
\(x=4\)
Bài 1:
\(-1000\rightarrow-100\rightarrow-43\rightarrow-15\rightarrow0\rightarrow105\rightarrow1000\)
Bài 1:
a) 210 + [46 + (-210)+(-26)]
= 210 + 46 - 210 - 26
= (210 - 210) + (46 - 26)
= 0 + 20
= 20
b) (-8) - [ (-5) + 8]
= (-8) + 5 - 8
= -3 - 8
= -11
c) 25. 134 + 25. (-34)
= 25. (-34 + 134)
= 25. 100
= 2500
Bài 2:
a) x + (-35) = 18
x = 18 + 35
x = 53
Vậy x = 53
b) -2x - (-17) = 15
17 - 15 = 2x
2 = 2x
x = 2 : 2
x = 1
Vậy x = 1
Bài 5:
a. (b - 2) = 3 = 1. 3 = (-1). (-3)
Vì \(a;b\inℤ\)nên ta có bảng sau:
a | 1 | 3 | -1 | -3 |
b - 2 | 3 | 1 | -3 | -1 |
b | 5 | 3 | -1 | 1 |
Vậy \(\left(a;b\right)\in\left\{\left(1;5\right),\left\{3;3\right\},\left\{-1;-1\right\},\left\{-3;-1\right\}\right\}\)
Chúc bạn học tốt!!!
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
2/3 x 5 + 2/5 x 7 + 2/7 x 9 + ..... + 2/41 x 43
= 2/3 - 2/5 + 2/5 - 2/7 + 2/7 - 2/9 + ... + 2/41 - 2/43
= 2/3 - 2/43
= 80/129
411 + [3.(7 - 2)2 – 43].210 → 411+[3.5.2-43].210 → 411+[30-43].210→ 411+-13.210 → 411+-2730=-2319