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1) 2,75 - 5/6 × 2/5 = 2,75 - (5/6) × (2/5) = 2,75 - 1/3 = 2,75 - 0,33 = 2,42
2) 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 3/4) - 3/5 = 1,25 - (5/6 - 9/12) - 3/5 = 1,25 - (10/12 - 9/12) - 3/5 = 1,25 - 1/12 - 3/5 = 1,25 - 0,08 - 0,6 = 1,25 - 0,68 = 0,57
3) 4/9 × 0,75 + 8/5 + 3,125 = (4/9) × 0,75 + 8/5 + 3,125 = 0,44 + 8/5 + 3,125 = 0,44 + 1,6 + 3,125 = 0,44 + 4,725 = 5,165
4) 1,125 - 4/7 - 0,12 = 1,125 - (4/7) - 0,12 = 1,125 - 0,57 - 0,12 = 0,435 - 0,12 = 0,315
5) (1/3 + 0,4) × 3,5 + (1/6 + 0,75) × 6/5
= 0,75 x 0,25 + 0,75 x 1,25 - 0,75 x 0,5
= 0,75 x ( 0,25 + 1,25 - 0,5 )
= 0,75 x 1
= 0,75
=3/4.0,25+3/4.1,25-3/4.0,5
=3/4.(0,25+1,25-0,5)
=3/4.10
=15/2
a) \(0,75\times26+49\times\frac{3}{4}+\frac{3}{4}\times24+\) \(0,75\)
\(=\) \(0,75\times\left(26+1\right)+\frac{3}{4}\times\left(49+24\right)\)
\(=\) \(\frac{3}{4}\times27+\frac{3}{4}\times73\)
\(=\) \(\frac{3}{4}\times\left(27+73\right)\)
\(=\)\(\frac{3}{4}\times100=75\)
b) câu b,c làm tương tự
a, \(=16,24\left(12-3+1\right)\)
\(=16,24.10=162,4\)
b, \(=1,25\left(1+2+7\right)\)
\(=1,25.10=12,5\)
c, \(=2,46\left(2+8\right)\)
\(=2,46.10=24,6\)
\(a,=16,24\times12-16,24\times3+16,24\times1\\ =16,24\times\left(12-3+1\right)=16,24\times10=162,4\\ b,=1,25\times\left(1+2+7\right)=1,25\times10=12,5\)
\(a)\frac{9}{4}\times y=\left[\frac{5}{7}-\frac{3}{14}\right]\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\left[\frac{10}{14}-\frac{3}{14}\right]\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\frac{1}{2}\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\frac{2}{7}\)
\(\Rightarrow y=\frac{2}{7}:\frac{9}{4}=\frac{8}{63}\)
b, Tương tự câu a
1/2.x-2/3+0,75=1,25.2/3
1/2.x-2/3+3/4=5/4.2/3
1/2.x-2/3+3/4=5/6
1/2.x-2/3=5/6-3/4
1/2.x-2/3=1/12
1/2.x=1/12+2/3
1/2.x=3/4
x=3/4:1/2
x=6/4
x=1,5
Thay X \(=1,25\) vào biểu thức \(\dfrac{4}{7}\) x \(X+\dfrac{3}{7}-0,75\) x X ta có:
\(\dfrac{4}{7}\) x \(1,25+\dfrac{3}{7}-0,75\) x \(1,25\)
\(=\dfrac{5}{7}+\dfrac{3}{7}-\dfrac{15}{16}\)
\(=\dfrac{80}{112}+\dfrac{48}{112}-\dfrac{105}{112}\)
\(=\dfrac{80+48-105}{112}=\dfrac{23}{112}\)
Vậy X\(=1,25\) giá trị biểu thức \(\dfrac{4}{7}\) x \(X+\dfrac{3}{7}-0,75\) x X là: \(\dfrac{23}{112}\)