
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


3x-1 + 5 . 3x-1 = 486
3x-1 . ( 5 + 1 ) = 486
3x-1 . 6 = 486
3x-1 = 486 : 6
3x-1 = 81
3x-1 = 34
=> x - 1 = 4
x = 4 + 1
x = 5
Vậy x = 5
3x-1 + 5.3x-1 = 486
1.3x-1 + 5.3x-1 = 486
=> 3x-1.( 1 + 5) = 486
3x-1. 6 = 486
3x - 1 = 486 : 6
3 x - 1 = 81
3 x - 1 = 34
=> x - 1 = 4
x = 4 + 1
x = 5
NHỚ **** NHÉ !!!!!!!!!!!!!!!!!!!!!!!!

\(3^{x-1}+5.3^{x-1}=486\)
\(\Rightarrow3^{x-1}.\left(5+1\right)=486\)
\(3^{x-1}.6=486\)
\(3^{x-1}=81\)
\(3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
<=> 3x-1 +5.3x-1 =486
<=> 3x-1 . (1+5) = 486
<=> 3x-1 . 6 =486
<=> 3x-1 = 486 :6
<=> 3x-1 = 81
<=> 3x-1 = 34
<=> X-1=4
<=> X = 4+1
<=> X=5

\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)

Bài 2:
a: 15;20;35 đều chia hết cho x
x lớn nhất
Do đó: x=ƯCLN(15;20;35)=5
b: =>x=ƯCLN(12;54)=6
c: x chia hết cho 10 và 15
nên \(x\in B\left(30\right)\)
mà x<100
nên \(x\in\left\{30;60;90\right\}\)
d: x chia hếtcho 12 và 18
mà x<250
nên \(x\in\left\{36;72;108;144;180;216\right\}\)

\(3^x+3^{x+1}+3^{x+2}=3900\)
\(3^x+3^x.3+3^x.9=3900\)
\(3^x\left(1+3+9\right)=3900\)
\(3^x.13=3900\)
\(3^x=3900:13\)
\(3^x=300\)


1/
$xy=18=1.18=2.9=3.6=6.3=9.2=18.1$
Do $x,y$ là số tự nhiên nên $(x,y)=(1,18), (2,9), (3,6), (6,3), (9,2), (18,1)$

Bg
c) 9 < 3x : 3 < 81
=> 32 < 3x - 1 < 34
=> x - 1 = {2; 3; 4}
=> x = {3; 4; 5}
d) 5x . 5x + 1 . 5 x + 2 < 218 . 518 : 218
=> 5x + x + 1 + x + 2 < 218 : 218 . 518
=> 53x + 3 < 1.518
=> 53.(x + 1) < 518
=> 3.(x + 1) < 18
=> x + 1 < 18 : 3
=> x + 1 < 6
=> x < 6 - 1
=> x < 5
c. \(9\le3^x:3\le81\)
\(\Rightarrow3^2\le3^{x-1}\le3^4\)
\(\Rightarrow3^{x-1}\in\left\{3^2;3^3;3^4\right\}\)
\(\Rightarrow x-1\in\left\{2;3;4\right\}\)
\(\Rightarrow x\in\left\{3;4;5\right\}\)
d. Thêm đk : x thuộc N
\(5^x.5^{x+1}.5^{x+2}\le2^{18}.5^{18}:2^{18}\)
\(\Rightarrow5^{x+x+1+x+2}\le5^{18}\)
\(\Rightarrow x+x+x+1+2\le18\)
\(\Rightarrow3x+3\le18\)
\(\Rightarrow3\left(x+1\right)\le18\)
\(\Rightarrow x+1\le6\)
\(\Rightarrow x\le5\)
\(\Rightarrow x\in\left\{1;2;3;4;5\right\}\)

Mình xin giải như sau:
a)15x-57=3^14:3^9
15.x-57=3^5
15.x-57=243
15.x=243+57
15.x=300
x=300:15
x=20
b)50-[70:(x-1)]=15
70:(x-1)=50-15
70:(x-1)=35
x-1=70:35
x-1=2
x=2+1
x=3
c) (5^2+2^3).x+4^2=7^2
(25+8).x+16=49
33.x=49-16
33.x=33
x=33:33
x=1
d) 2^x:2^5=1
2^x=1.2^5
2^x=2^5
Suy ra x=5
18-(x-2)^5=2.3^2
18-(x-2)^5=2.9
18-(x-2)^5=18
(x-2)^5=18-18
(x-2)^5=0
x=0+2
x=2
\(3^x\cdot3^{x+1}\cdot18=486\)
\(\Leftrightarrow2x+1=3\)
hay x=1
\(3^x.3^{x+1}.18=486\)
\(3^x.3^{x+1}=27\)
\(3^{2x+1}=27\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow x=1\)