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3x+3x+1+3x+2=1053
=>3x+3x.31+3x.32=1053
=>3x.(1+3+9)=1053
=>3x.13=1053
=>3x=1053:13=81
=>3x=34=>x=4
Vậy x=4
\(a,3^{x-1}+3^x+3^{x+1}=1053\\ \Leftrightarrow3^x.\dfrac{1}{3}+3^x+3^x.3=1053\\ \Leftrightarrow3^x\left(\dfrac{1}{3}+1+3\right)=1053\\ \Leftrightarrow\dfrac{3^x.13}{3}=1053\\ \Leftrightarrow3^x=243\\ \Leftrightarrow3^x=3^5\\ \Leftrightarrow x=5\)
\(b,\left(x+3\right)^5=\left(x+3\right)^7\\ \Leftrightarrow\left(x+3\right)^7-\left(x+3\right)^5=0\\ \Leftrightarrow\left(x+3\right)^5\left(\left(x+3\right)^2-1\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}\left(x+3\right)^5=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+3-0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-3\\x+3=\pm1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-3\\x\in\left\{-4;-2\right\}\end{matrix}\right.\)
a) (2x+1)^3=9 .81=729
=> (2x+1)=9
=> 2x=8=>x=4
b).........?
c) x=5 hoặc 6
d) .....?
a: =>(3/2-2x):2/3=1/6
=>3/2-2x=1/6x2/3=2/18=1/9
=>2x=25/18
hay x=25/36
b: \(\Leftrightarrow2x-2x+\dfrac{5}{2}-2=x-\dfrac{1}{4}\)
=>x-1/4=1/2
=>x=3/4
c: \(\Leftrightarrow2x-\dfrac{2}{3}-\dfrac{1}{3}x+\dfrac{1}{4}x=0\)
=>23/12x=2/3
=>x=8/23
1) \(\left|x+\frac{4}{5}\right|+\frac{7}{5}=\frac{3}{5}\)
\(\Rightarrow\left|x+\frac{4}{5}\right|=\frac{3}{5}-\frac{7}{5}\)
\(\Rightarrow\left|x+\frac{4}{5}\right|=\frac{-4}{5}\)
\(x+\frac{4}{5}=\pm\frac{4}{5}\)
\(TH1:x+\frac{4}{5}=\frac{4}{5}\)
\(\Rightarrow x=\frac{4}{5}-\frac{4}{5}=0\)
\(TH2:x+\frac{4}{5}=\frac{-4}{5}\)
\(\Rightarrow x=\frac{-4}{5}-\frac{4}{5}=\frac{-8}{5}\)
Vậy x ∈ {0; \(\frac{-8}{5}\)}
Nguyễn Trà My
Phần a)
\(3\times\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(32-3x+13=76-x\)
\(116-3x=76-x\)
\(116-76=3x-x\)
\(46=2x\)
\(x=46\div2\)
\(x=13\)