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1/ 3(x - 2) = 9 => x - 2 = 3 => x = 5
2/ 3(x - 36) = 216 => x - 36 = 72 => x = 108
3/ (x - 3)3 = 33 => x - 3 = 3 => x = 6
4/ 2x = 32 => 2x = 25 => x = 5
5/ 3x - 16 = 2.74 : 73 = 14 => 3x = 30 => x = 10
6/ (6x - 39) : 3 = 201 => 6x - 39 = 603 => 6x = 642 => x = 107
7/ (3x - 15)2 = 81 => (3x - 15)2 = 92 => 3x - 15 = 9 => 3x = 24 => x = 8
8/ 3(x + 4) = 105 => x + 4 = 35 => x = 31
9/ 12x - 43 = 4.84 : 83 = 32 => 12x = 32 : 64 => 12x = 1/2 => x = 1/24
10/ 41 - (2x - 5) = 680 => 2x - 5 = -639 => 2x = -634 => x = - 317
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\(a)2x^2-98=0\)
\(2x^2=0+98\)
\(2x^2=98\)
\(x^2=98:2\)
\(x^2=49\)
\(\rightarrow x^2=7^2\)
\(\rightarrow x=7\)
Vậy x = 7
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a) \(\frac{3x}{-4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-3}{2}\)
=> \(\frac{-3x}{4}=\frac{-6}{4}\)
=> \(-3x=-6\)
=> \(x=\left(-6\right):\left(-3\right)=2\)
b) \(\frac{2}{x}=\frac{y}{10}=\frac{4}{-5}\)
=> \(\frac{2}{x}=\frac{y}{10}=\frac{-4}{5}\)
+) \(\frac{2}{x}=\frac{-4}{5}\)
=> \(\left(-4\right)\cdot x=2\cdot5\)
=> \(\left(-4\right)\cdot x=10\)
=> \(x=\frac{10}{-4}=\frac{-10}{4}=\frac{-5}{2}\)
+) \(\frac{y}{10}=\frac{-4}{5}\)
=> \(5\cdot y=-40\)
=> \(y=\left(-40\right):5=-8\)
Vậy \(x=-\frac{5}{2},y=-8\)
c) \(\frac{7}{-x}=\frac{5}{y}=\frac{2}{34}\)
=> \(\frac{-7}{x}=\frac{5}{y}=\frac{1}{17}\)
+) \(\frac{-7}{x}=\frac{1}{17}\Rightarrow x=\left(-7\right)\cdot17=-119\)
+) \(\frac{5}{y}=\frac{1}{17}\Rightarrow y=5\cdot17=85\)
Vậy \(x=-119,y=85\)
d) \(\frac{x^2}{4}=16\)
=> \(x^2=16\cdot4=64\)
=> \(x\in\left\{8;-8\right\}\)
e) \(\frac{3}{x^3}=\frac{4}{-36}\)
=> \(\frac{3}{x^3}=\frac{1}{-9}=\frac{-1}{9}\)
=> \(x^3=3:\left(-\frac{1}{9}\right)=-27\)
=> \(x=-3\)
Vậy x = -3
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\(a,1⋮\left(x+7\right)\)
\(\Rightarrow x+7\inƯ\left(1\right)=\left\{\pm1\right\}\)
Ta lập bảng xét giá trị
x+7 | 1 | -1 |
x | -6 | -8 |
\(b,4⋮x-5\)
\(x-5\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
Ta lập bảng xét giá trị
x-5 | 1 | -1 | 2 | -2 | 4 | -4 |
x | 6 | -4 | 7 | 3 | 9 | 1 |
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a) -152 - (3x + 1) = (-2).(-3)3
-152 - 3x - 1 = (-2).(-27)
-3x - 153 = 54
-3x = 54 + 153
-3x = 207
x = -69
b) x - 43 = (35 - x) - 48
x - 43 = 35 - x - 48
x - 43= -x - 13
x = -x - 13 + 43
x = 30 + x
x + x = 30
2x = 30
x = 15
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1.(3x-1/4)^2=36
(3x-1/4)^2=6^2
3x-1/4 =6
3x =6+1/4
3x = 25/4
x =25/4:3
x =25/12
2.(1/4-2x)^3=8
(1/4-2x)^3=2^3
1/4-2x =2
2x =1/4-2
2x =-7/4
x =-7/8
3.(5-7/2x)^2=25
(5-7/2x)^2=5^2
5-7/2x =5
7/2x =0
x =0
4.x+(1/4)^2=25
x+1/16 =25
x =25-1/16
x =399/16
7.(2/5x-3/4)^2=1/9
(2/5x-3/4)^2=(1/3)^2
2/5x-3/4 =1/3
2/5x =1/3+3/4
2/5x =13/12
x =13/12:2/5
x =65/24
8.(3/7-x)^2=1/49
(3/7-x)^2=(1/7)^2
3/7-x =1/7
x =3/7-1/7
x =2/7
9.(2/3x+1/4)^3=125
(2/3x+1/4)^3=5^3
2/3x+1/4 =5
2/3x =5-1/4
2/3x =19/4
x =19/4:2/3
x =57/8
10.(-3/4x+1/4)^2=25/16
(-3/4x+1/4)^2=(5/4)^2
-3/4x+1/4 =5/4
-3/4x =5/4-1/4
-3/4x =1
x =1:-3/4
x =-4/3
11.2.(x+1/4)^2=1/4
2x^2+1/8 =1/4
2x^2 =1/4-1/8
2x^2 =1/8
x^2 =1/8:2
x^2 =1/16
x =1/4
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Ta có " (x - 5)7 = (x - 5)4
=> (x - 5)7 - (x - 5)4 = 0
<=> (x - 5)4[(x - 5)3 - 1] = 0
\(\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^3-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^3=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}\)
X bằng 1
=>3x+1=4
hay x=1