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2/3 x 4/5 + 4/5 x 8/3 = 4/5 x (2/3 + 8/3) = 4/5 x 10/3 = 8/3
27/32 x 16/9 -27/32 x7/9 + 27/32
= 27/32 x (16/9 - 7/9 + 1 )
=27/32 x 2
=27/16
\(\frac{2}{3}\) x \(\frac{4}{5}\) + \(\frac{4}{5}\) x \(\frac{8}{3}\)
=\(\frac{4}{5}\) x ( \(\frac{2}{3}\) + \(\frac{8}{3}\) )
= \(\frac{4}{5}\) x \(\frac{10}{3}\)
= \(\frac{40}{15}\) = \(\frac{8}{5}\)
a)\(4\frac{2}{5}+5\frac{2}{3}+2\frac{3}{4}+\frac{3}{5}+\frac{4}{12}+\frac{1}{4}\)
\(=\left(4\frac{2}{5}+\frac{3}{5}\right)+\left(5\frac{2}{3}+\frac{4}{12}\right)+\left(2\frac{3}{4}+\frac{1}{4}\right)\)
\(=5+6+3=14\)
b)\(\frac{41}{27}\cdot\frac{13}{18}-\frac{13}{18}\cdot\frac{14}{27}\)
\(=\frac{13}{18}\cdot\left(\frac{41}{27}-\frac{14}{27}\right)\)
\(=\frac{13}{18}\cdot1=\frac{13}{18}\)
a ) 37 x 27 + 63 x 27
= ( 37 + 63 ) x 27
= 100 x 27
= 2700
b ) 1 + 2 + 3 + 4 + ... + 97 + 98 + 99
= ( 99 - 1 ) : 1 + 1
= 99 x ( 99 + 1 ) : 2
= 4950
c ) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10
= ( 1 + 9 ) + ( 2 + 8 ) + ( 3 + 7 ) + ( 4 + 6 ) + ( 5 + 10 )
= 10 + 10 + 10 + 10 + 15
= 55
( x + 1 ) + ( x + 2 ) + ... + ( x + 98 ) + ( x + 99 ) = 9900
( x + x + ... + x + x ) + ( 1 + 2 + ... + 98 + 99 ) = 9900
99.x + \(\frac{\left(99+1\right).99}{2}\)= 9900
99.x + 4950 = 9900
99.x = 9900 - 4950
99.x = 4950
x = 4950 : 99
x = 50
2 . x + 5 . x - 3 . x = 125 : 4 + 27 : 3
x . ( 2 + 5 - 3 ) = 31,25 + 9
x . 4 = 40,25
x = 40,25 : 4
x = 10,0625
a) 3 x X x 2/3 = 4/5
3.x=6/5
x=2/5
b) 3,94 x 18,24 + 18,24 x 3,72 + 18,24 x 2,34
=18,24(3,94+3,72+2,34)
=18,24.10
=182,4
d) 8/19 x 2/7 + 8/19 x 1/7 + 8/19 x 4/7
=8/19(2/7+1/7+4/7)
=8/19.1
=8/19
\(\frac{4}{9}+\frac{5}{9}X\left(1-\frac{2}{3}\right):\frac{5}{27}\)
=\(1X\frac{1}{3}X\frac{27}{5}\)
=\(\frac{1X9X3}{3X5}\)
\(\frac{9}{5}\)
1) 5(x - 2) + 27 = 4x - 8
=> 5x - 10 + 27 = 4x - 8
=> 5x + 17 = 4x - 8
=> 5x - 4x = -8 - 17
=> x = -25
2) 3(x + 1) + 2(x + 2) = -13
=> 3x + 3 + 2x + 4 = -13
=> 5x + 7 = -13
=> 5x = -13 - 7
=> 5x = -20
=> x = -20 : 5
=> x = -4
3) (2x + 4)(5 - x) = 0
=> \(\orbr{\begin{cases}2x+4=0\\5-x=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=-4\\x=5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=5\end{cases}}\)
Vậy ...
4) x2 - 3x = 0
=> x(x - 3) = 0
=> \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy ...
5) x2 - 3x + 2 = 0
=> x(x - 3) = -2
=> x(x - 3) = 1 . (1 - 3)
=> x = 1
\(\frac{27}{x}=\frac{9}{50}\)
\(\Rightarrow27\times50=9\times x\)
\(\Rightarrow1350=9\times x\)
\(\Rightarrow x=1350:9=150\)
~ Hok tốt ~
\(\frac{2+3}{5+x}=\frac{5}{6}\)
\(\Rightarrow\left(5+x\right)\times5=\left(2+3\right)\times6\)
\(\Rightarrow\left(5+x\right)\times5=5\times6\)
\(\Rightarrow\left(5+x\right)\times5=30\)
\(\Rightarrow\left(5+x\right)=30:5\)
\(\Rightarrow\left(5+x\right)=6\)
\(\Rightarrow x=6-5\)
\(\Rightarrow x=1\)
\(\left(3x-5\right):4+2=27\)
\(\left(3x-5\right):4\) \(=27-2\)
\(\left(3x-5\right):4\) \(=25\)
\(\left(3x-5\right)\) \(=25\times4\)
\(\left(3x-5\right)\) \(=100\)
\(3x-5\) \(=100\)
\(3x\) \(=100+5\)
\(3x\) \(=105\)
\(x\) \(=105:3\)
\(x\) \(=35\)
Dấu chấm là nhân nha mọi người