Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{-3}{2}\times\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{5}\right):3\dfrac{2}{3}\\ =\dfrac{45}{128}+\left(-2\right)\times\dfrac{3}{11}\\ =\dfrac{45}{128}-\dfrac{6}{11}\\ =-\dfrac{273}{1408}\)
\(\left(9-x\right)^3=64\)
\(\left(9-x\right)^3=4^3\)
\(\Leftrightarrow9-x=4\)
\(x=5\)
-2011+|x|=5.16-81
-2011+|x|=80-81
-2011+|x|=-1
|x| =(-1)-(-2011)
|x| =2010
-> x=2010 hoặc x=-2010
a) \(3\left(x-5\right)+6=36\)
\(\Rightarrow3\cdot\left(x-5\right)=36-6\)
\(\Rightarrow3\cdot\left(x-5\right)=30\)
\(\Rightarrow x-5=10\)
\(\Rightarrow x=10+5\)
\(\Rightarrow x=15\)
b) \(200-8\cdot\left(x+7\right)=24\)
\(\Rightarrow8\cdot\left(x+7\right)=200-24\)
\(\Rightarrow8\cdot\left(x+7\right)=176\)
\(\Rightarrow x+7=\dfrac{176}{8}\)
\(\Rightarrow x+7=22\)
\(\Rightarrow x=22-7\)
\(\Rightarrow x=15\)
c) \(\left(x-890\right)\left(74-x\right)=0\)
+) \(x-890=0\)
\(\Rightarrow x=890\)
+) \(74-x=0\)
\(\Rightarrow x=74\)
d) \(\left(31-x\right)\cdot\left(x-64\right)=0\)
+) \(31-x=0\)
\(\Rightarrow x=31\)
+) \(x-64=0\)
\(\Rightarrow x=64\)
1.
2|x-6|+7x-2=|x-6|+7x
2|x-6| - |x-6|=7x-(7x-2)
|x-6| = 2
=>x-6 = +2
*x-6=2 *x-6 = -2
x =2+6 x = (-2)+6
x =8 x = 4
2.
|x-5|-7(x+4)=5-7x
|x-5|-7x-28 =5-7x
|x-5|-28 =5-7x+7x
|x-5|-28 = 5
|x-5| = 5+28
|x-5| = 33
=>x-5 = +33
*x-5=33 *x-5=-33
x =38 x = -28
3.
3|x+4|-2(x-1)=7-2x
3|x+4|-2x+2 =7-2x
3|x+4|-2 =7-2x+2x
3|x+4|-2 =7
3|x+4| =7+2
3|x+4| = 9
|x+4| =9:3
|x+4| = 3
=>x+4 = +3
*x+4=3 *x+4=-3
x =-1 x = -7
1, Ta có :
\(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)
\(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)
\(x+\frac{3}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{3}{5}\)
\(x=\frac{15}{10}-\frac{6}{10}\)
\(x=\frac{9}{10}\)
Vậy x = \(\frac{9}{10}\)
2, Ta có :
\(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)
\(\frac{3}{4}\div x=-\frac{5}{6}\)
\(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)
\(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)
\(x=-\frac{9}{10}\)
Vậy x = \(-\frac{9}{10}\)
\(1+3+5+......+x=2500\)
\(\Rightarrow\left[\left(x-1\right):2+1\right].\left(x+1\right):2=2500\)
\(\Rightarrow\left(\frac{x}{2}-\frac{1}{2}+1\right).\left(x+1\right)=2500.2\)
\(\Rightarrow\left(\frac{x}{2}+\frac{1}{2}\right).\left(x+1\right)=5000\)
\(\Rightarrow\frac{x^2}{2}+\frac{1}{2}x+\frac{x}{2}+\frac{3}{2}=5000\)
\(\Rightarrow\frac{x^2+x+x+3}{2}=5000\)
\(\Rightarrow x^2+2x+3=5000.2\)
\(\Rightarrow x^2+2x.1+1^2+3-1^2=10000\)
\(\Rightarrow\left(x+1\right)^2+2=10000\)
\(\Rightarrow\left(x+1\right)^2=10000-2\)
\(\Rightarrow\left(x+1\right)^2=9998\)
\(\Rightarrow x+1=\sqrt{9998}\)
\(\Rightarrow x=\sqrt{9998}-1\)
\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{5}{6}+x=x-\frac{2}{3}\)
\(\Leftrightarrow\left(x-x\right)+\frac{5}{6}=x-\frac{2}{3}\)
\(\Leftrightarrow0+\frac{5}{6}=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{2}{3}=\frac{5}{6}\)
\(\Leftrightarrow x=\frac{5}{6}+\frac{2}{3}\)
\(\Leftrightarrow x=\frac{5}{6}+\frac{4}{6}\)
\(\Leftrightarrow x=\frac{3}{2}\)