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a) x - 15 = 7 + (-2)
x-15 = 5
x=20
b) | x - 5 | = 15 + (-8)
I x - 5 I = 7
1) x-5 = 7 => x = 12
2) x-5 = -7 => x= -2
Vậy x=12 hoặc x=-2
c) I x | - 25 = 45 + (-15)
I x | - 25 = 30
I xI = 55
Vậy x= 55 hoặc x=-55
a) x - 15 = 7 + ( - 2 )
x - 15 = 5
x = 5 + 15
x = 20
b) | x - 5 | = 15 + ( - 8 )
| x - 5 | = 7
=> x = 7 + 5
x = 12
c) | x | - 25 = 45 + ( - 15 )
| x | - 25 = 30
=> | x | = 30 + 25
| x | = 55
=> x = 55
70 - 5(x - 3) = 45
-5(x - 3) = 45 - 70
-5(x - 3) = -25
x - 3 = (-25) : (-5)
x - 3 = 5
x = 5 + 3
x = 8
Trả lời:
\(70-5\times\left(x-3\right)=45\)
\(\Leftrightarrow5\times\left(x-3\right)=25\)
\(\Leftrightarrow x-3=5\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
\(5x+3\left(10-x\right)+x=45\)
\(\Leftrightarrow5x+30-3x+x=45\)
\(\Leftrightarrow3x+30=45\)
\(\Rightarrow3x=15\rightarrow x=5\)
ta có
(1/3+1/6+1/36) +(1/10+1/15+1/45)+(1/21+1/28)
=(\(\frac{12+6+1}{36}\)+\(\frac{9+6+2}{90}\)+\(\frac{4+3}{84}\)
19/36+17/90+1/12
=(19/36+1/12)+17/90
=7/12+17/90
=105/180+34/180
=139/180
1/3 +1/6+1/10+1/15+1/21+1/28+1/36+1/45
=1/1x3+1/3x2+1/2x5+1/3x5+1/3x7+1/7x4+1/4x9+1/9x5
=1/1-1/3+1/3-1/2....+1/9-1/5
=1/1
\(a,\left(x-27\right).\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-27=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0+27\\x=0+3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=27\\x=3\end{cases}}\)
\(b,70-5.\left(2x-3\right)=45\)
\(\Rightarrow5.\left(2x-3\right)=70-45\)
\(\Rightarrow5.\left(2x-3\right)=25\)
\(\Rightarrow2x-3=25\div5\)
\(\Rightarrow2x-3=5\)
\(\Rightarrow2x=5+3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=8\div2\)
\(\Rightarrow x=4\)
~Study well~
#KSJ
a)
\(\left(2x-15\right)^5=\left(2x-15\right)^3\\ \Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\\ \Leftrightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15-1\right).\left(2d-15+1\right)=0\end{matrix}\right.\\\Leftrightarrow\left[{}\begin{matrix}2x-15=0\\2x-16=0\\2x-14=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right. \)
b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\\ \Leftrightarrow\left(7x-11\right)^3=343=7^3\\ \Leftrightarrow7x-11=7\\ \Leftrightarrow x=\dfrac{18}{7}\)
\(=\dfrac{3}{7}\left(-\dfrac{15}{13}-\dfrac{11}{13}-1\right)=\dfrac{3}{7}\left(-2-1\right)=-\dfrac{9}{7}\)
3x-45:15=18
3x-3=18
3x=21
x=7
***mình nha các bạn
3.x-45:15= 18
3.x-3=18
3.x=18+3
3.x=21
x=21:3
x=7(cái này đúng nhất)